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Q:

A man sitting in a train which is traveling at 50 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.?

A) 60	B) 62
C) 64	D) 65

Answer & Explanation Answer: B) 62

Explanation:

Relative speed =280/9 m / sec = (280/9*18/5) kmph = 112 kmph.

Speed of goods train = (112 - 50) kmph = 62 kmph.

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Q:

In the following question, various terms of an alphanumerical series are given with one or more terms missing as shown by (?). Choose the missing terms out of the given alternatives. A/2, B/4, C/6, D/8, ?, ?

A) D/10, E/10	B) E/10, F/12
C) E/8, F/10	D) E/12, F/14

Answer & Explanation Answer: B) E/10, F/12

Explanation:

The letters are in alphabetical order. The numbers increase by two.

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Q:

In the following questions a letter-series is given, in which some letters are missing. The missing letters are given in the proper sequence as one of the alternatives. Choose the correct alternatives. _ nmmn _ mmnn _ mnnm _

A) mnnm	B) nmmn
C) nmnm	D) nnmm

Answer & Explanation Answer: D) nnmm

Explanation:

The series is nnmm/nnmn/nnmm/nnmm.
The pattern 'nnmm' is repeated.

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Q:

Two trains having equal lengths, take 10 seconds and 15 seconds respectively to cross a post. If the length of each train is 120 meters, in what time (in seconds) will they cross each other when traveling in opposite direction?

A) 10	B) 25
C) 12	D) 20

Answer & Explanation Answer: C) 12

Explanation:

Speed of train 1 = $(\frac{120}{10}) m / s e c$ = 12 m/sec

Speed of train 2 = $(\frac{120}{15}) m / s e c$ = 8 m/sec

if they travel in opposite direction, relative speed = 12 + 8 = 20 m/sec

distance covered = 120 + 120 = 240 m

time = distance/speed = 240/20 = 12 sec

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Q:

In the following question a letter-series is given, in which some letters are missing. The missing letters are given in the proper sequence as one of the alternatives. Choose the correct alternatives. ab __ d __ aaba __ na _ badna _ b

A) andaa	B) babda
C) dbanb	D) badna

Answer & Explanation Answer: A) andaa

Explanation:

The series is abadna/abadna/abadna/ab.
The pattern 'abadna' is repeated

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Q:

In each of the following questions a letter-series is given, in which some letters are missing. The missing letters are given in the proper sequence as one of the alternatives. Choose the correct alternatives. _ op _ mo _ n _ _ pnmop _

A) mnpmon	B) mpnmop
C) mnompn	D) mnomon

Answer & Explanation Answer: A) mnpmon

Explanation:

The pattern 'mopn' is repeated.

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Q:

A jogger is running at 9 kmph alongside a railway track is 240 meters ahead of the engine of a 120 meters long train running at 45 kmph in the same direction. In how much time will the train pass the jogger ?

A) 48 sec	B) 36 sec
C) 18 sec	D) 72 sec

Answer & Explanation Answer: B) 36 sec

Explanation:

Speed of the train relative to jogger = (45-9) km/hr = 36 km/hr =(36*5/18) m/sec = 10 m/sec

Distance to be covered =(240 + 120)m = 360 m

$\therefore$ Time taken = 360/10 sec = 36 sec

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Q:

A train is traveling at 48 kmph . It crosses another train having half of its length , traveling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. What is the length of the platform ?

A) 500	B) 400
C) 360	D) 480

Answer & Explanation Answer: B) 400

Explanation:

Speed of train 1 = 48 kmph
Let the length of train 1 = 2x meter

Speed of train 2 = 42 kmph
Length of train 2 = x meter (because it is half of train 1's length)

Distance = 2x + x = 3x
Relative speed= 48+42 = 90 kmph = (90*5/18) m/s = 25 m/s

Time = 12 s

Distance/time = speed

=>3x/12 = 25 $\Rightarrow$ (25*12)/3

Length of the first train = 2x = 200 meter
Time taken to cross the platform= 45 s

Speed of train 1 = 48 kmph = 480/36 = 40/3 m/s

Distance = 200 + y [where y is the length of the platform]

x =100m => 200+y = 45* 40/3
$\Rightarrow$ y = 400m

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