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Q:

Legend : Story : : Merlin : ?

A) Eagle B) Parakeet
C) Hawk D) crow
 
Answer & Explanation Answer: C) Hawk

Explanation:

First is a type of second.

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Filed Under: Analogy

Q:

A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:

A) 50 m B) 150 m
C) 200 m D) data inadequate
 
Answer & Explanation Answer: B) 150 m

Explanation:

Let the length of the train be x metres and its speed be y m/sec.
Then, (x/y)= 15   y =(x/15)

 

(x+100)/25 = x/15

 

=> 15(x + 100) = 25x

 

=> 15x + 1500 = 25x

 

=> 1500 = 10x

 

=> x = 150 m.

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Filed Under: Problems on Trains

Q:

Horse : Jockey :: Car : ?

A) Chauffeur B) Steering
C) Mechanic D) Brake
 
Answer & Explanation Answer: A) Chauffeur

Explanation:

A horse is driven by a jockey.

 

Similarly, a car is driven by a chauffeur.

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Filed Under: Analogy
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Q:

A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train ?

A) 69.5 km/hr B) 70 km/hr
C) 79 km/hr D) 79.2 km/hr
 
Answer & Explanation Answer: D) 79.2 km/hr

Explanation:

Let the length of the train be x metres and its speed by y m/sec.


Then, x/y = 8 => x = 8y


Now, (x+264)/20 = y
8y + 264 = 20y
y = 22.
Speed = 22 m/sec = (22*18/5) km/hr = 79.2 km/hr.

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Filed Under: Problems on Trains

Q:

A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train ?

A) 230 m B) 240 m
C) 260 m D) 320 m
 
Answer & Explanation Answer: A) 230 m

Explanation:

Relative speed = (120 + 80) km/hr


=(200*5/18)m/s = (500/9)m/s

 

Let the length of the other train be x metres.

 

Then, x+270/9 = 500/9 

 

=>  x + 270 = 500

 

=>  x = 230.

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Filed Under: Problems on Trains

Q:

0.1 decates ago, Vijaya was quadrice as old as her daughter Simran. 0.6 decades hence, Vijaya’s age will beat her daughter’s age by 0.9 decades. The proportion of the current ages of Vijaya and Simran is : [ 0.1 Decates =1 Year; quadrice = 4 times]

A) 8:1 B) 10:2
C) 11:4 D) 13:4
 
Answer & Explanation Answer: D) 13:4

Explanation:

Let, Ages of Vijaya and Simran – 1 year ago was 4A and A years correspondingly.
Then, [(4A + 1) + 6] – [(A + 1) + 6] = 9
3A = 9  => A = 3

 

Needed Ratio = (4A + 1) : (A + 1) = 13 : 4

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Filed Under: Problems on Ages

Q:

If two times of the daughter’s age in years is included to the mother’s age, the total is 70 and if two times of the mother’s age is included to the daughter’s age, the total is 95. So the Mother’s age is,

A) 30 B) 38
C) 40 D) 41
 
Answer & Explanation Answer: C) 40

Explanation:

Let daughter’s age = A and mother’s age = B
Given: 2A+B = 70 and A+2B = 95
Solving B, we will get B = 40.

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Filed Under: Problems on Ages

Q:

Eye : Myopia :: Teeth : ?

A) Cataract B) Trachoma
C) Eczema D) Pyorrhea
 
Answer & Explanation Answer: D) Pyorrhea

Explanation:

The second word is a disease of the first word.

That is here Myopia is the disease of the eyes. Similarly, Pyorrhea is the disease of the teeth.

 

Hence, Eye : Myopia :: Teeth : Pyorrhea.

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Filed Under: Analogy
Exam Prep: GRE , CAT , Bank Exams , AIEEE
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