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Q:

On a school’s Annual day sweets were to be equally distributed amongst 112 children. But on that particular day, 32 children were absent. Thus the remaining children got 6 extra sweets. How many sweets was each child originally supposed to get ?

A) 14	B) 16
C) 12	D) 15

Answer & Explanation Answer: D) 15

Explanation:

Let 'K' be the total number of sweets.
Given total number of students = 112
If sweets are distributed among 112 children,
Let number of sweets each student gets = 'L'

=> K/112 = L ....(1)
But on that day students absent = 32 => remaining = 112 - 32 = 80
Then, each student gets '6' sweets extra.

=> K/80 = L + 6 ....(2)
from (1) K = 112L substitute in (2), we get
112L = 80L + 480
32L = 480
L = 15

Therefore, 15 sweets were each student originally supposed to get.

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Q:

One paper is equally folded 35 times, then what is the new thickness of the paper ?

A) T(2^50)	B) 50T
C) 2 x 50 T	D) T/50

Answer & Explanation Answer: A) T(2^50)

Explanation:

Let initial thickness of the paper be 'T'
after first fold it will be '2T' = $2^{1} T$
after second fold it will be '4T' = $2^{2} T$
after 50th fold it will be T x ( $2^{50}$ T)

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Q:

Mr. Shankar spends 25% of his monthly salary on household expenditure, 20% of the remaining on children’s education, and the remaining is equally invested in three different schemes. If the amount invested in each scheme is Rs.5600, what is the monthly salary of Shankar ?

A) Rs. 34000	B) Rs. 31245
C) Rs. 24315	D) Rs. 28000

Answer & Explanation Answer: D) Rs. 28000

Explanation:

Let the monthly salary of Shankar be = Rs.x
Amount invested on expenditure = 25% = x/4;
Remaning amount = 3x/4;
Amount invested on children education = 20% i.e = 3x/20;
Remaining amount = 3x/4 - 3x/20 = 3x/5;
Remaining amount invested in three different schemes i.e is 1/3(3x/5)
=> x/5 = 5600
Therefore x = 28000
Hence, Monthly salary of Shankar is Rs. 28,000.

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Q:

On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is ?

A) Rs. 55	B) Rs. 60
C) Rs. 65	D) Rs. 70

Answer & Explanation Answer: B) Rs. 60

Explanation:

Let the cost price of a ball is Rs.x
Given, on selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls
The equation is :
17x - 720 = 5x
Solving the equation
we get x = 60
Therefore, cost price of a ball is Rs. 60.

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Q:

The market price of an article was 40% more than its cost price. Rana was going to sell it at market price to a customer, but he showed Rana some defects in the article, due to which Rana gave him a discount of 28.57%. Next day he came again and showed Rana some more defects, hence he gave him another discount that was equal to 12.5% of the cost price. What was the approximate profit/loss to Rana ?

A) Loss of 12.5%	B) Profit of 12.5%
C) Loss of 24.5%	D) Profit of 22.5%

Answer & Explanation Answer: A) Loss of 12.5%

Explanation:

Let the cost price be Rs. 100
Then, market price is Rs. 140
Now, the first discount is of 28.57% Rs.140 =~ Rs. 40
Hence, its selling price = 140 - 40 = Rs. 100
Now since Rana is selling at cost price, any further discount will be equal to loss percentage.
The next dicount of 12.5% will be the loss percentage to Rana.

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Q:

If the selling price of a mat is five times the discount offered and if the percentage of discount is equal to the percentage profit, find the ratio of the discount offered to the cost price.

A) 6:31	B) 11:30
C) 7:30	D) 31:6

Answer & Explanation Answer: C) 7:30

Explanation:

Since S.P. = 5 (M.P. - S.P.) => 5 M.P. = 6 S.P.
M.P. = (6/5) S.P.
Since the percentage discount = Percentage profit,
$\frac{\frac{6}{5} S . P - S . P}{\frac{6}{5} S . P} \times 100 = \frac{S . P - C . P}{C . P} \times 100$
Therefore, 1/6 = (S.P/C.P) – 1 => S.P = (7/6) C.P
M.P = 6/5 S.P = 6/5 x 7/6 C.P = 7/5 C.P
Therefore, Ratio of discount to C.P
= (M.P – S.P)/C.P = [{(7/5)C.P - (7/6)C.P} / C.P.]
= 7/30

Therefore, the ratio is 7 : 30

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Q:

A cuboid shaped wooden block has 6 cm length, 4 cm breadth and 1 cm height.
Two faces measuring 4 cm x 1 cm are coloured in black.
Two faces measuring 6 cm x 1 cm are coloured in red.
Two faces measuring 6 cm x 4 cm are coloured in green.
The block is divided into 6 equal cubes of side 1 cm (from 6 cm side), 4 equal cubes of side 1 cm(from 4 cm side).

How many cubes will have green colour on two sides and rest of the four sides having no colour ?

A) 8	B) 24
C) 16	D) 4

Answer & Explanation Answer: A) 8

Explanation:

kar1486102114.png image

There are 16 small cubes attached to the outer walls of the cuboid.
Therefore remaining inner small cubes will be the cubes having two sides green coloured.
So the required number = 24 - 16 = 8

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Q:

If $\log_{7} (2)$ = m, then $\log_{49} (28)$ is equal to ?

A) 1/(1+2m)	B) (1+2m)/2
C) 2m/(2m+1)	D) (2m+1)/2m

Answer & Explanation Answer: B) (1+2m)/2

Explanation:

$\log_{49} (28) = \frac{1}{2 \log_{7} (7 \times 4)}$

= $\frac{1}{2} + \frac{1}{2} (2 \log_{7} (2))$
= $\frac{1}{2} + \log_{7} (2)$
= $\frac{1}{2} + m$
= $\frac{1 + 2 m}{2}$ .

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