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Q:

Find the ODD number ?

odd1502270940.jpg image

A) 42 B) 142
C) 119 D) 21
 
Answer & Explanation Answer: B) 142

Explanation:

Except 142 all are divisible by number '7'.

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Filed Under: Math Puzzles
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Q:

If NAMO = 172 and OM = 56  then, SHIVAY = ?

A) 606 B) 415
C) 504 D) 404
 
Answer & Explanation Answer: C) 504

Explanation:

(COUNTING OF LETTERS)
NAMO = 14 + 1 + 13 + 15 = 43 x 4 = 172,  OM = 15 + 13 = 28 x 2 = 56,

SHIVAY = 19 + 8 + 9 + 22 + 1 + 25 = 84 x 6 = 504

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Filed Under: Alphabet Test
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Q:

'P' walked 1 km towards south direction and turned  90oACW and walked 2 km. Then he turned his left and walked 1 km and then he turned his right and walked 2 km. After that he turned 90o ACW and walked 3 km. How far is he from the starting point ?

A) 5 km B) 4 km
C) 2 km D) 0 km
 
Answer & Explanation Answer: A) 5 km

Explanation:
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Filed Under: Direction Sense Test
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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Q:

Solve the Missing Number Puzzle ?

missing_number1501485405.jpg image

Answer

The rule followed here is


7 + 3 - 4 = 6


Similarly,


4 + 2 - 2 = 4


9 + 5 - 4 = 10


Hence, the missing numbers are 4 & 10.

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Subject: Number Puzzles Exam Prep: GATE , CAT , Bank Exams , AIEEE
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Q:

Crack the Relation Logical Puzzle ?

20108561_1367416623365438_8515941278875417415_n1501053222.jpg image

A) Son B) Himself
C) Father D) Uncle
 
Answer & Explanation Answer: C) Father

Explanation:

Man's Father is Madhu's Father's Son => Madhu itself. So the Man in the photograph is Madhu's son. 

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Filed Under: Logic Puzzles
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Q:

In the following pieces of code, B and D will compile without any error. True or false ?

A: StringBuffer sb1 = "abcd";

B: Boolean b = new Boolean("abcd");

C: byte b = 255;

D: int x = 0x1234;

E: float fl = 1.2;

A) TRUE B) FALSE
Answer & Explanation Answer: A) TRUE

Explanation:

The code segments B and D will compile without any error. A is not a valid way to construct a StringBuffer, you need to create a StringBuffer object using "new". B is a valid construction of a Boolean (any string other than "true" or "false" to the Boolean constructor will result in a Boolean with a value of "false"). C will fail to compile because the valid range for a byte is -128 to +127 (i.e., 8 bits, signed). D is correct, 0x1234 is the hexadecimal representation in java. E fails to compile because the compiler interprets 1.2 as a double being assigned to a float (down-casting), which is not valid. You either need an explicit cast, as in "(float)1.2" or "1.2f", to indicate a float.

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Q:

What is the output after compile and run the following code ?

int Output = 10;
boolean b = false;
if((b == true) && ((Output += 10) == 20))
{
System.out.println("We are equal " + Output);
}
else
{
System.out.println("Not equal! " + Output);
}

A) Compilation and output of "We are equal 10" B) Compilation and output of "Not equal! 10"
C) Compilation error, attempting to perform binary comparison on logical data type D) Compilation and output of "Not equal! 20"
 
Answer & Explanation Answer: B) Compilation and output of "Not equal! 10"

Explanation:

The output will be "Not equal! 10". Please note that && is logical AND operator. If first operand before (&&) is false then the other operand will not be evaluated. This illustrates that the Output +=10 calculation was never performed because processing stopped after the first operand was evaluated to be false. If you change the value of b1 to true, processing occurs as you would expect and the output would be "We are equal 20".

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Filed Under: Oracle Certification
Job Role: Analyst

Q:

Can you Solve the Problem ?

SOLVE1500443612.jpg image

Answer

Let the two digits be x & y


From given data in the question, we get


x + y = 3(x - y)


x + y = 3x - 3y


=> 2x = 4y


x/y = 2/1


For having the 2:1, numbers satisfying are


12, 21, 24, 42, 36, 63, 48, 84


From this 36 is eleminated because it is a perfect square and no others are prime or perfect squares.


Hence, there exists 7 such 2-digit numbers => 12, 21, 24, 42, 63, 48, 84.

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Subject: Math Puzzles Exam Prep: AIEEE , Bank Exams , CAT , GATE
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