Chennai port is known for its Coastal breakwater, artificial, large seaport type of harbor.

Chennai Port, formerly known as Madras Port, is the second largest container port of India, behind the Nhava Sheva Port, and the largest port in the Bay of Bengal. It is the third oldest port among the 13 major ports of India

Let Rs. K invested in each scheme

Two years C.I on 20% = 20 + 20 + 20x20/100 = 44%

Two years C.I on 15% = 15 + 15 + 15x15/100 = 32.25%

Now,

(P x 44/100) - (P x 32.25/100) = 528.75

=> 11.75 P = 52875

=> P = Rs. 4500

Hence, total invested money = P + P = 4500 + 4500 = Rs. 9000.

Let the time taken by train be 't' hrs.

Then,

40t = 35t + 1560

40t = 35t + 35/4

t = 7/4 hrs

Therefore, Required length of the total journey d = s x t

= 40 x 7/4

= 70 kms.

Answer 1)  

1/3 x (54 x 150 + 60 x 300 + 36 x 450)

= 1/3 x 42300

= 14100.

Answer 2)

Required ratio of chairs = 64 x 450 + 56 x 50036 x 450 + 44 x 500

= 56800/38200

= 284/191.

Answer 3)

Required number of chairs =  35 x 12100 x 50000
= 3600.

The state of California uses a mechanism known as NOTS.

NOTS stands for Negligent Operator Treatment System.

What is this:

It is a program that is known to rehabilitate chronic violators of the driving laws in California. It consists of a series of computer generated warning letters and sanctions against violators. It affects drivers with age 18 years old and above in California.

How it works:

The actions in this program are based on "negligent operator points" that is being recorded every time period. These are added continuously until it reaches a certain degree which it needs an administrative hearing. Points are being assigned depending on the degree of the offense. It would range from zero to three points.

Total work is given by L.C.M of 72, 48, 36

Total work = 144 units

Efficieny of A = 144/72 = 2 units/day

Efficieny of B = 144/48 = 3 units/day

Efficieny of C = 144/36 = 4 units/day

According to the given data,

2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100

3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54

p = 198/16.5

p = 12 days.

Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day

(C+D) in p days = (4 + 6) x 12 = 120 unit

Remained part of work = (144-120)/144 = 1/6.

F-F = 4 - 4 = 0

Ca-F = 4 - 1 = 3.0

H-F = 4 - 2.2 = 1.8

Na-F = 4 - 0.93 = 3.07

Hence, the highest electronegativity difference is in Na-F.

As now, the time 4 : 48 pm after 45 min it will be

4:48 + 45 min = (4 hrs : 48 + 12 min) pm + 33 min = 5 hrs : 33 min pm.

Hence, it is 5:33 pm.