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Q:

If E = 5 and READ is coded as 7, then what is the code of 'DEAR' ?

A) 6	B) 7
C) 8	D) 9

Answer & Explanation Answer: B) 7

Explanation:

Here E = 5 = 5/1 = 5

=> READ = 18 + 5 + 1 + 4 = 28/4 = 7

=> DEAR = 4 + 5 + 1 + 18 = 28/4 = 7

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Filed Under: Coding and Decoding
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Q:

If two line pa + b = 2 and 3a + b = 4 are parallel to each other, then what is the value of p ?

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: C) 3

Explanation:

Given two lines are parallel

pa+b=2

b=-pa+2..........(1)

3a+b=4

b=-3a+4 ...........(2)

m₁ = -p

m₂= -3

The condition for the two lines to be parallel is m₁=m₂

p = 3

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Filed Under: Arithmetical Reasoning
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Q:

Which Country has opened its fifth Nuclear Power Plant to meet its growing energy demands ?

A) India	B) Pakistan
C) Russia	D) China

Answer & Explanation Answer: B) Pakistan

Explanation:

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Q:

P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

A) 99	B) 100
C) 89	D) 1

Answer & Explanation Answer: A) 99

Explanation:

Let, Distance between A and B = d

Distance travelled by P while it meets Q = d + 11

Distance travelled by Q while it meets P = d – 11

Distance travelled by Q while it meets R = d + 9

Distance travelled by R while it meets Q = d – 9

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

But given Ratio of speeds of P & R => P : R = 3 : 2

$\frac{S P}{S R} = \frac{S P}{S Q} x \frac{S Q}{S R} = \frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$

=> $\frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$ = 3/2

=> d = 1, 99

=> d = 99 satisfies.

Therefore, Distance between A and B = 99

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Filed Under: Time and Distance
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Q:

If the labour cost 20% of the cost of production and raw material cost 10% of the cost of production and the price on which article is sold is 20% above the cost of production. If the price of labour is increased by 40% and the price of raw material increased by 20% and rest other expenditure of cost remain constant. The industry thus decide to increase the selling price by 10%. Find the new profit percent ?

A) 18%	B) 20%
C) 22%	D) 24%

Answer & Explanation Answer: B) 20%

Explanation:

Let the Cost of Production of the article = 100

Then, Labour Cost = 20

Raw Material = 10

Other Expenditure = 100 - 10 – 20 = 70

Selling Price of the article = 120

After increasing Labour and Raw material cost by 40% & 20% respectively,

New Labour cost = 28

New Raw material cost = 12

New Cost of Production = 70 + 28 + 12 = 110

Then, New SP = 110% of 120 = 120 x 110/100 = 132

=> New Gain = 132 - 110 = 22

=> New Profit % = 22 x 100/110 = 20%

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Filed Under: Profit and Loss
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Q:

If two is subtracted from each odd digit and three is added to each even digit in the number 94257636, how many digits will appear twice in the new number thus formed ?

A) 0	B) 1
C) 2	D) 3

Answer & Explanation Answer: D) 3

Explanation:

EXP.

Here 5, 7 & 9 are repeating after modulation.

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Filed Under: Arithmetical Reasoning
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Q:

If the average height of boys in a hall is 180 cm and that of girls is 150 cm. If the average height of the gathering is 165 cm, then find the number of girls present in the hall if the number of boys present in the hall are 78 ?

A) 56	B) 64
C) 87	D) 78

Answer & Explanation Answer: D) 78

Explanation:

Using Trial and error method,

we get the number of girls in the hall = 78

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Filed Under: Average
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Q:

Priya can do a work in 16 days. In how many days will the work be completed by Sai, if the efficiency of Sai is 60% more than that of Priya ?

A) 8 days	B) 12 days
C) 14 days	D) 10 days

Answer & Explanation Answer: D) 10 days

Explanation:

Ratio of efficiencies of Priya and Sai is

Sai : Priya = 160 : 100 = 8 : 5

Given Priya completes the work in 16 days

Let number of days Sai completes the work be 'd'

=> 5×16 = 8×d

d = 10 days.

Therefore, number of days Sai completes the work is 10 days.

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Filed Under: Time and Work
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