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Q:

Some children goto ice-cream shop. 9 flavours are available there. Each child takes a cone with two different flavours. No two children take same combination and they have taken all such possible combinations. How many children went to ice cream shop ?

A) 28	B) 56
C) 44	D) 36

Answer & Explanation Answer: D) 36

Explanation:

Given there are 9 flavours of ice creams.

Each child takes the combination of two flavours and no two children will have the same combination

This can be done by ways i.e children.

Number of children= $C_{2}^{9}$ = 9 x 8 / 1x 2 = 36.

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Filed Under: Permutations and Combinations
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Q:

If Reena’s age was twice of her present age, when subtracted from four times three years from hence, with three times the three years before her present age. What will be her age after one year ?

A) 22 yrs	B) 21 yrs
C) 20 yrs	D) 24 yrs

Answer & Explanation Answer: A) 22 yrs

Explanation:

Let Reena’s present age be 'K' yrs.
Given:{(K+3) x 4} - {(K-3) x 3)}
=> K = 21 yrs
So her present age is 21 yrs.
Then, her age after 1 year is 22 yrs.

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Filed Under: Problems on Ages
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Q:

Five farmers have 7,9,11,13 & 14 apple trees respectively in their orchards. Last year each of them discovered that every tree in their own orchard yields exactly the same number of apples. Further, if the 3rd farmer gives one apple to the 1st and the 5th gives 3 to each of the 2nd & d 4th, they would all exactly have the same number of apples, what were the yields per tree in the orchards of the 3rd & 4th farmers ?

A) 17 & 9	B) 9 & 11
C) 9 & 9	D) 11 & 9

Answer & Explanation Answer: D) 11 & 9

Explanation:

Let the number of apples in each tree of the 5 farmers be a, b, c, d,e respectively. Therefore total no of apples are 7a, 9b, 11c, 13d and 14e respectively.

Given,
7a+1 = 9b+3 = 11c-1 = 13d+3 = 14e-6 = x

9b+3 = 13d+3
===> 9b = 13d
so take b = 13 and d = 9

9b+3 = 9*13+3 = 120
ie, x=120

substituting
7a+1 = 120
7a = 119
a = 17

11c-1 = 120
11c = 121
c=11

14e-6 = 120
14e = 126
e = 9

Yields per tree in the orchards of d 3rd & 4th farmers= 11,9

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Filed Under: Arithmetical Reasoning
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Q:

If in an A.P series 18th term is 29 and 29th term is 18. Then find the 49th term ?

A) -3	B) -2
C) 0	D) 1

Answer & Explanation Answer: B) -2

Explanation:

We know that in A.P series
18th term = a + 17d
29th term = a + 28d
But given
a + 17d = 29..........(i)
a + 28d = 18......... (ii)
Solving equation (i) and (ii), we get
d = -1
put d = -1 in any of the above equations and we get,
a = 46
Now, we know 49th term can be written as, a + 48d
putting the value of a and d in the above equation,
a + 48d = 46 + 48(-1)
= 46 - 48
= -2

Hence, the 49th term is -2.

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Filed Under: Arithmetical Reasoning
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Q:

A can write 32 pages in 6 hours and B can write 40 pages in 5 hours. If they write together, in how many hours they can write 110 pages ?

A) 7 hrs	B) 6 hrs 10 min
C) 5 hrs 25min	D) 8 hrs 15 min

Answer & Explanation Answer: D) 8 hrs 15 min

Explanation:

A can write in 1hour = 32/6 pages

Similarly, B in 1 hour = 40/5 pages

Together (A+B) in 1 hour = 32/6 + 40/5 = 40/3

So, A+B write 40/3 pages in 1 hour

A+B write 110 pages in (3/40) x 110 Hours = 8 hours 15 min.

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Filed Under: Time and Work
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Q:

How many minutes is it until 6 o'clock if 50 minutes ago it was 4 times as many minutes past 3 o'clock ?

A) 26 min	B) 24 min
C) 22 min	D) 20 min

Answer & Explanation Answer: A) 26 min

Explanation:

Let the required number of minutes = M
Total minutes between 3o'clock and 6o' clock = 180 minutes
M + 50 + 4M = 180
5M + 50 = 180
5M = 130
M = 26 minutes.

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Filed Under: Clock puzzles
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Q:

If a 36 cm thread is used to wrap a book, lengthwise twice and breadth wise once, what is the size of the book ?

A) 288 sq.cm	B) 188 sq.cm
C) 144 sq.cm	D) 244 sq.cm

Answer & Explanation Answer: A) 288 sq.cm

Explanation:

Length of the thread is 36 cms.
length wise twice breath wise once then totally thrice.
so 36/3 = 12.
so length is 12 x 2 = 24 cms
breath is 12 cms
Area of the book = length x breath = 24 x 12 = 288 sq.cm

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Filed Under: Area
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Q:

There are n boxes and m fruits. If we put 3 fruits in each box 3 fruits will be excess. If we put 4 fruits in each box 1 box will be excess. Find number of boxes and fruits ?

A) 3 & 9	B) 6 & 19
C) 7 & 24	D) 5 & 18

Answer & Explanation Answer: C) 7 & 24

Explanation:

7 boxes & 24 Balls.
Let, n = No. of boxes ; m = No. of fruits
3n+3 = m---------->(1)
4(n-1)= m---------->(2)
=>4n-4 = 3n+3;
=>4n-3n = 4+3
n = 7
Put n=7 in eqn(1)
=> 3(7)+3 = m
21+3 = m
m = 24;

Number of boxes = 7 and fruits = 24

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Filed Under: Arithmetical Reasoning
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