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Q:

If (2a + 3b)/(5a - 3b) = 23/5 , then the value of ba is ?

A) 5	B) 4
C) 20	D) 28

Answer & Explanation Answer: C) 20

Explanation:

Given (2a + 3b)/(5a - 3b) = 23/5
=> 10a + 15b = 115a - 69b
=> 105a = 84b => 5a = 4b
a/b = 4/5 => a=4 & b=5
=> bxa = 5x4 = 20.

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Filed Under: Ratios and Proportions
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Q:

If you had the chance to start your career over again, what would you do differently ?

Answer

This depends on several factors. Different Individuals have different answers for it.
You can answer as - " I will most likely be involved in a different but still related career path; something to do with the creative side. If I were to start over I would attempt to get myself to specialize in one area as a young man. It’s very interesting to follow one’s interests all at the same time, but you don’t get anywhere very quickly this way. By pursuing lots of interests all at the same time, it takes a long, long time to acquire professional level skills."

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Q:

There are 209 doctors and nurses in a hospital. If the ratio of the doctors to the nurses is 11 : 8, then how many nurses are there in the hospital?

A) 88	B) 96
C) 108	D) 121

Answer & Explanation Answer: A) 88

Explanation:

Given,
The ratio of the doctors to the nurses is 11 : 8
Number of nurses = 8/19 x 209 = 88.

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Filed Under: Ratios and Proportions
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Q:

If y/(x - z) = (y + x)/z = x/y then find z : y : x ?

A) 1:2:3	B) 3:2:4
C) 4:3:2	D) 2:3:4

Answer & Explanation Answer: B) 3:2:4

Explanation:

Given, y/(x - z) = (y + x)/z = x/y
$y z = x y + x^{2} - y z - x z . . . . (1)$
Also $\frac{x}{y} = \frac{y}{x - z}$ $\Rightarrow x^{2} - x z = y^{2} . . . . (2)$
Using (1) and (2), we get yz = xy - yz + $y^{2}$
2yz = xy + $y^{2}$
2z = x + y
Only option (B) satisfies the equation.

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Q:

If x is a whole number, then x²(x² - 1) is always divisible by ?

A) 4	B) 8
C) 12	D) None

Answer & Explanation Answer: C) 12

Explanation:

we can do this by trial and error method.

Putting x = 2,we get 2²(2² - 1) = 12.
checking with other integers, the above equation always gives a value which is a multiple of 12,
So, x²(x² - 1) is always divisible by 12.

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Filed Under: Numbers
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Q:

If $\log_{7} (2)$ = m, then $\log_{49} (28)$ is equal to ?

A) 1/(1+2m)	B) (1+2m)/2
C) 2m/(2m+1)	D) (2m+1)/2m

Answer & Explanation Answer: B) (1+2m)/2

Explanation:

$\log_{49} (28) = \frac{1}{2 \log_{7} (7 \times 4)}$

= $\frac{1}{2} + \frac{1}{2} (2 \log_{7} (2))$
= $\frac{1}{2} + \log_{7} (2)$
= $\frac{1}{2} + m$
= $\frac{1 + 2 m}{2}$ .

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Filed Under: Logarithms
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Q:

If x and y are the two digits of the number 653xy such that this number is divisible by 80, then x+y is equal to ?

A) 5	B) 4
C) 3	D) 2

Answer & Explanation Answer: D) 2

Explanation:

Since 653xy is divisible by 5 as well as 2, so y = 0.
Now, 653x0 must be divisible by 8.
So, 3x0 must be divisible by 8. This happens when x = 2
x + y = (2 + 0) = 2.

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Q:

If $a^{2} + b^{2} = c^{2}$ , then $\frac{1}{l o g_{c + a} (b)} + \frac{1}{l o g_{c - a} (b)} = ?$

A) 1	B) 2
C) 4	D) 8

Answer & Explanation Answer: B) 2

Explanation:

Given $a^{2} + b^{2} = c^{2}$

Now $\frac{1}{\log_{c + a} (b)} + \frac{1}{\log_{c - a} (b)}$

= $\log_{b} (c + a) + \log_{b} (c - a)$

= $\log_{b} (c^{2} - a^{2})$

= $2 \log_{b} (b) = 2$

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Filed Under: Logarithms
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