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Q:

A sales boy is allowed $4 \frac{1}{2}$ % discount on the total sales made by him plus a bonus of $\frac{1}{4}$ % on the sales over Rs.12,000.If his total earnings were Rs.2400, then his total sales(in Rs.) are ?

A) Rs.60,145.23	B) Rs.54,285.54
C) Rs.52,147.85	D) Rs.50,589.47

Answer & Explanation Answer: D) Rs.50,589.47

Explanation:

Let the total earnings be Rs.x

Then $4 \frac{1}{2}$ % of x + $\frac{1}{4}$ % of (x-12000) =2400

$\Rightarrow \frac{9}{2} \times \frac{x}{100} + \frac{1}{4} \times \frac{x - 12000}{100} = 2400$

=> x=50,589.47

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Filed Under: Percentage
Exam Prep: CAT
Job Role: Bank Clerk

Q:

The reduction potential of hydrogen half-cell will be negative if :
(1) $P (H_{2})$ = 2 atm and [H+] = 2.0 M
(2) $P (H_{2})$ = 1 atm and [H+] = 2.0 M
(3) $P (H_{2})$ = 1 atm and [H+] = 1.0 M
(4) $P (H_{2})$ = 2 atm and [H+] = 1.0 M

A) Option 1	B) Option 2
C) Option 3	D) Option 4

Answer & Explanation Answer: D) Option 4

Explanation:

$H^{+} - e^{-} \to \frac{1}{2} H_{2}$

Apply Nernst equation

$E = 0 - \frac{0.059}{1} \log (\frac{P H_{2}^{\frac{1}{2}}}{[H^{+}]})$

$E = - \frac{0.059}{1} \log (\frac{2^{\frac{1}{2}}}{1})$

Therefore E is Negative

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Filed Under: Chemistry
Exam Prep: AIEEE

Q:

A gas absorbs a photon of 355 nm and emits at two wavelengths. If one of the emissions is at 680 nm, the other is at :

A) 518 nm	B) 1035 nm
C) 325 nm	D) 743 nm

Answer & Explanation Answer: D) 743 nm

Explanation:

$\frac{1}{λ} = \frac{1}{λ 1} + \frac{1}{λ 2}$

$\frac{1}{355} = \frac{1}{680} + \frac{1}{λ 2}$

$\frac{1}{λ 2} = \frac{680 - 355}{680 \times 355}$

$\Rightarrow λ 2 = 743 n m$ .

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Filed Under: Chemistry
Exam Prep: AIEEE

Q:

In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centre positions. If one atom of B is missing from one of the face centred points, the formula of the compound is

1) $A_{2} B_{5}$

2) $A_{3} B_{2}$

3) $A_{2} B_{3}$

4) $A_{3} B_{4}$

A) Option 1	B) Option 2
C) Option 3	D) Option 4

Answer & Explanation Answer: A) Option 1

Explanation:

$Z_{A} = \frac{8}{8}$ ; $Z_{B} = \frac{5}{2}$

So formula of compound is $A B_{\frac{5}{2}}$

i.e., $A_{2} B_{5}$ .

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Filed Under: Chemistry
Exam Prep: AIEEE

Q:

Ethylene glycol is used as an antifreeze in a cold climate. Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at –6°C will be: (Kf for water = 1.86 Kg/mol and molar mass of ethylene glycol = 62 kg/mol)

A) 204.60 g	B) 304.30 g
C) 804.32 g	D) 400.00 g

Answer & Explanation Answer: C) 804.32 g

Explanation:

$∆ T_{f} = k_{f} . m$

for ethylene glycol in aq. solution

$∆ T_{f} = k_{f} \frac{w}{m o l . w t} \times \frac{1000}{w t . o f s o l v e n t} 6 = \frac{1.86 x w x 1000}{62 x 4000}$

=> w = 800 g

So, the weight of solute should be more than 800 g.

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Filed Under: Chemistry
Exam Prep: AIEEE

Q:

In a certain city, 5% of all the persons in town have unlisted phone numbers. If you select 100 names at random from that city's phone directory, how many people selected will have unlisted phone numbers?

Answer

Zero. You are selecting names from the list, so they are all listed.

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Subject: Math Puzzles

Q:

I. Rural and semi-urban areas in the country have been suffering due to load shedding for quite some time.

II. If the Government is not able to overcome the power crisis, load shedding will be extended even to the urban areas.

A) Statement I is the cause and statement II is its effect	B) Statement II is the cause and statement I is its effect
C) Both the statements I and II are effects of independent causes	D) Both the statements I and II are effects of some common cause

Answer & Explanation Answer: D) Both the statements I and II are effects of some common cause

Explanation:

The facts given in both the statements are clearly the result of acute power shortage.

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Filed Under: Cause and Effect Reasoning

Q:

Who was the Indian cricketer honored with CK Naidu Lifetime Achievement Award in 2014 ?

A) Kapil Dev	B) Sachin Tendulkar
C) Rahul Dravid	D) M S Dhoni

Answer & Explanation Answer: A) Kapil Dev

Explanation:

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Filed Under: Honours and Awards

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