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Q:

Assertion(A) : The pouring of kerosene oil on stagnant pools helps to eradicate malaria.
Reason(R) : The kerosene oil is poisonous for the mosquitoes.

A) R correctly explains A	B) R is true but A is fale
C) A is true but R is false	D) Both A and R are false

Answer & Explanation Answer: C) A is true but R is false

Explanation:

The kerosene oil sprayed on the water provodes a thin cating and the larvae of the mosquitoes are prevented from coming up to breathe. Thus, they die.
Hence, A is true but R is false.

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Filed Under: Assertion and Reason
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Q:

Assertion(A) : Most of the Himalayan rivers are perennial.
Reason(R) : They are fed by melting snow.

A) R correctly explains A	B) R is true but A is fale
C) A is true but R is false	D) Both A and R are false

Answer & Explanation Answer: A) R correctly explains A

Explanation:

Most Himalayan rivers are perennial because they are fed by the melting snow throughout the year.
Thus, both A and R are true & R correctly explains A.

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Filed Under: Assertion and Reason
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Q:

Which fraction comes next in the sequence

$\frac{2}{3}, \frac{1}{3}, \frac{5}{27}, \frac{7}{81}, ?$

A) 1/27	B) 11/278
C) 9/48	D) 7/123

Answer & Explanation Answer: A) 1/27

Explanation:

Clearly, the numerators of the fractions in the given sequence follow the series of 2, 3, 5, 7,... and the denominator follows 3, 9, 27, 81, 243, ...
Then, the next term in the given sequence is $\frac{9}{3^{5}} = \frac{9}{243} = \frac{1}{27}$ .

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Filed Under: Number Series
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Q:

Choose what replaces '?' in the following figure ?

creative111486456294.jpg image

A) Q	B) O
C) M	D) N

Answer & Explanation Answer: D) N

Explanation:

The alphabetical value of the letters in the left hand column follows through the sequence of Prime Numbers, with the letters in the right hand column representing the corresponding reverse alphabetical values. So,

M = Reverse of M = N.

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Filed Under: Missing letters puzzles
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Q:

Paw : Cat :: Hoof : ?

A) Donkey	B) Lion
C) Elephant	D) Horse

Answer & Explanation Answer: D) Horse

Explanation:

The cat's foot is called a paw. The horse's foot is called a hoof.

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Filed Under: Analogy
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Q:

Frugal : Parsimonious :: ?

A) joy : ecstasy	B) rich : poor
C) love : hate	D) poor : misery

Answer & Explanation Answer: A) joy : ecstasy

Explanation:

Frugal and parsimonious are synonyms of each other and bear the meaning 'being stingy' or 'sparing'. Similarly, joy and ecstasy are related to happiness.

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Filed Under: Analogy
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Q:

Statement: A large number of students who have passed their XII Std. terminal examination in the country could not get admission to colleges as the number of seats available are grossly inadequate.
Courses of action:
a. The evaluation system of XII Std. terminal examination should be made more tough so that fewer students pass the examination.
b. The Government should encourage the private sector to open new colleges by providing them land at cheaper rate.
c. The rich people should be asked to send their wards to foreign countries for higher studies enabling the needy students to get admission in colleges within the country.

A) only a and b follows	B) Only c follows
C) Only b follows	D) All a, b & c follows

Answer & Explanation Answer: C) Only b follows

Explanation:

Clearly, reducing the number of aspirants for admission to colleges or sending the students of well-to-do families to foreign countries for higher studies, is no proper solution. So, both I and III do not follow. The right solution is to increase the number of colleges so as t accommodate the increasing number of admission-seekers. So, only II follows.

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Filed Under: Statement and Courses of Action
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Q:

Three maths classes: A, B and C take an algebra test. The average score of class A is 83. The average score of class B is 76. The average score of class C is 85. The average score of class A and B is 79 and average score of class B and C is 81. What is the average score of classes A, B, C ?

A) 81	B) 78
C) 80.5	D) 81.5

Answer & Explanation Answer: D) 81.5

Explanation:

Let the number of students in classes A, B and C be P, Q and R respectively.
Then, total score of A = 83P, total score of B = 76Q, total score of C = 85R.
Also given that,
(83P + 76Q) / (P + Q) = 79
=>4P = 3Q.
(76Q + 85R)/(Q + R) = 81
=>4R = 5Q,
=>Q = 4P/3 and R = 5P/3
Therefore, average score of A, B, C = ( 83P + 76Q + 85R ) / (P + Q + R) = 978/12 = 81.5

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Filed Under: Average
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