How many 18' s are there in 3712?
3712 = 752
Required number = 75218 = 75 x 4 = 300
Simplify the following expression:
Express in meters the sum of 0.5035 km, 332.9 cm, and 1771mm:
The value of 323÷1130of23-14of212÷35×44525of712÷34-34×112÷214 is:
If 5sinθ=4, then the value of secθ+4cotθ4tanθ-5cosθ is:
The value of sec6θ-tan6θ-3sec2θtan2θ+1cos4θ-sin4θ+2sin2θ+2 is:
In triangle ABC, ∠C=90°, AC = 5 cm and BC = 12 cm. The bisector of ∠A meets BC at D. What is the length of AD?
If 16a4+36a2b2+81b4=91 and 4a2+9b2-6ab=13, then what is the value of 3ab?
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