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Quantitative Aptitude - Arithmetic Ability/
Square Roots and Cube Roots /
Question

What should come in place of both the question marks in the equation

$\frac{?}{\sqrt{128}} = \frac{\sqrt{162}}{?}$

A) 12	B) 14
C) 144	D) 196

Answer: A) 12

Explanation:

Let $\frac{x}{\sqrt{128}} = \frac{\sqrt{162}}{x}$

Then, $x^{2} = \sqrt{128 \times 162} = \sqrt{64 \times 2 \times 18 \times 9} = \sqrt{(8^{2} \times 6^{2} \times 3^{2})} = 8 \times 6 \times 3 = 144$

$∴ x = 12$

Subject: Square Roots and Cube Roots

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Which of the following numbers will have an irrational square root?

A) 1024	B) 2401
C) 4096	D) 2048

A) 1024

B) 2401

C) 4096

D) 2048

Answer & Explanation Answer: D) 2048

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Which of the numbers given below is the square root of 15376?

A) 122	B) 124
C) 134	D) 128

A) 122

B) 124

C) 134

D) 128

Answer & Explanation Answer: B) 124

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Which of the numbers given below is the square root of 14161?

A) 119	B) 121
C) 131	D) 141

A) 119

B) 121

C) 131

D) 141

Answer & Explanation Answer: A) 119

Explanation:

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What is the value of $\sqrt{729} + \sqrt{72.9} + \sqrt{7.29}$

A) 30.5	B) 32.33
C) 35.6	D) 38.23

A) 30.5

B) 32.33

C) 35.6

D) 38.23

Answer & Explanation Answer: D) 38.23

Explanation:

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Determine the value of $(\frac{1}{r} + \frac{1}{s})$ when $r^{3} + s^{3} = 0 and r + s = 6$ ?

A) 0	B) 0.5
C) 1	D) 2

A) 0

B) 0.5

C) 1

D) 2

Answer & Explanation Answer: B) 0.5

Explanation:

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What is the remainder, when $4 x^{4} + 10 x^{3} - 20 x^{2} + 90 is divided by (x + 2)$ ?

A) 0	B) -6
C) 45	D) 90

A) 0

B) -6

C) 45

D) 90

Answer & Explanation Answer: B) -6

Explanation:

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If a is positive and $a^{2} + \frac{1}{a^{2}} = 7, then a^{3} + \frac{1}{a^{3}} = ?$

A) 9	B) 27
C) 18	D) 0

A) 9

B) 27

C) 18

D) 0

Answer & Explanation Answer: C) 18

Explanation:

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Cube root of 729 then square it

A) 9	B) 36
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A) 9

B) 36

C) 81

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Answer & Explanation Answer: C) 81

Explanation:

729 = 9 x 9 x 9

=> Cube root of 729 = 9

Now, required square of 9 = 9 x 9 = 81.

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What should come in place of both the question marks in the equation ?128=162?

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What should come in place of both the question marks in the equation

$\frac{?}{\sqrt{128}} = \frac{\sqrt{162}}{?}$