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Q:

What is the first term of an arithmetic progression of positive integers ?

(I) Sum of the squares of the first and the second term is 116.

(II)The fifth term is divisible by 7.

A) Only a is sufficient B) Only b is sufficient
C) Both a & b are necessary D) None

Answer:   A) Only a is sufficient



Explanation:

The sum of square of two no is 116 i.e no lie 1-11, because 11x11 =121 which is greater than 116
again after cheaking all possible pair of no only 4 and 10 satisfy this condsn , again the progression is of positive integer so 10 cant not be 1st term
so the 1st term is 4,
but from the 2nd we cant able to find the 1st term

so only 1st statement is sufficient to answer the question

Subject: Statement and Conclusions
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K > R = L, P > L, R ≥ S
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I. S < L
II. L = S

A) If only conclusion I follow. B) If only conclusion II follow.
C) If either conclusion I or conclusion II follows. D) If neither conclusion I nor II follows.
 
Answer & Explanation Answer: C) If either conclusion I or conclusion II follows.

Explanation:

K > R = L, P > L, R ≥ S
L = R ≥ S
Conclusions:
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II. L = S
This forms a complementary pair - S is either smaller or equal to L. Hence, the correct option is Either conclusion I or conclusion II follows.

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