A town having teenagers(boys & girls) of 5000 | Time and Work Questions & Answers

Q:

16 women can do a piece of work in 10 days while 15 men can do the same work in 12 days. All men and all women work alternately starting with all men, then find the time taken by them to complete the whole work?

A) 10 5/2 days	B) 11 days
C) 11 2/5 days	D) 12 1/2 days

Answer & Explanation Answer: A) 10 5/2 days

Explanation:

Let efficiency of every man and every woman be 'm' unit/day and 'w' unit/day respectively

15×12×m = 10×16×w

⇒ m/w = 8/9

Total work = 15 × 12 × 9 = 1620 units

In 2 days, total work done = 15 x 9 + 16 x 8 = 263 units

So, in 10 days work done will be = 263 × 5 = 1315 units

Remaining work will be done in = (1620-1315)/(15×8) = 5/2 days

Total days = 10 5/2 days.

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Q:

A and B can do a piece of work for Rs 1540. Find the difference between the wages of C and B for the same work If A can do the work in 12 days and B can do the same work in 8 days and with the help of C, A and B can do the same work in 2 days?

A) 980	B) 1232
C) 810	D) 1121

Answer & Explanation Answer: B) 1232

Explanation:

From the given data,

Day Capacity

A -> 12 2

B -> 8 3 2

A + B + C -> 2 12

=> Capacity of C = 12 - 5 = 7

Ratio of capacity of A : B : C = 2 : 3 : 7

Difference of wages of C & B = 4/5 x 1540

= 4 x 308 = Rs. 1232

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4 856

Q:

16 men and 12 women can complete a work in 20 days. 18 women can complete the same work in 40 days. In how many days will 12 men 27 women complete the same work?

A) 16 days	B) 18 days
C) 19 days	D) 21 days

Answer & Explanation Answer: A) 16 days

Explanation:

(16M + 12W) x 20 = 18W x 40

=> 2M = 3W

Then,
Convert all men into women

12M + 27W = 27 + 12 x 3/2W = 45W

Let number of days required be 'D'

=> 18 x 40 = 45 x D

=> D = 16 days.

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3 746

Q:

M can complete a piece of work in 10 days. N is 33.33% less efficient than M. calculate the number of days required to both to complete the work?

A) 6 days	B) 8 days
C) 11 days	D) 13 days

Answer & Explanation Answer: A) 6 days

Explanation:

M = 10 days

The ratio of efficiency of M & N are 3 : 2

Hence, the time rquired for N alone = 15 days

=> Required time taken t=by both to complete the work = M x N / M + N

= 10 x 15/ 10 + 15

= 150/25

= 6 days.

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Q:

Meghana alone would take 32 hours more to complete a job than both Meghana and Ganesh together. If Ganesh worked alone, he took 12 1/2 hours more to complete it than both Meghana and Ganesh worked together. What time would they take if both Meghana and Ganesh worked together?

A) 20 hrs	B) 18 hrs
C) 22 hrs	D) 20.5 hrs

Answer & Explanation Answer: A) 20 hrs

Explanation:

Time taken by both Meghana and Ganesh to work together is given by =

$\sqrt{t_{1} x t_{2}}$

Where

$t_{1} = 32 h r s t_{2} = 12 \frac{1}{2} h r s = \frac{25}{2} h r s$

Therefore, time took by both to work together =

$\sqrt{32 x \frac{25}{2}} = \sqrt{16 x 25} = 4 x 5 = 20 h r s$

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Q:

Aadi can do a piece of work in 12 days alone, Bunny can do the same work in 16 days alone. After Aadi has been working for 5 days and Bunny for 7 days, Charan finishes it in 14 days. In how many days will Charan alone be able to do the work?

A) 96 days	B) 48 days
C) 24 days	D) 12 days

Answer & Explanation Answer: A) 96 days

Explanation:

Let number of days Charan can do the same work alone is 'd' days.

According to the given data,

$\frac{5}{12} + \frac{7}{16} + \frac{14}{d} = 1 \frac{14}{d} = 1 - \frac{(20 + 21)}{48} \frac{14}{d} = \frac{48 - 41}{48} d = \frac{14 x 48}{7} d = 96 days$

Therefore, Charan alone can complete the work in 96 days.

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Q:

Prabhas is twice as good a workman as Rana and finishes a piece of work in 3 hours. In how many hours they together could finish that piece of work?

A) 3 hrs	B) 3.5 hrs
C) 2.5 hrs	D) 2 hrs

Answer & Explanation Answer: D) 2 hrs

Explanation:

Given Prabhas is twice as good a workman as Rana.

Prabhas finishes the work in 3 hrs

=> Rana finishes the work in 6 hrs.

Number of hours required together they could finish the work

= 3 x 6 / 3 + 6

= 18/9

= 2 hrs.

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Q:

Three athletes can complete one round around a circular field in 16, 24 and 36 min respectively. They start running together at same instant then after how much time they will meet to each other for first time ?

A) 2 hrs 24 min	B) 2 hrs 44 min
C) 1 hrs 24 min	D) 1 hrs 24 min

Answer & Explanation Answer: A) 2 hrs 24 min

Explanation:

Given that three athletes can complete one round around a circular field in 16, 24 and 36 min respectively.

Now, required time after which they met for the first time = LCM of (16, 24 & 36) min

Now, LCM of 16, 24, 36 = 144 minutes = 2 hrs 24 min.

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A) 8	B) 6
C) 4	D) 2

A town having teenagers(boys & girls) of 5000 requires 150 litre of water per head. It has a tank measuring 20 m × 15 m × 5 m. The water of this tank will sufficient for ____ days.

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