# Line Charts Questions

Q:

The following line graph gives the ratio of the amounts of imports by a company to the amount of exports from that company over the period from 1995 to 2001.

Ratio of Value of Imports to Exports by a Company Over the Years.

1. If the imports in 1998 was Rs. 250 crores and the total exports in the years 1998 and 1999 together was Rs. 500 crores, then the imports in 1999 was ?

A. Rs. 250 cr         B. Rs. 300 cr         C. Rs. 357 cr         D. Rs. 420 cr

2. The imports were minimum proportionate to the exports of the company in the year ?

A. 1995                 B. 1996                 C. 1997                 D. 2000

3. What was the percentage increase in imports from 1997 to 1998 ?

A. 72                     B. 56                     C. 28                     D. Data Inadequate

4. If the imports of the company in 1996 was Rs. 272 crores, the exports from the company in 1996 was ?

A. Rs. 370 cr         B. Rs. 320 cr         C. Rs. 280 cr         D. Rs. 275 cr

5. In how many of the given years were the exports more than the imports ?

A. 1                       B. 2                       C. 3                       D. 4

1. ANSWER : D

Explanation - The ratio of imports to exports for the years 1998 and 1999 are 1.25 and 1.40 respectively.

Let the exports in the year 1998 = Rs. x crores.

Then, the exports in the year 1999 = Rs. (500 - x) crores.

$\inline&space;\fn_cm&space;\therefore&space;1.25=\frac{250}{x}\Rightarrow&space;x=\frac{250}{1.25}=200$        [ Using ratio for 1998 ]

Thus, the exports in the year 1999 = Rs. (500 - 200) crores = Rs. 300 crores.

Let the imports in the year 1999 = Rs. y crores.

Then, $\inline&space;\fn_cm&space;1.40=\frac{y}{300}\Rightarrow&space;y=(300\times&space;1.40)=420$

Imports in the year 1999 = Rs. 420 crores.

2. ANSWER : C

Explanation - The imports are minimum proportionate to the exports implies that the ratio of the value of imports to exports has the minimum value.

Now, this ratio has a minimum value 0.35 in 1997, i.e., the imports are minimum proportionate to the exports in 1997.

3. ANSWER : D

Explanation - The graph gives only the ratio of imports to exports for different years. To find the percentage increase in imports from 1997 to 1998, we require more details such as the value of imports or exports during these years.

Hence, the data is inadequate to answer this question.

4. ANSWER : B

Explanation -  Ratio of imports to exports in the year 1996 = 0.85.

Let the exports in 1996 = Rs. x crores.

Then , $\inline&space;\fn_cm&space;\frac{272}{x}=0.85\Rightarrow&space;x=\frac{272}{0.85}=320$

Exports in 1996 = Rs. 320 crores.

5. ANSWER : D

Explanation - The exports are more than the imports imply that the ratio of value of imports to exports is less than 1.Now, this ratio is less than 1 in years 1995, 1996, 1997 and 2000.

Thus, there are four such years.

2098
Q:

Study the following line graph and answer the questions based on it.

Number of Vehicles Manufactured by Two companies ove the Years (Number in Thousands)

1. What is the difference between the number of vehicles manufactured by Company Y in 2000 and 2001 ?

A. 50000                   B. 42000                   C. 33000                   D. 21000

2. What is the difference between the total productions of the two Companies in the given years ?

A. 19000                   B. 22000                   C. 26000                   D. 28000

3. What is the average numbers of vehicles manufactured by Company X over the given period ? (rounded off to nearest integer)

A. 119333                 B. 113666                 C. 112778                 D. 111223

4. In which of the following years, the difference between the productions of Companies X and Y was the maximum among the given years ?

A. 1997                     B. 1998                     C. 1999                     D. 2000

5. The production of Company Y in 2000 was approximately what percent of the production of Company X in the same year ?

A. 173                       B. 164                       C. 132                       D. 97

1. ANSWERS  : D

Explanation-   Required difference = (128000 - 107000) = 21000.

2. ANSWERS  : C

Explanation-  From the line-graph it is clear that the productions of Company X in the   years 1997, 1998, 1999, 2000, 2001 and 2002 are 119000, 99000, 141000, 78000, 120000 and 159000 and those of Company Y are 139000, 120000,100000, 128000, 107000 and 148000 respectively.

Total production of Company X from 1997 to 2002

= 119000 + 99000 + 141000 + 78000 + 120000 + 159000

= 716000.

and total production of Company Y from 1997 to 2002

= 139000 + 120000 + 100000 + 128000 + 107000 + 148000

= 742000.

Difference = (742000 - 716000) = 26000.

3. ANSWERS  : A

Explanation-  Average number of vehicles manufactured by Company X

$\inline&space;\fn_cm&space;\frac{1}{6}\times&space;(119000&space;+&space;99000&space;+&space;141000&space;+&space;78000&space;+&space;120000&space;+&space;159000)$

= 119333.

4. ANSWERS  : D

Explanation-   The difference between the productions of Companies X and Y in various years are:

For 1997 (139000 - 119000)  = 20000.

For 1998 (120000 - 99000)  = 21000.

For 1999 (141000 - 100000)  = 41000.

For 2000 (128000 - 78000) = 50000.

For 2001 (120000 - 107000) = 13000.

For 2002 (159000 - 148000) = 11000.

Clearly, maximum difference was in 2000.

5. ANSWERS  :  B

Explanation  - Required percentage= $\inline&space;\fn_cm&space;{&space;\left&space;(&space;\frac{128000}{78000}\times&space;100&space;\right&space;)}$% = 164%

1596
Q:

The following Line chart gives the ratio of the amounts of imports by a Company to the amount of exports from that Company over the period from 1995 to 2001. Answer the following questions based on fo

1. In how many of the given years were the exports more than imports ?

A. 1                          B. 2                          C. 3                          D.4

2. The imports were minimum proportionate to the exports of the Company in the year :

A. 1997                    B. 1995                    C. 1996                    D. 2000

3. If the imports of a company in 1996 was Rs. 272 crores, the exports from the company in 1996 was:

A. Rs 120 Cr            B. Rs 220 Cr            C. Rs 320 Cr            D. Rs 420 Cr

4. What was the percentage increase in imports from 1997 to 1998 ?

A. 70                        B. 72                        C. 74                        D. Data Inadequate

5. If the imports in 1998 was Rs. 250 crores and the total exports in years 1998 and 1999 together was Rs 500 crores, then the imports in 1999 was :

A. Rs.320 Cr            B. Rs.420 Cr            C. Rs.520 Cr            D. Rs.620 Cr

1. ANSWER : D

Explanation -  Clearly the exports are more than the imports implies that the ratio of value of imports to exports in less than 1. So years are 1995, 1996, 1997 and 2000. So these are four years

2. ANSWER : A

Explanation - Clearly from the line graph we can judge it is minimum in year 1997.

3. ANSWER : C

Explanation -  We are given with the ratio of imports and exports in the line graph.
Let the exports from the company in 1996 was x then,
272/x = 0.85
=> x = 272/0.85
=> x = 320

Note: Please not that we are given the ratio of imports to exports, so export will will in denominator .

4. ANSWER : D

Explanation -
For calculating the percentage we will need value of exports, imports etc. We are only given with the ratio. So data in Inadequate.

Note: Please note in charts questions, most probably it includes 1 or more than 1 questions which are percentage based. So please clear percentage questions before preparing it. Because this is very scoring section.

5. ANSWER : B

Explanation - The Ratio of imports to exports for the years 1998 and 1999 are 1.25 and 1.40 respectively. Let the exports in the year 1998 = Rs. x crores
Then,the exports in the year 1999 = (500-x) crores

=> 1.25 = 250/x [because 1.25 is 1998 ratio]

=> x = 250/1.25 = 200 crore

Thus the exports in the year 1999 were 500 - 200
= 300 crore

Let the imports in the year 1999 = Rs y crore
Then 1.40 = y/300
=> y = 1.40*300 = 420 crore

724
Q:

A train runs through cities A, B, C, D, E, F, G and H. The line graph indicates the time schedule of the train including times of arrival and departure.

1. The total stoppage time at the cities in the first half and second half of the total distance is in the ratio.

1. 1 : 3             2. 3 : 1             3. 2 : 1             4. 1 : 2

2. Between how many pairs of consecutive stations does the speed run below the overall average speed of the entire trip?

1. 2                     2. 1                    3. 3                     4. 4

3. If the train stops at each city for 50% more time than what it is at present, then at what time will it arrive at city H after departing from city A as per schedule ?

1. 20.16             2. 19.02             3. 18.51             4. 18.59

4. The overall average speed of the entire trip excluding stoppage time is nearly :

1. 75 km/h        2. 81 km/h        3. 46 km/h        4. 65 km/hr

5. What percent of time of the entire trip was actually spent travelling between the cities ?

1. 91.8%             2. 7.6%             3. 76%               4. 24%

1. Answer : 4

Explanation : Required ratio = $\inline \dpi{100} \fn_cm \frac{10+2+5}{10+15+10}=\frac{17}{35}\approx \frac{1}{2}=1:2$

2. Answer : 1

Explanation : A to B Speed = $\inline \dpi{100} \fn_cm \frac{140\times 3}{5}$ = 84

B to C Speed = $\inline \dpi{100} \fn_cm \frac{91\times 3}{4}$ = 68.25

C to D Speed = $\inline \dpi{100} \fn_cm \frac{149\times 60}{103}$ = 86.796

D to E Speed = $\inline \dpi{100} \fn_cm \frac{88\times 3}{4}$ = 66

E to F Speed = $\inline \dpi{100} \fn_cm \frac{106\times 4}{5}$ = 84.8

F to G Speed = $\inline \dpi{100} \fn_cm \frac{176}{2}$ = 88

G to h Speed = $\inline \dpi{100} \fn_cm \frac{110\times 4}{5}$ = 88

Average speed of entire trip = $\inline \dpi{100} \fn_cm \frac{84+68.25+86.796+66+84.8+88+88}{7}$ =80.83

3. Answer : 3

Explanation :  Total half time = 10 + 2 + 5 + 10 + 15 + 10 = 52

Total half time, if the train stops at each city for 50% more = $\inline \dpi{100} \fn_cm 52\times \frac{150}{100}$ = 78

Train will arrive at city H after departing from city A = 18.25 + (78 - 52 ) = 18.25 + 26 = 18.51

4. Answer : 2

Explanation : Average speed = $\inline \dpi{100} \fn_cm \frac{84+68.25+86.796+66+84.8+88+88}{7}$ = 80.83 = 81 km/hr

5. Answer : 1

Explanation :  Required percentage of time = $\inline \dpi{100} \fn_cm \frac{1.40+1.20+1.43+1.20+1.15+2+1.15}{18.25-7}\times 100$

$\inline \dpi{100} \fn_cm \frac{10.23}{11.25}\times 100$

= 91.8 %