Problems on Ages Questions

Let the present age of Pinky be x years

Then the age of Mary is x - 12 years

After 3 years,

Ratio of  MaryPinky = x - 9x + 3 = 58

8x - 72 = 5x +15

=> 3x = 87

=> x = 29

=> Age of Pinky = 29 years

=> Age of Mary = 29 - 12 = 17 years

Present age of Sam = 29 + 17 = 46

Before 15 years Sam age = 46 - 15 = 31 years.

X= 2/3Y 

=> Y= 3/2X

Aage of X after 6 years = 46 years

So present age of X = 46-6 = 40 years

Now, present age of Y = 3/2 * 40 = 60 years.

Let father's age be x year and son's age be y year.

According to question,

2(x+y) = 8y _______(I)

and (x+y)/2 = 30

=> x+y = 60 years__________(II)

From equation (I) and (II)

8 y = 120

y = 15 years,

Hence x = 45 years.

Let Mohan present age = p

ATQ,

5/6 x p = p - 5

p = 30

His wifes age = 30 - 3 = 27 yrs.

Total age of 10 students = 150 years

Total age of 15 students = 240 years

Total age of 5 new students = 240 - 150 = 90 years

 Average age of 5 new students = 90/5 = 18 years.

Let their ages be x, y, z
Hence given that x + y + z = 65
Now, six years ago x age is x - 6, y is y - 6 and that of z is z - 6
Then the sum of their ages six years ago is (x + y + z) - (6 + 6 + 6) = 65 - 18 = 47

Let present ages of Sushanth = w, Krish = x, Rishi = y and Rohit = z , then
w + x + y = 43 x 3 = 129 ---(i) and
w + y + z = 49 x 3 = 147 ---(ii)
Subtracting (i) from (ii), (w+y+z) - (w+x+y) = 147 - 129 , z - x = 18 ---(iii)
Given Rohit's age=z=54, so from (iii), x = 54 - 18 = 36.
Therefore, Krish age is 36 years.

According to the given data,

(V + R)/2 = 24

Now, after joining of Veerender,

V + R + D)/3 = 25.5

Hence, Veerender Age = 3(25.5) - 2(24) = 76.5 - 48 = 28.5 years.