## Quantitative Aptitude - Arithmetic Ability Question & Answers

What was the day on 15th august 1947 ?

A) Friday | B) Saturday |

C) Sunday | D) Thursday |

Explanation:

15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)

Odd days in 1600 years = 0

Odd days in 300 years = 1

46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day

Jan. Feb. Mar. Apr. May. Jun. Jul. Aug

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 1 ) = 213 days = (30 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days.

Given day is Friday.

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Subject: Calendar - Quantitative Aptitude - Arithmetic Ability

Today is Monday. After 61 days, it will be :

A) Tuesday | B) Monday |

C) Sunday | D) Saturday |

Explanation:

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

After 61 days, it will be Saturday.

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Subject: Calendar - Quantitative Aptitude - Arithmetic Ability

A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.

A) 360, 160, 200 | B) 160, 360, 200 |

C) 200, 360,160 | D) 200,160,300 |

Explanation:

let ratio be x.

Hence no. of coins be 5x ,9x , 4x respectively

Now given total amount = Rs.206

=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206

we get x = 40

=> No. of 50p coins = 200

=> No. of 25p coins = 360

=> No. of 10p coins = 160

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Subject: Ratio and Proportion - Quantitative Aptitude - Arithmetic Ability

In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was :

A) 2500 | B) 2700 |

C) 2900 | D) 3100 |

Explanation:

Total number of votes = 7500

Given that 20% of Percentage votes were invalid

=> Valid votes = 80%

Total valid votes =

1st candidate got 55% of the total valid votes.

Hence the 2nd candidate should have got 45% of the total valid votes

=> Valid votes that 2nd candidate got = total valid votes x

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Subject: Percentage - Quantitative Aptitude - Arithmetic Ability

If each side of a square is increased by 25%, find the percentage change in its area?

A) 65.25 | B) 56.25 |

C) 65 | D) 56 |

Explanation:

let each side of the square be a , then area = a x a

New side = 125a / 100 = 5a / 4

New area =(5a x 5a) / (4 x 4) = (25a²/16)

increased area== (25a²/16) - a²

Increase %= [(9a²/16 ) x (1/a² ) x 100]% = 56.25%

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Subject: Area - Quantitative Aptitude - Arithmetic AbilityExam Prep: Bank Exams

Job Role: Bank PO