# Numbers Questions

A) 6 and 2 | B) 8 and 2 |

C) 6 and 5 | D) 8 and 5 |

Explanation:

Let the number be 476ab0

476ab0 is divisible by 3

=> 4 + 7 + 6 + a + b + 0 is divisible by 3

=> 17 + a + b is divisible by 3 ------------------------(i)

476ab0 is divisible by 11

[(4 + 6 + b) -(7 + a + 0)] is 0 or divisible by 11

=> [3 + (b - a)] is 0 or divisible by 11 --------------(ii)

Substitute the values of a and b with the values given in the choices and select the values which satisfies both Equation 1 and Equation 2.

if a=6 and b=2,

17 + a + b = 17 + 6 + 2 = 25 which is not divisible by 3 --- Does not meet equation(i).Hence this is not the answer

if a=8 and b=2,

17 + a + b = 17 + 8 + 2 = 27 which is divisible by 3 --- Meet equation(i)

[3 + (b - a)] = [3 + (2 - 8)] = -3 which is neither 0 nor divisible by 11---Does not meet equation(ii).Hence this is not the answer

if a=6 and b=5,

17 + a + b = 17 + 6 + 5 = 28 which is not divisible by 3 --- Does not meet equation (i) .Hence this is not the answer

if a=8 and b=5,

17 + a + b = 17 + 8 + 5 = 30 which is divisible by 3 --- Meet equation 1

[3 + (b - a)] = [3 + (5 - 8)] = 0 ---Meet equation 2

Since these values satisfies both equation 1 and equation 2, this is the answer

A) 6393 | B) 5831 |

C) 6993 | D) 6339 |

Explanation:

(Place value of 7)-(face value of 7)

=7000-7=6993.

A) 1 | B) 2 |

C) 3 | D) 4 |

Explanation:

clearly 4864 is divisible by 4

So 9 P 2 must be divisible by 3.So(9+P+2) must be divisible by 3.

so P=1.

A) 6 | B) 7 |

C) 8 | D) 9 |

Explanation:

The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3

If the sum is 24, we need to solve the equation 3n + 3 = 24;

=> 3n = 21;

=> n = 7

The greatest of the three numbers is therefore 7 + 2 = 9

A) 86 | B) 94 |

C) 100 | D) 115 |

Explanation:

Let the number be x.Then

60% of of x=36.

Required number is 100.