# Numbers Questions

A) 553681 | B) 555181 |

C) 555681 | D) 556581 |

Explanation:

987 = 3 * 7 * 47.

So, the required number must be divisible by each one of 3, 7, 47

553681 => (Sum of digits = 28, not divisible by 3)

555181 => (Sum of digits = 25, not divisible by 3)

555681 is divisible by each one of 3, 7, 47.

A) 8 | B) 9 |

C) 10 | D) 11 |

Explanation:

Here a = 3 and r = 6/3 = 2. Let the number of terms be n.

Then, t = 384 => a * r^(n-1) = 384

=> 3 * 2^(n-1) = 384 => 2^(n-1) = 128 = 2^(7)

=> n-1 = 7 => n = 8.

A) 12/35 | B) 1/35 |

C) 35/8 | D) 7/32 |

Explanation:

Let a and b are the numbers.Then a+b is 12 and ab is 35.

a+b/ab = 12/35

1/b + 1/a = 12/35

A) 6 | B) 7 |

C) 8 | D) 9 |

Explanation:

The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3

If the sum is 24, we need to solve the equation 3n + 3 = 24;

=> 3n = 21;

=> n = 7

The greatest of the three numbers is therefore 7 + 2 = 9

A) 13 | B) 12 |

C) 11 | D) 10 |

Explanation:

(2272-875) = 1397, is exactly divisible by N.

Now , 1397 = 11 x 127

The required 3-digit number is 127,the sum of digits is 10.

A) 32761 | B) 42437 |

C) 81225 | D) 20164 |

Explanation:

The square of a natural number never ends in 7.

42437 is not the square of a natural number

A) 86 | B) 94 |

C) 100 | D) 115 |

Explanation:

Let the number be x.Then

60% of $\frac{3}{5}$of x=36.

=> $\frac{60}{100}*\frac{3}{5}*x=36$

=> $\frac{9x}{25}=36$ => x=$\frac{25*36}{9}=100$

Required number is 100.