# Numbers Questions

A) 6 | B) 7 |

C) 8 | D) 9 |

Explanation:

The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3

If the sum is 24, we need to solve the equation 3n + 3 = 24;

=> 3n = 21;

=> n = 7

The greatest of the three numbers is therefore 7 + 2 = 9

A) 553681 | B) 555181 |

C) 555681 | D) 556581 |

Explanation:

987 = 3 * 7 * 47.

So, the required number must be divisible by each one of 3, 7, 47

553681 => (Sum of digits = 28, not divisible by 3)

555181 => (Sum of digits = 25, not divisible by 3)

555681 is divisible by each one of 3, 7, 47.

A) 8 | B) 9 |

C) 10 | D) 11 |

Explanation:

Here a = 3 and r = 6/3 = 2. Let the number of terms be n.

Then, t = 384 => a * r^(n-1) = 384

=> 3 * 2^(n-1) = 384 => 2^(n-1) = 128 = 2^(7)

=> n-1 = 7 => n = 8.

A) 4 | B) 5 |

C) 6 | D) 7 |

Explanation:

132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also.

264 => 4,3,11(/)

396 => 4,3,11(/)

462 => 11,3

792 => 4,3,11(/)

968 => 11,4

2178 => 11,3

5184 => 3,4

6336 => 4,3,11(/)

Required number of numbers=4.