Q:

 What is the greatest of 3 consecutive integers whose sum is 24 ?

A) 6 B) 7
C) 8 D) 9
 
Answer & Explanation Answer: D) 9

Explanation:

The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3

If the sum is 24, we need to solve the equation 3n + 3 = 24;

=> 3n = 21;

=> n = 7

The greatest of the three numbers is therefore 7 + 2 = 9

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5 2767
Q:

A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in the answer both 98 are wrong and the other digits are correct , then the correct answer would be :

A) 553681 B) 555181
C) 555681 D) 556581
 
Answer & Explanation Answer: C) 555681

Explanation:

987 = 3 * 7 * 47.
So, the required number must be divisible by each one of 3, 7, 47
553681 => (Sum of digits = 28, not divisible by 3)
555181 => (Sum of digits = 25, not divisible by 3)
555681 is divisible by each one of 3, 7, 47.

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7 2725
Q:

How many terms are in the G.P. 3, 6, 12, 24, ......., 384 ?

A) 8 B) 9
C) 10 D) 11
 
Answer & Explanation Answer: A) 8

Explanation:

Here a = 3 and r = 6/3 = 2. Let the number of terms be n.
Then, t = 384 => a * r^(n-1) = 384
=> 3 * 2^(n-1) = 384 => 2^(n-1) = 128 = 2^(7)

=> n-1 = 7 => n = 8.

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5 2535
Q:

How many of the following numbers are divisible by 132?

264,396,462,792,968,2178,5184,6336

A) 4 B) 5
C) 6 D) 7
 
Answer & Explanation Answer: A) 4

Explanation:

132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also.
264   => 4,3,11(/)
396   => 4,3,11(/)
462   => 11,3
792   => 4,3,11(/)
968   => 11,4
2178 => 11,3
5184 => 3,4
6336 => 4,3,11(/)
Required number of numbers=4.

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7 2461
Q:

A number when divided by 779 gives a remainder 47. By dividing the same number by 19, what would be the remainder?

Answer

Number = ( 779 x a) + 47, where "a" is the quotient


           = (19 x 41 x a) + (19 x 2) + 9


           = 19 x (41a + 2) + 9


           = 19 x (New quotient) + 9


\inline \fn_jvn \therefore  Required remainder = 9

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5 2426