# Numbers Questions

Q:

The sum of the two numbers is 12 and their product is 35.What is the sum of the reciprocals of these numbers?

 A) 12/35 B) 1/35 C) 35/8 D) 7/32

Explanation:

Let a and b are the numbers.Then a+b is 12 and ab is 35.

$\inline \fn_cm \frac{a+b}{ab}=\frac{12}{35}$

$\inline \fn_cm \frac{1}{b}+\frac{1}{a}=\frac{12}{35}$

9 5201
Q:

On dividing 2272 as well as 875 by 3-digit number N,we get the same remainder.The sum of the digits of N is:

 A) 13 B) 12 C) 11 D) 10

Explanation:

(2272-875) = 1397, is exactly divisible by N.

Now , 1397 = 11 x 127

The required 3-digit number is 127,the sum of digits is 10.

11 4984
Q:

A number when divided by 779 gives a remainder 47. By dividing the same number by 19, what would be the remainder?

Number = ( 779 x a) + 47, where "a" is the quotient

= (19 x 41 x a) + (19 x 2) + 9

= 19 x (41a + 2) + 9

= 19 x (New quotient) + 9

$\inline&space;\fn_jvn&space;\therefore$  Required remainder = 9

4914
Q:

What is the greatest of 3 consecutive integers whose sum is 24 ?

 A) 6 B) 7 C) 8 D) 9

Explanation:

The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3

If the sum is 24, we need to solve the equation 3n + 3 = 24;

=> 3n = 21;

=> n = 7

The greatest of the three numbers is therefore 7 + 2 = 9

9 4865
Q:

If 60% of $\inline \frac{3}{5}$ of a number is 36, then the number is

 A) 86 B) 94 C) 100 D) 115

Explanation:

Let the number be x.Then

60% of ${\color{Black}&space;\frac{3}{5}}$of x=36.

${\color{Black}&space;\Rightarrow&space;}$${\color{Black}&space;\frac{60}{100}\times&space;\frac{3}{5}\times&space;x=36}$

${\color{Black}&space;\Rightarrow&space;x=100}$

Required number is 100.