Q:

A number when divided by 779 gives a remainder 47. By dividing the same number by 19, what would be the remainder?

Answer

Number = ( 779 x a) + 47, where "a" is the quotient


           = (19 x 41 x a) + (19 x 2) + 9


           = 19 x (41a + 2) + 9


           = 19 x (New quotient) + 9


\inline \fn_jvn \therefore  Required remainder = 9

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5 4219
Q:

Which one of the following cannot be the square of a natural number?

A) 32761 B) 42437
C) 81225 D) 20164
 
Answer & Explanation Answer: B) 42437

Explanation:

The square of a natural number never ends in 7.
42437 is not the square of a natural number

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5 4053
Q:

What smallest number should be added to 4456 so that the sum is completely divisible by 6 ?

A) 4 B) 3
C) 2 D) 1
 
Answer & Explanation Answer: C) 2

Explanation:

6)4456(742
42
--------
25
24
-------
16
12
-----
4
------
Required number = (6-4) = 2.

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3 3860
Q:

How many of the following numbers are divisible by 132?

264,396,462,792,968,2178,5184,6336

A) 4 B) 5
C) 6 D) 7
 
Answer & Explanation Answer: A) 4

Explanation:

132 = 4 x 3 x 11, So if the number is divisible by all three numbers 4,3 and 11,then the number is divisible by 132 also.
264   => 4,3,11(/)
396   => 4,3,11(/)
462   => 11,3
792   => 4,3,11(/)
968   => 11,4
2178 => 11,3
5184 => 3,4
6336 => 4,3,11(/)
Required number of numbers=4.

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9 3605
Q:

What smallest number of 6 digit is divisible by 111?

Answer

Smallest number of 6 digits is 100000


on dividing 100000 by 111 we get 100 as remainder 


\inline \fn_jvn \therefore Number to be added = (111 -100) = 11


\inline \fn_jvn \therefore Required Number  = 100011

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32 3591