Q:

What smallest number of 6 digit is divisible by 111?

Answer

Smallest number of 6 digits is 100000


on dividing 100000 by 111 we get 100 as remainder 


\inline \fn_jvn \therefore Number to be added = (111 -100) = 11


\inline \fn_jvn \therefore Required Number  = 100011

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31 2640
Q:

What smallest number should be added to 4456 so that the sum is completely divisible by 6 ?

A) 4 B) 3
C) 2 D) 1
 
Answer & Explanation Answer: C) 2

Explanation:

6)4456(742
42
--------
25
24
-------
16
12
-----
4
------
Required number = (6-4) = 2.

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3 2603
Q:

If V = 12R / (r + R) , then R =

A) Vr / (12 - V) B) Vr + (V /12 )
C) V D) V / (r - 12 )
 
Answer & Explanation Answer: A) Vr / (12 - V)

Explanation:

We have to rearrange the equation to make R the subject.

Start by cross multiplying by (r + R); V (r + R) = 12R

Multiply out the bracket Vr + VR = 12R

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1 2460
Q:

n is a whole number which when divided by 4 gives 3 as remainder. What will be the remainder when 2*n is divided by 4 ?

A) 3 B) 2
C) 1 D) 0
 
Answer & Explanation Answer: B) 2

Explanation:

Let n=4*q + 3. Then, 2*n = 8*q + 6 = 4(2*q + 1) + 2.
Thus when 2*n is divided by 4, the reminder is 2.

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2 2362
Q:

If the number 517?324 is completely divisible by 3,then the smallest whole number in place of ? will be:

A) 2 B) 1
C) 3 D) 7
 
Answer & Explanation Answer: A) 2

Explanation:

Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = ( 22 + x ),which must be divisible by 3.
Whe x=2. [(22 + 2) = 24 is divisible by 3] Answer is 2

 

 

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4 2355