AIEEE Questions

Q:

What was the day on 15th august 1947 ?

A) Friday B) Saturday
C) Sunday D) Thursday
 
Answer & Explanation Answer: A) Friday

Explanation:

15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)

Odd days in 1600 years = 0

Odd days in 300 years = 1

46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day

Jan.   Feb.   Mar.   Apr.   May.   Jun.   Jul.   Aug

( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 ) = 227 days = (32 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days.

Hence, as the number of odd days = 5 , given day is Friday.

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Q:

The diagonal of the floor of a rectangular closet is 7 feet. The shorter side of the closet is 4 feet. What is the area of the closet in square feet?

A) 9 B) 18
C) 27 D) 36
 
Answer & Explanation Answer: C) 27

Explanation:

Other side =  =  =  = 6 ft

 

 Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

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Q:

Two electric bulbs marked 25W – 220V and 100W – 220V are connected in series to a 440Vsupply. Which of the bulbs will fuse?

A) 25 W B) Both
C) 100 W D) Neither
 
Answer & Explanation Answer: A) 25 W

Explanation:

Resistances of both the bulbs are

R_{1}=\frac{V^{2}}{P_{1}}=\frac{220^{2}}{25}

R_{2}=\frac{V^{2}}{P_{2}}=\frac{220^{2}}{100}

Hence  R_{1}> R_{2}

When connected in series, the voltages divide in them in the ratio of their resistances. The voltage of 440 V devides in such a way that voltage across 25 w bulb will be more than 220 V. Hence 25 w bulb will fuse.

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Filed Under: Physics
Exam Prep: AIEEE

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Q:

There are three rooms in a Hotel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ?

A) 105 B) 7! x 6!
C) 7!/5! D) 420
 
Answer & Explanation Answer: A) 105

Explanation:

Choose 1 person for the single room & from the remaining choose 2 for the double room & from the remaining choose 4 people for the four person room,

Then, 7C1 x 6C2 x 4C4
     = 7 x  x 1
     = 7 x 15 = 105.
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Q:

Hydrogen atom is excited from ground state to another state with principal quantum number equal to 4. Then the number of spectral lines in the emission spectra will be

A) 2 B) 6
C) 5 D) 3
 
Answer & Explanation Answer: B) 6

Explanation:

Number of spectral lines from a state n to ground state is

                   =\frac{n(n-1)}{2}=6.

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Filed Under: Physics
Exam Prep: AIEEE

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