# AIEEE Questions

Q:

The diagonal of the floor of a rectangular closet is 7$\fn_jvn \frac{1}{2}$ feet. The shorter side of the closet is 4$\fn_jvn \frac{1}{2}$ feet. What is the area of the closet in square feet?

 A) 9 B) 18 C) 27 D) 36

Explanation:

Other side = $\inline \sqrt{\left ( \frac{15}{2} \right )^{2}-\left ( \frac{9}{2} \right )^{2}}$ = $\inline \sqrt{\frac{225}{4}-\frac{81}{4}}$ = $\inline \sqrt{\frac{144}{4}}$ = 6 ft

Area of closet = (6 x 4.5) sq. ft = 27 sq. ft.

0 3289
Q:

Two electric bulbs marked 25W – 220V and 100W – 220V are connected in series to a 440Vsupply. Which of the bulbs will fuse?

 A) 25 W B) Both C) 100 W D) Neither

Answer & Explanation Answer: A) 25 W

Explanation:

Resistances of both the bulbs are

$R_{1}=\frac{V^{2}}{P_{1}}=\frac{220^{2}}{25}$

$R_{2}=\frac{V^{2}}{P_{2}}=\frac{220^{2}}{100}$

Hence  $R_{1}>&space;R_{2}$

When connected in series, the voltages divide in them in the ratio of their resistances. The voltage of 440 V devides in such a way that voltage across 25 w bulb will be more than 220 V. Hence 25 w bulb will fuse.

Filed Under: Physics
Exam Prep: AIEEE

29 3029
Q:

There are three rooms in a Hotel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ?

 A) 105 B) 7! x 6! C) 7!/5! D) 420

Explanation:

Choose 1 person for the single room & from the remaining choose 2 for the double room & from the remaining choose 4 people for the four person room,

Then, 7C1 x 6C2 x 4C4
= 7 x $\inline \fn_jvn \small \frac{6x5}{2}$ x 1
= 7 x 15 = 105.

4 1285
Q:

Hydrogen atom is excited from ground state to another state with principal quantum number equal to 4. Then the number of spectral lines in the emission spectra will be

 A) 2 B) 6 C) 5 D) 3

Explanation:

Number of spectral lines from a state n to ground state is

$=\frac{n(n-1)}{2}=6.$

Filed Under: Physics
Exam Prep: AIEEE

6 1214
Q:

In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centre positions. If one atom of B is missing from one of the face centred points, the formula of the compound is

$\inline \dpi{100} \small 1.\: A_{2}B_{5}$

$\inline \dpi{100} \small 2.\: A_{2}B$

$\inline \dpi{100} \small 3.\: AB_{2}$

$\inline \dpi{100} \small 4.\: A_{2}B_{3}$

 A) Option 1 B) Option 2 C) Option 3 D) Option 4

Answer & Explanation Answer: A) Option 1

Explanation:

$\inline \dpi{100} \small Z_{A}=\frac{8}{8}\; \; Z_{B}=\frac{5}{2}$

So formula of compound is $\inline \dpi{100} \small AB_{\frac{5}{2}}$

i.e., $\inline \dpi{100} \small A_{2}B_{5}$