1
Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages? 

Answer:



Q:

Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ?

A) A is eldest & C is youngest B) D is eldest & C is youngest
C) C is eldest & A is youngest D) A is eldest & B is youngest
 
Answer & Explanation Answer: B) D is eldest & C is youngest

Explanation:

Given sum of present ages of A, B, C & D

A + B + C + D = 176

and also given that,

(A-4) : (B-4) : (C-4) : (D-4) = 11 : 9 : 6 : 14

Let the ratio = x

=> A-4 + B-4 + C-4 + D-4 = 11x + 9x + 6x + 14x

=> (A + B + C + D ) - 16 = 40x

=> 176 - 16 = 40x

=> x = 4

=> A = 44 + 4 = 48

=> B = 40

=> C = 28

=> D = 60

Therefore, from the above conclusions

D is eldest with 60 years and C is youngest with 28 years of ages.

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8 93
Q:

Sum of the ages of Rajesh, Suresh, Mahesh and Dinesh is 76 years. 7 years hence, their age ratio is 7:6:5:8. Find Mahesh’s present age ?

A) 17 years B) 13 years
C) 14 years D) 16 years
 
Answer & Explanation Answer: B) 13 years

Explanation:

Given R + S + M + D = 76

=> R+7 : S+7 : M+7 : D+7 = 7:6:5:8

=> Let the ratio = x

=> M+7 = 5x

=> M = 5x-7

=> R = 7x-7

=> S = 6x-7

=> D = 8x-7

=> R + S + M + D = 76

=> 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76

=> 26x - 28 = 76

=> 26x = 104

=> x = 4

=> Mahesh's present age = 5x-7 = 20 - 7 = 13 years.

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7 173
Q:

The age of Manisha and Sudeshna are in the ratio of 5 : 6 respectively. After 8 years the ratio  of their ages will be 7 : 8. What is the difference of their ages ?

A) 6 B) 4
C) 8 D) 10
 
Answer & Explanation Answer: B) 4

Explanation:

Let the age of Manisha and Sudeshna is 5x and 6x years respectively.

According to the given data,

5x+8/6x+8 = 7/8

42x + 56 = 40x + 64

x = 4

Required Difference of their ages = (6 × 4)  –  (5 × 4)

= 4 years.

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6 58
Q:

In a joint family, there are 24 members whose age is decreased by 4 months, when one girl aged 24 years is replaced by a new boy. Find the age of the new boy ?

A) 18 years B) 12 years
C) 15 years D) 16 years
 
Answer & Explanation Answer: D) 16 years

Explanation:

Age of new boy = (Age of moved girl) – (Number of family members × Decreased in average)

= 24 – 24×4/12

= 24 – 8

= 16 years.

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4 111
Q:

The average age of a couple and their son was 40 years, the son got married and a child was born just two years after their marriage. When child turned to 10 years, then the average age of the family becomes 38 years. What was the age of the daughter in law at the time of marriage ?

A) 12 years B) 10 years
C) 14 years D) 13 years
 
Answer & Explanation Answer: A) 12 years

Explanation:

Given the average age of couple and their son = 40

=> Sum of age (H +W +S) = 40×3

Let the age of daughter in law at the time of marriage = D years

Now after 10 years,

(H + S +W) + 3×12 + D +12 + 10 = 38×5

178 + D = 190

D = 190 -178 = 12 years

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6 177