# Problems on Ages Questions

Q:

A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 38 now, the son age 5 years back was :

 A) 14 B) 19 C) 33 D) 38

Explanation:

Let the son's present age be x years .Then, (38 - x) = x => x= 19.

Son's age 5 years back = (19 - 5) = 14 years

Filed Under: Problems on Ages

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Q:

In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is :

 A) 19 B) 29 C) 39 D) 49

Explanation:

Let B's present age = x years. Then, A's present age = (x + 9) years.
(x + 9) + 10 = 2(x - 10)

=> x + 19 = 2x - 20

=> x =39.

Filed Under: Problems on Ages

335 63938
Q:

The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A ?

 A) 12 B) 13 C) 14 D) 15

Explanation:

(A+B) - (B+C) = 12

$\inline \fn_jvn \Rightarrow$A - C = 12.

$\inline \fn_jvn \Rightarrow$C is younger than A by 12 years.

Filed Under: Problems on Ages

289 49871
Q:

What is the age of Teja?

A: Four years ago, Raju was as old as Teja is at present.

B: Sita’s present age is two times of Raju’s present age.

C: The average age of Teja and Sita is 19 years.

 A) Any two statements are sufficient to give answer B) Only C is sufficient C) All of three statements are necessary to give answer D) Even using all the three statements answer cannot be found

Explanation:

From the given statements A, B & C

Let the present age of Teja = P

Raju present age = P + 4

Sita's present age = 2(P + 4)

Average of ages of Sita & Teja = 19

=> (2P + 8 + P)/2 = 19

= 3P + 8 = 38

=> P = 30/3 = 10

Hence, the present age of Teja = P = 10 yrs.

Therefore, by using all the three statements A, B & C we can find the age of Teja.

Filed Under: Problems on Ages
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13 37973
Q:

The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.

As the ratio of their present ages is 3 : 4 , let their present ages be 3X and 4X.

So, 5 years ago, as the ratio of their ages was 5 : 7, we can write  (3x-5) : (4x-5) = 5 : 7. Solving, we get X = 10. Hence, their present ages are 3X = 30 and 4X = 40

Subject: Problems on Ages

37655
Q:

The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?

Let the son's age be x years and the father's age be 4x years

$\inline \Rightarrow (4x-5)=9(x-5)$

5x = 40

x = 8

$\inline&space;\therefore$ present age of the father = $\inline&space;4x$ = $\inline&space;4\times&space;8$ = 32 years

Subject: Problems on Ages

37033
Q:

The sum of the present ages of a father and his son is 60 years. five years ago, father's age was four times the age of the son. so now the son's age will be:

 A) 5 B) 10 C) 15 D) 20

Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 5= 4(x - 5)

55 - x = 4x - 20

5x = 75  => x = 15

Filed Under: Problems on Ages

144 35518
Q:

The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new students is?

Total age of 10 students = 150 years

Total age of 15 students = 240 years

Total age of 5 new students = 240 - 150 = 90 years

$\inline&space;\therefore$ Average age of 5 new students = $\inline \frac{90}{5}$ = 18 years