Suppose age of each women be W and average age of 12 men be x

Hence , each woman's age = 24 years

A) A is eldest & C is youngest | B) D is eldest & C is youngest |

C) C is eldest & A is youngest | D) A is eldest & B is youngest |

Explanation:

Given sum of present ages of A, B, C & D

A + B + C + D = 176

and also given that,

(A-4) : (B-4) : (C-4) : (D-4) = 11 : 9 : 6 : 14

Let the ratio = x

=> A-4 + B-4 + C-4 + D-4 = 11x + 9x + 6x + 14x

=> (A + B + C + D ) - 16 = 40x

=> 176 - 16 = 40x

=> x = 4

=> A = 44 + 4 = 48

=> B = 40

=> C = 28

=> D = 60

Therefore, from the above conclusions

**D is eldest with 60 years and C is youngest with 28 years of ages.**

A) 17 years | B) 13 years |

C) 14 years | D) 16 years |

Explanation:

Given R + S + M + D = 76

=> R+7 : S+7 : M+7 : D+7 = 7:6:5:8

=> Let the ratio = x

=> M+7 = 5x

=> M = 5x-7

=> R = 7x-7

=> S = 6x-7

=> D = 8x-7

=> R + S + M + D = 76

=> 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76

=> 26x - 28 = 76

=> 26x = 104

=> x = 4

=> Mahesh's present age = 5x-7 = 20 - 7 = **13 years**.

A) 6 | B) 4 |

C) 8 | D) 10 |

Explanation:

Let the age of Manisha and Sudeshna is 5x and 6x years respectively.

According to the given data,

5x+8/6x+8 = 7/8

42x + 56 = 40x + 64

x = 4

Required Difference of their ages = (6 × 4) – (5 × 4)

= 4 years.

A) 18 years | B) 12 years |

C) 15 years | D) 16 years |

Explanation:

Age of new boy = (Age of moved girl) – (Number of family members × Decreased in average)

= 24 – 24×4/12

= 24 – 8

= 16 years.

A) 12 years | B) 10 years |

C) 14 years | D) 13 years |

Explanation:

Given the average age of couple and their son = 40

=> Sum of age (H +W +S) = 40×3

Let the age of daughter in law at the time of marriage = D years

Now after 10 years,

(H + S +W) + 3×12 + D +12 + 10 = 38×5

178 + D = 190

D = 190 -178 = 12 years