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Q:

# The average of ages of threee persons is 60 years . Those ages are in the proportion of 1:2:3. what is the age of the youngest one among them?

Q:

Present ages of Deepa and Hyma are in the ratio of 5:6 respectively. After four years, this ratio becomes 6: 7. What is the difference between their present ages?

 A) 6 yrs B) 4 yrs C) 8 yrs D) 2 yrs

Explanation:

Let the present age of Deepa = 5p

Let the present age of Hyma = 6p

After four years their ratio = 6 : 7

=>

=> 35p + 28 = 36p + 24

=> p = 4

Therefore, the difference between their ages = 24 - 20 = 4 years.

2 29
Q:

The ratio between present ages of Renuka and Sony is 5 : 4 . 4 years ago, Sony's age was 24 years. What will be Renuka's age after 5 years ?

 A) 25 B) 30 C) 35 D) 40

Explanation:

Present age of Sony = 24 + 4 = 28 years

After 5 years Renuka's age = 7×5 + 5 = 40 years

5 50
Q:

Hari Ram’s present age is three times his son’s present age and two fifth of his father’s present age. The average of the present age of all of them is 46 years. What is the difference between Hari Ram’s son’s present age and Hari Ram’s father’s present age?

 A) 44 yrs B) 56 yrs C) 67 yrs D) 78 yrs

Explanation:

Let Hari Ram's present age = x

Then, his son's age = x/3

Father's age = 5x/2

Now the required difference =

5 112
Q:

Sweety is 54 years old and her mother is 80. How many years ago was Sweety's mother three times her age?

 A) 20 B) 41 C) 26 D) 33

Explanation:

Given P = 54 and M = 80

According to the question,

Let ‘A’ years ago, M = 3P

=> M - A/P - A = 3

=> 80 - A = 3(54 - A)

=> 80 - A = 162 - 3A

=> 2A = 82

=> A = 41

Therefore, A = 41 years ago Sweety’s mother was 3 times of Sweety’s age.

Hence, at the age S = 13 and M = 39.

6 220
Q:

7 years ago, the ratio of the ages of Anirudh to that of Bhavana, was 7:9. Chandhu is 12 years older than Anirudh and 12 years younger than Bhavana. What is Chandhu's present age?

 A) 91 years B) 115 years C) 103 years D) Can't be determined

Explanation:

Let present Anirudh's age be 'A' and Bhavana's age be 'B'

Given seven years, their ratio is 7:9

=> A-7 : B-7 = 7 : 9

=> 9A - 7B = 14 .......(1)

And given,

Chandhu is 12 years older than A nad 12 years younger than B

=> C = A + 12....(2)

=> B = C + 12

=> B = A + 12 + 12 .....(From (2))

=> B = A + 24 ....(3)

Put (3) in (1)

9A - 7(A+24) = 14

9A - 7A - 168 = 14

2A = 182

=> A = 91 years

=> C = A + 12 = 91 +12 = 103 years.

7 272
Q:

The average age of A and B, 2 years ago was 26. If the age of A, 5 years hence is 40 yrs, and B is 5 years younger to C, then find the difference between the age of A and C?

 A) 11 yrs B) 9 yrs C) 7 yrs D) 13 yrs

Explanation:

Let the present ages of A and B be 'x' and 'y' respectively

From the given data,

[(x-2) + (y-2)]/2 = 26

=> x+y = 56

But given the age of A, 5 years hence is 40 yrs => present age of A = 40 - 5 = 35 yrs

=> x = 35 => y = 56 - 35 = 21

=> Age of B = 21 yrs

Given B is 5 years younger to C,

=> Age of C = 21 + 5 = 26 yrs

=> Required Difference between ages of A and C = 35 - 26 = 9 yrs.

5 297
Q:

The average age of husband, wife and their child 3 years ago was 24 years and that of wife and child 5 years ago was 25 years. The present age of the husband is:

 A) 21 yrs B) 27 yrs C) 29 yrs D) 31 yrs

Explanation:

Sum of ages of husband, wife and child= (24 × 3) + 9 = 81 years

Sum of ages of wife and child => 25 × 2 + 10 = 50 + 10 = 60 years

Age of husband = 81 - 60 = 21 years.

5 222
Q:

Four person A, B, C and D. The sum of their present age is 176. Four years ago ratio of their age was 11: 9 : 6 : 14, then find who is eldest and youngest among them ?

 A) A is eldest & C is youngest B) D is eldest & C is youngest C) C is eldest & A is youngest D) A is eldest & B is youngest

Answer & Explanation Answer: B) D is eldest & C is youngest

Explanation:

Given sum of present ages of A, B, C & D

A + B + C + D = 176

and also given that,

(A-4) : (B-4) : (C-4) : (D-4) = 11 : 9 : 6 : 14

Let the ratio = x

=> A-4 + B-4 + C-4 + D-4 = 11x + 9x + 6x + 14x

=> (A + B + C + D ) - 16 = 40x

=> 176 - 16 = 40x

=> x = 4

=> A = 44 + 4 = 48

=> B = 40

=> C = 28

=> D = 60

Therefore, from the above conclusions

D is eldest with 60 years and C is youngest with 28 years of ages.