Free Practice Questions for Competitive Exams, Interviews, Certifications

Q:

Arrange the words given below in a meaningful sequence.

1.Presentation 2.Recommendation 3. Arrival 4.Discussion 5.Introduction

A) 5, 3, 4, 1, 2	B) 3, 5, 4, 2, 1
C) 3, 5, 1, 4, 2	D) 5, 3, 1, 2, 4

Answer & Explanation Answer: C) 3, 5, 1, 4, 2

Explanation:

The correct order is :

Arrival Introduction Presentation Discussion Recommendation

3 5 1 4 2

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Filed Under: Logical Sequence of Words - Verbal Reasoning - Mental Ability

2335 360698

Q:

What was the day on 15th august 1947 ?

A) Friday	B) Saturday
C) Sunday	D) Thursday

Answer & Explanation Answer: A) Friday

Explanation:

15 Aug, 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947)

15th_August_1947_day1534219857.jpg image

Odd days in 1600 years = 0

Odd days in 300 years = 1

46 years = (35 ordinary years + 11 leap years) = (35 x 1 + 11 x 2)= 57 (8 weeks + 1 day) = 1 odd day

Jan. Feb. Mar. Apr. May. Jun. Jul. Aug

( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 ) = 227 days = (32 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 1 + 1 + 3) = 5 odd days.

Hence, as the number of odd days = 5 , given day is Friday.

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Filed Under: Calendar - Quantitative Aptitude - Arithmetic Ability
Exam Prep: CAT , Bank Exams , AIEEE , GATE
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2948 340217

Q:

Today is Monday. After 61 days, it will be :

A) Tuesday	B) Monday
C) Sunday	D) Saturday

Answer & Explanation Answer: D) Saturday

Explanation:

Each day of the week is repeated after 7 days. So, after 63 days, it will be Monday.

After 61 days, it will be Saturday.

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Filed Under: Calendar - Quantitative Aptitude - Arithmetic Ability
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

1885 214174

Q:

In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was :

A) 2500	B) 2700
C) 2900	D) 3100

Answer & Explanation Answer: B) 2700

Explanation:

Total number of votes = 7500

Given that 20% of Percentage votes were invalid

=> Valid votes = 80%

Total valid votes = 7500*(80/100)

1st candidate got 55% of the total valid votes.

Hence the 2nd candidate should have got 45% of the total valid votes

=> Valid votes that 2nd candidate got = total valid votes x (45/100)

7500*(80/100)*(45/100) = 2700

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Filed Under: Percentage - Quantitative Aptitude - Arithmetic Ability

1706 196558

Q:

A bag contains 50 P, 25 P and 10 P coins in the ratio 5: 9: 4, amounting to Rs. 206. Find the number of coins of each type respectively.

A) 360, 160, 200	B) 160, 360, 200
C) 200, 360,160	D) 200,160,300

Answer & Explanation Answer: C) 200, 360,160

Explanation:

let ratio be x.

Hence no. of coins be 5x ,9x , 4x respectively

Now given total amount = Rs.206

=> (.50)(5x) + (.25)(9x) + (.10)(4x) = 206

we get x = 40

=> No. of 50p coins = 200

=> No. of 25p coins = 360

=> No. of 10p coins = 160

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Filed Under: Ratios and Proportions - Quantitative Aptitude - Arithmetic Ability

1399 179617

Q:

A and B invest in a business in the ratio 3 : 2. If 5% of the total profit goes to charity and A's share is Rs. 855, the total profit is :

A) 500	B) 1000
C) 1500	D) 2000

Answer & Explanation Answer: C) 1500

Explanation:

Let the total profit be Rs. 100.

After paying to charity, A's share = (95*3/5) = Rs. 57.

If A's share is Rs. 57, total profit = Rs. 100.

If A's share is Rs. 855, total profit = (100/57*855) = 1500.

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Filed Under: Partnership - Quantitative Aptitude - Arithmetic Ability

389 134197

Q:

Crack the code & Unlock the Key ?

A) 062	B) 602
C) 042	D) 204

Answer & Explanation Answer: C) 042

Explanation:

From all the hints given,

only 042 satisfies and it unlocks the key.

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Filed Under: Number Puzzles
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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591 125681

Q:

A problem is given to three students whose chances of solving it are 1/2, 1/3 and 1/4 respectively. What is the probability that the problem will be solved?

A) 1/4	B) 1/2
C) 3/4	D) 7/12

Answer & Explanation Answer: C) 3/4

Explanation:

Let A, B, C be the respective events of solving the problem and $A, B, C$ be the respective events of not solving the problem. Then A, B, C are independent event

$∴ A, B, C$ are independent events

Now, P(A) = 1/2 , P(B) = 1/3 and P(C)=1/4

$P (A) = \frac{1}{2}, P (B) = \frac{2}{3}, P (C) = \frac{3}{4}$

$∴$ P( none solves the problem) = P(not A) and (not B) and (not C)

= $P (A \cap B \cap C)$

= $P (A) P (B) P (C)$ $[∵ A, B, C a r e I n d e p e n d e n t]$

= $\frac{1}{2} \times \frac{2}{3} \times \frac{3}{4}$

= $\frac{1}{4}$

Hence, P(the problem will be solved) = 1 - P(none solves the problem)

= $1 - \frac{1}{4}$ = 3/4

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Filed Under: Probability - Quantitative Aptitude - Arithmetic Ability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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568 118805

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