6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ?

A) 42.2 mts	B) 33.45 mts
C) 66.6 mts	D) 58.78 mts

Answer & Explanation Answer: C) 66.6 mts

Explanation:

ht1488353450.jpg image

From above diagram
AC represents the hill and DE represents the tower

Given that AC = 100 m

angleXAD = angleADB = 30° (∵ AX || BD )
angleXAE = angleAEC = 60° (∵ AX || CE)

Let DE = h

Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE

tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1)

tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)
∵ BD = CE and Substitute the value of CE from equation 1
100/√3 = 100−h(√3) => h = 66.66 mts

The height of the tower = 66.66 mts.

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Filed Under: Height and Distance
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17 6967

Q:

There are 600 Kabaddi players 4% wear knee band on one leg. Of the remaining, 25% wear knee bands on both legs. How many players don't wear a knee band ?

A) 426	B) 428
C) 415	D) 432

Answer & Explanation Answer: D) 432

Explanation:

There are 600 Kabaddi players
4% wear knee band on one leg
Remaining players = 600 x 0.96 = 576
Of the remaining, 25% wear knee bands on both leg
and Of the remaining, 75% do not wear knee bands .
So players not wearing knee bands = 0.75 x 576 = 576 x 3/4 = 144 x 3 = 432.

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Filed Under: Percentage
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5 6961

Q:

How much does a clock lose per day, if its hands coincide ever 65 minutes ?

A) 1440/143 min	B) 184/13 min
C) 1425/18 min	D) 541/9 min

Answer & Explanation Answer: C) 1425/18 min

Explanation:

55 min. spaces are covered in 60 min.
60 min. spaces are covered in ((60/55) x 60) min = 720/11 min.
Loss in 65 min. = (720/11 - 65 ) = 5/11
Loss in 24 hrs = (5/11 x 1/65 x 24 x 60)min = 1440/143 min.

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Filed Under: Calendar
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21 6954

Q:

A sales boy is allowed $4 \frac{1}{2}$ % discount on the total sales made by him plus a bonus of $\frac{1}{4}$ % on the sales over Rs.12,000.If his total earnings were Rs.2400, then his total sales(in Rs.) are ?

A) Rs.60,145.23	B) Rs.54,285.54
C) Rs.52,147.85	D) Rs.50,589.47

Answer & Explanation Answer: D) Rs.50,589.47

Explanation:

Let the total earnings be Rs.x

Then $4 \frac{1}{2}$ % of x + $\frac{1}{4}$ % of (x-12000) =2400

$\Rightarrow \frac{9}{2} \times \frac{x}{100} + \frac{1}{4} \times \frac{x - 12000}{100} = 2400$

=> x=50,589.47

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Filed Under: Percentage
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8 6946

Q:

A school has scheduled three volleyball games, two soccer games, and four basketball games. You have a ticket allowing you to attend three of the games. In how many ways can you go to two basketball games and one of the other events?

A) 25	B) 30
C) 50	D) 75

Answer & Explanation Answer: B) 30

Explanation:

Since order does not matter it is a combination.

The word AND means multiply.

Given 4 basketball, 3 volleyball, 2 soccer.

We want 2 basketball games and 1 other event. There are 5 choices left.

C(n,r)

C(How many do you have, How many do you want)

C(have 4 basketball, want 2 basketball) x C(have 5 choices left, want 1)

C(4,2) x C(5,1) = (6)(5) = 30

Therefore there are 30 different ways in which you can go to two basketball games and one of the other events.

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Filed Under: Permutations and Combinations

1 6937

Q:

A sum of Rs. 4,300 is distributed among M, N and O, such that M receives 25% more than N and N receives 25% less than O. What is O’s share in the amount?

A) 1564	B) 1600
C) 1632	D) 1714

Answer & Explanation Answer: B) 1600

Explanation:

Let O's share = Rs. P

=> N's share = $\frac{75}{100} x P = \frac{3 P}{4}$

M's share = $\frac{5}{4} x \frac{3 P}{4} = \frac{15 P}{16}$

$\frac{15 P}{16} + \frac{3 P}{4} + P = 4300 = > P = 4300 x \frac{16}{43} = 1600$

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Filed Under: Partnership
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14 6925

Q:

A 260 m long train running at the speed of 120 km/hr crosses another train running in opposite direction at the speed of 80 km/hr in 9 sec. What is the length of the other train ?

A) 240 mts	B) 270 mts
C) 260 mts	D) 250 mts

Answer & Explanation Answer: A) 240 mts

Explanation:

Relative speed = 120 + 80 = 200 km/hr.
= 200 x 5/18 = 500/9 m/sec.

Let the length of the other train be L mts.
Then, (L + 260)/9 = 500/9 => L = 240 mts.

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Filed Under: Problems on Trains
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3 6917

Q:

A shopkeeper sells two articles at Rs.1000 each, making a profit of 20% on the first article and a loss of 20% on the second article. Find the net profit or loss that he makes?

A) 2%	B) 4%
C) 3%	D) 2.5%

Answer & Explanation Answer: B) 4%

Explanation:

SP of first article = 1000

Profit = 20%

CP = $\frac{100}{100 + P} \times S P$ = 5000/6 = 2500/3

SP of second article = 1000

Loss = 20%

CP = $\frac{100}{100 - L} \times S P$ = 5000/4 = 1250

Total SP = 2000

Total CP = $\frac{2500}{3}$ + 1250 = 6250/3

CP is more than SP, he makes a loss.

Loss = CP-SP = (6250/3)- 2000 = 250/3

Loss Percent = $\frac{\frac{250}{3}}{\frac{6250}{3}} \times 100$ = 4%

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Filed Under: Profit and Loss
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5 6910

Quantitative Aptitude - Arithmetic Ability Questions

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