129+ Problems on Ages with Solutions and Explanation

Q:

If Reena’s age was twice of her present age, when subtracted from four times three years from hence, with three times the three years before her present age. What will be her age after one year ?

A) 22 yrs	B) 21 yrs
C) 20 yrs	D) 24 yrs

Answer & Explanation Answer: A) 22 yrs

Explanation:

Let Reena’s present age be 'K' yrs.
Given:{(K+3) x 4} - {(K-3) x 3)}
=> K = 21 yrs
So her present age is 21 yrs.
Then, her age after 1 year is 22 yrs.

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Q:

The average of the ages of Sumit, Krishna and Rishabh is 43 years and the average of the ages of Sumit, Rishabh and Rohit is 49 years. If Rohit is 54 years old, what is Krishna'a age ?

A) 48 yrs	B) 42 yrs
C) 40 yrs	D) 36 yrs

Answer & Explanation Answer: D) 36 yrs

Explanation:

Let present ages of Sumit=w, Krishna=x, Rishabh=y and Rohit=z , then
w+x+y = 43x3 = 129 ---(i) and
w+y+z = 49x3 = 147 ---(ii)
Subtracting (i) from (ii), (w+y+z) - (w+x+y)=147 -129 , z- x =18 ---(iii)
Given Rohit's age => z = 54, so from (iii), x = 54-18 = 36

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Q:

Tom's father is thrice as old as Tom. 10 years ago Tom's father's age was 7 times his age. What is Tom's current age?

A) 17 years	B) 16 years
C) 15 years	D) 14 years

Answer & Explanation Answer: D) 14 years

Explanation:

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Q:

The average age of a couple and their son was 40 years, the son got married and a child was born just two years after their marriage. When child turned to 10 years, then the average age of the family becomes 38 years. What was the age of the daughter in law at the time of marriage ?

A) 12 years	B) 10 years
C) 14 years	D) 13 years

Answer & Explanation Answer: A) 12 years

Explanation:

Given the average age of couple and their son = 40

=> Sum of age (H +W +S) = 40×3

Let the age of daughter in law at the time of marriage = D years

Now after 10 years,

(H + S +W) + 3×12 + D +12 + 10 = 38×5

178 + D = 190

D = 190 -178 = 12 years

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Q:

The ratio of present ages of X and Y is 4:5. Which of the following can't be the ratio of ages of X and Y, 20 years ago ?

A) 2 : 5	B) 8 : 15
C) 9 : 10	D) 3 : 5

Answer & Explanation Answer: C) 9 : 10

Explanation:

The ratio of X and Y ages at present is 4:5.

Then, the ratio 20 years ago will not be more than the ratio at present.

So, from the options 9:10 is not satifying => its ratio is 0.9 which is greater than presnt ratio of 0.8.

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Q:

Sweety is 54 years old and her mother is 80. How many years ago was Sweety's mother three times her age?

A) 20	B) 41
C) 26	D) 33

Answer & Explanation Answer: B) 41

Explanation:

Given P = 54 and M = 80

According to the question,

Let ‘A’ years ago, M = 3P

=> M - A/P - A = 3

=> 80 - A = 3(54 - A)

=> 80 - A = 162 - 3A

=> 2A = 82

=> A = 41

Therefore, A = 41 years ago Sweety’s mother was 3 times of Sweety’s age.

Hence, at the age S = 13 and M = 39.

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Q:

Jeremy is 26 years younger than his father. Eight years hence his father's age will be two years less than twice his age. What is Jeremy's present age?

A) 20 years	B) 18 years
C) 24 years	D) 22 years

Answer & Explanation Answer: A) 20 years

Explanation:

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Q:

Satheesh is two years older than Goutham who is twice as old as Sai. If the total of the ages of Satheesh, Goutham and Sai is 27, then how old is Goutham?

A) 12	B) 10
C) 11	D) 13

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