# Problems on Ages Questions

Q:

A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 38 now, the son age 5 years back was :

 A) 14 B) 19 C) 33 D) 38

Explanation:

Let the son's present age be x years .Then, (38 - x) = x => x= 19.

Son's age 5 years back = (19 - 5) = 14 years

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Q:

In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is :

 A) 19 B) 29 C) 39 D) 49

Explanation:

Let B's present age = x years. Then, A's present age = (x + 9) years.
(x + 9) + 10 = 2(x - 10)

=> x + 19 = 2x - 20

=> x =39.

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Q:

The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A ?

 A) 12 B) 13 C) 14 D) 15

Explanation:

(A+B) - (B+C) = 12

$\inline \fn_jvn \Rightarrow$A - C = 12.

$\inline \fn_jvn \Rightarrow$C is younger than A by 12 years.

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Q:

The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?

Let the son's age be x years and the father's age be 4x years

$\inline \Rightarrow (4x-5)=9(x-5)$

5x = 40

x = 8

$\inline&space;\therefore$ present age of the father = $\inline&space;4x$ = $\inline&space;4\times&space;8$ = 32 years

36565
Q:

The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.

As the ratio of their present ages is 3 : 4 , let their present ages be 3X and 4X.

So, 5 years ago, as the ratio of their ages was 5 : 7, we can write  (3x-5) : (4x-5) = 5 : 7. Solving, we get X = 10. Hence, their present ages are 3X = 30 and 4X = 40

36135
Q:

The sum of the present ages of a father and his son is 60 years. five years ago, father's age was four times the age of the son. so now the son's age will be:

 A) 5 B) 10 C) 15 D) 20

Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 5= 4(x - 5)

55 - x = 4x - 20

5x = 75  => x = 15

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Q:

The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new students is?

Total age of 10 students = 150 years

Total age of 15 students = 240 years

Total age of 5 new students = 240 - 150 = 90 years

$\inline&space;\therefore$ Average age of 5 new students = $\inline \frac{90}{5}$ = 18 years

28036
Q:

Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of rajeev?

 A) 12 B) 14 C) 22 D) 10

Explanation:

Let Rajeev's present age be  x years.

Rajeev's age after 15 years = (x + 15) years.

Rajeev's age 5 years back = (x - 5) years

Then ATQ,

x + 15 = 5 (x - 5)

x + 15 = 5x - 25

=> x = 10

Hence, Rajeev's present age = x = 10 years.