# Problems on Ages Questions

Q:

A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 38 now, the son age 5 years back was :

 A) 14 B) 19 C) 33 D) 38

Explanation:

Let the son's present age be x years .Then, (38 - x) = x => x= 19.

Son's age 5 years back = (19 - 5) = 14 years

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Q:

The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A ?

 A) 12 B) 13 C) 14 D) 15

Explanation:

(A+B) - (B+C) = 12

$\inline \fn_jvn \Rightarrow$A - C = 12.

$\inline \fn_jvn \Rightarrow$C is younger than A by 12 years.

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Q:

In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is :

 A) 19 B) 29 C) 39 D) 49

Explanation:

Let B's present age = x years. Then, A's present age = (x + 9) years.
(x + 9) + 10 = 2(x - 10)

=> x + 19 = 2x - 20

=> x =39.

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Q:

The sum of the present ages of a father and his son is 60 years. five years ago, father's age was four times the age of the son. so now the son's age will be:

 A) 5 B) 10 C) 15 D) 20

Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 5= 4(x - 5)

55 - x = 4x - 20

5x = 75  => x = 15

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Q:

The age of a man is 4 times of his son. Five years ago, the man was nine times old as his son was at that time. The present age of man is?

Let the son's age be x years and the father's age be 4x years

$\inline \Rightarrow (4x-5)=9(x-5)$

5x = 40

x = 8

$\inline&space;\therefore$ present age of the father = $\inline&space;4x$ = $\inline&space;4\times&space;8$ = 32 years

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Q:

The ratio of the present ages of P and Q is 3 : 4. Five years ago, the ratio of their ages was 5 : 7. Find their present ages.

As the ratio of their present ages is 3 : 4 , let their present ages be 3X and 4X.

So, 5 years ago, as the ratio of their ages was 5 : 7, we can write  (3x-5) : (4x-5) = 5 : 7. Solving, we get X = 10. Hence, their present ages are 3X = 30 and 4X = 40

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Q:

The ratio of the father's age to the son's age is 3 : 1. The product of their ages is 147. The ratio of their ages after 5 years will be?

Let father's age be 3x and son's age be x years

$\inline \fn_cm \Rightarrow 3x\times x=147$

$\inline \fn_cm \Rightarrow x^{2}=49\Rightarrow x=7$

Father's age after 5 years = 3x + 5 = 26 years

Son's age after 5 years = x + 5 = 12 years

$\inline \fn_cm \therefore$ Ratio of father's and son's ages = 26 : 12 = 13 : 6

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Q:

Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?

 A) 11/P + 6 B) P/11 +6 C) 17 - P/6 D) 17/P

Explanation:

Let Ben’s age now be B

Anita’s age now is A.

(A - 6) = P(B - 6)

But A is 17 and therefore 11 = P(B - 6)

11/P = B-6

(11/P) + 6 = B