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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Select the related letters from the given alternatives.

 

IJK : RQP :: TUV : ?

 

A) CDE B) YZZ
C) GFE D) DCB
 
Answer & Explanation Answer: C) GFE

Explanation:
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Filed Under: Analogy
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1 47525
Q:

Statements followed by some conclusions are given below.

 

Statements :

 

1. Some football players are cricketers.

2. All hockey players love football though some are cricketers.

 

Conclusions :

 

I. Some hockey players who are cricketers play football too.

II. There is at the most one cricketer who plays football and hockey.

 

Find which of the given conclusions logically follows from the given statements.

 

A) Only conclusion I follows B) Only conclusion II follows
C) Both I and II follow D) Neither I nor II follows
 
Answer & Explanation Answer: D) Neither I nor II follows

Explanation:
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Filed Under: Statement and Conclusions
Exam Prep: Bank Exams

6 47447
Q:

A can contains a mixture of two liquids A and B in the ratio  7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?

A) 10 B) 20
C) 21 D) 25
 
Answer & Explanation Answer: C) 21

Explanation:

Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively

 

Quantity of A in mixture left =7x-712×9=7x-214 litres.

 

Quantity of B in mixture left =  5x-512×9=5x-154litres.

 

7x-2145x-154+9=79

 

⇒28x-2120x+21=79

 

⇒x=3

 So, the can contained 21 litres of A.

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Filed Under: Alligation or Mixture

272 47440
Q:

Which of the following terms follows the trend of the given list?

 

XXXXXXY, XXXXXYY, XXXXYYY, XXXYYYY, XXYYYYY, _______________.

 

A) XXXXXXX   B) XXXXXXY  
C) XYYYYYY   D) XXXXXYY
 
Answer & Explanation Answer: C) XYYYYYY  

Explanation:
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Filed Under: Alphabet Test
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Q:

Select the related word/letters/number from the given alternatives.

CGK : DHL : : UYC : ?

A) VZD B) WZD
C) WZA D) VAE
 
Answer & Explanation Answer: A) VZD

Explanation:
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Filed Under: Analogy
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Q:

A parallelogram has sides 30m and 14m and one of its diagonals is 40m long. Then its area is

A) 136 B) 236
C) 336 D) 436
 
Answer & Explanation Answer: C) 336

Explanation:

let ABCD be the given parallelogram 

area of parallelogram ABCD = 2 x (area of triangle ABC) 

now a = 30m, b = 14m and c = 40m

 s=1/2 x (30+14+40) = 42 

 

Area of triangle ABC = ss-as-bs-c  

 

= 4212282= 168sq m 

area of parallelogram ABCD = 2 x 168 = 336 sq m

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Filed Under: Area
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103 47260
Q:

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A) 20% B) 30%
C) 40% D) 50%
 
Answer & Explanation Answer: D) 50%

Explanation:

Let original length = x and original breadth = y.

Original area = xy. 

New length = x/2 and New breadth=3y 

New area = 32xy 

Therefore,  Increase in area = New area-original area = 32xy-xy=12xy 

 

Therefore,  Increase % = increase in area original area*100=12xyxy*100=50 %

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Filed Under: Area
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47 47243
Q:

A dice is numbered from 1 to 6 in different ways.

If 1 is adjacent to 2, 3 and 5, then which of the following statements is necessarily true?

A) 4 is adjacent to 6 B) 2 is adjacent to 5
C) 1 is adjacent to 6 D) 1 is adjacent to 4
 
Answer & Explanation Answer: A) 4 is adjacent to 6

Explanation:

If 1 is adjacent to 2, 3 and 5, then either 4 or 6 lies opposite to 1. So, the numbers 4 and 6 cannot lie opposite to each other. Hence, 4 necessarily lies adjacent to 6.

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Filed Under: Cubes and Dice

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