Quantitative Aptitude - Arithmetic Ability Questions

Given the three mixtures ratio as (1:2),(2:3),(3:4)

(1+2),(2+3),(3+4)

Total content = 3,5,7

Given equal quantities of the three mixtures are mixed, then LCM of 3, 5, 7 = 105

105/3 = 35 , 105/5 = 21 , 105/7 = 15

Now, the individual equal quantity ratios are (35x1, 35x2), (21x2, 21x3), (15x3, 15x4)

 i.e (35,70), (42,63), (45,60)

So overall mixture ratio of milk and water is

35+42+45 : 70+63+60

122:193

But in the question asked the ratio of water to milk = 193 : 122

Let the two consecutive odd integers be (2x + 1) and (2x + 3)

Then,

(2x + 3)² - (2x + 1)²

= (2x + 3 + 2x + 1) (2x + 3 - 2x - 1)

= (4x + 4)(2)
= 8 (x + 1), which is always divisible by 8

The largest 4 digit number is = 9999
After dividing 9999 with 88, we get 55 as remainder
so largest 4 digit number divisible by 88 = 9999-55 = 9944.

B runs 45/2mts in 6 sec

B covers 300m in (6*2/45*300)sec =80 sec

Less Cogs  more turns and less time  less turns

$$\begin{gathered} Cogs Time Turns \\ A 54 45 80 \\ B 32 8 ? \end{gathered}$$

Number of turns required=80 × 54/32 × 8/45  = 24 times

Ans. 
5 = 3 + (13 + 1)
15 = 5 + (23 + 2)
45 = 15 + (33 + 3)
113 = 45 + (43 + 4)
? = 113 + (53 + 5), i.e. ? = 243

At 3 o'clock, the minute hand is 15 min. spaces apart from the hour hand. 

 To be coincident, it must gain 15 min. spaces. 

 55 min. are gained in 60 min.

  Then 15 min spaces are gained in  = 6055×15 min. 

Therefore,  The hands are coincident at  16411 min. past 3 o'clock.