Quantitative Aptitude - Arithmetic Ability Questions

Total Items = 7
Discounted = 1
Percentage = 1/7 x 100
= 14.285%

Ratio of shares of A,B,C = (24 x 4) : (10 x 6) : (56 x 5)

                                    = 96 : 60 : 280.

Let total rent be Rs. x. Then, A's share = Rs.96x436

 ∴96x436=960 ⇔x=960×43696=4360

Hence total rent of the field is Rs. 4360.

Relative speed = (72 - 36) x 5/18 = 2 x 5 = 10 mps.
Distance covered in 32 sec = 32 x 10 = 320 m.

The length of the faster train = 320 m.

Distance d = 1200km
let S be the speed

he walks 15 hours a day(i.e 24 - 9)
so totally he walks for 70 x 15 = 1050hrs.

S = 1200/1050 => 120/105 = 24/21 => 8/7kmph

given 1 1/2 of previous speed
so 3/2 * 8/7= 24/14 = 12/7

New speed = 12/7kmph

Now he rests 10 hrs a day that means he walks 14 hrs a day.

time = 840 x 7 /12 => 490 hrs
=> 490/14 = 35 days

So he will take 35 days to cover 840 km.

Let the son's present age be x years. Then, man's present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22

By hit and trail, we find that

47619 x 7 = 333333.

7) 333333 (47619
    333333
----------------
        0

And 476190476 x 7 = 3333333333 but smallest number is 47619.

x128 = 162x

Then x² = 162x128

   = Sqrt of 8² x 6² x 3²

   = 8 x 6 x 3

   x²  = 144.

 x  = 12.

Given that SP = Rs. 12000 - 10%  = Rs. 10,800

Loss% = 4

We know that, C.P = 100/(100 - Loss%) x 100

=> 100/100-4 x 10800

=> 1080000/96

C.P = Rs. 11,250