# Quantitative Aptitude - Arithmetic Ability Questions

## What is Quantitative Aptitude - Arithmetic Ability?

Quantitative Aptitude - Arithmetic Ability test helps measure one's numerical ability, problem solving and mathematical skills. Quantitative aptitude - arithmetic ability is found in almost all the entrance exams, competitive exams and placement exams. Quantitative aptitude questions includes questions ranging from pure numeric calculations to critical arithmetic reasoning. Questions on graph and table reading, percentage analysis, categorization, simple interests and compound interests, clocks, calendars, Areas and volumes, permutations and combinations, logarithms, numbers, percentages, partnerships, odd series, problems on ages, profit and loss, ratio & proportions, stocks &shares, time & distance, time & work and more .

Every aspirant giving Quantitative Aptitude Aptitude test tries to solve maximum number of problems with maximum accuracy and speed. In order to solve maximum problems in time one should be thorough with formulas, theorems, squares and cubes, tables and many short cut techniques and most important is to practice as many problems as possible to find yourself some tips and tricks in solving quantitative aptitude - arithmetic ability questions.

Wide range of Quantitative Aptitude - Arithmetic Ability questions given here are useful for all kinds of competitive exams like Common Aptitude Test(CAT), MAT, GMAT, IBPS and all bank competitive exams, CSAT, CLAT, SSC Exams, ICET, UPSC, SNAP Test, KPSC, XAT, GRE, Defence, LIC/G IC, Railway exams,TNPSC, University Grants Commission (UGC), Career Aptitude test (IT companies), Government Exams and etc.

A) 9 | B) 16 |

C) 22 | D) 36 |

Explanation:

In the given series 1 4 9 16 22 36

1 = 1 x 1

4 = 2 x 2

9 = 3 x 3

16 = 4 x 4

25 = 5 x 5 (Not 22)

36 = 6 x 6

Hence, the odd man in the series is 22.

A) p >= 12 | B) p <= 11/3 |

C) p < 12 | D) p > 11/3 |

Explanation:

The given inequality is** 3p - 16 < 20**

**For solving this inequality, follow these steps**

Now add 16 on both sides

we get **3p - 16 + 16 < 20 + 16**

**=> 3p < 36**

Now divide the above eqn with 3 on both sides

we get,** 3p/3 < 36/3**

**p < 12.**

A) 12/49 | B) 7/30 |

C) 13/56 | D) 11/46 |

Explanation:

In the given options,

12/49 can be written as 1/(49/12) = 1/4.083

7/30 can be written as 1/(30/7) = 1/4.285

13/56 can be written as 1/(56/13) = 1/4.307

11/46 can be written as 1/(46/11) = 1/4.1818

Here in the above,

1/4.083 has the smallest denominator and so 12/49 is the largest number or fraction.

A) 120 | B) 240 |

C) 256 | D) 360 |

Explanation:

Required number of 5 digit numbers can be formed by using the digits 1, 0, 2, 3, 5, 6 which are between 50000 and 60000 without repeating the digits are

**5 x 4 x 3 x 2 x 1 = 120.**

A) 1.5 kmph | B) 1 kmph |

C) 0.75 kmph | D) 0.5 kmph |

Explanation:

Speed of the boat upstream = 36/9 = 4 kmph

Speed of the boat in downstream = 36/6 = 6 kmph

Speed of stream = 6-4/2 = 1 kmph

A) 60 | B) 55 |

C) 45 | D) 40 |

Explanation:

From the given data,

let the length, breadth and height of the cuboid are m, n, r

m x n = 12

n x r = 20

r x m = 15

Hence, m x n x n x r x r x m = 12 x 20 x 15

mnr = sqrt of (12x20x15) = **60 cub.cm.**

A) 2 | B) 0 |

C) 1 | D) 50 |

Explanation:

50.003% of 99.8 **÷ **49.988 = ?

? ~= (50 x 100/100)/50

? ~= (50 x 100)/(100 x 50)

**? ~= 1**