6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

On what dates of July.2004 did Monday fall?

A) 6th,10th,21st,30th	B) 12th,7th,19th,28th
C) 5th,10th,24th,17th	D) 5th, 12th, 19th, 26th

Answer & Explanation Answer: D) 5th, 12th, 19th, 26th

Explanation:

Let us find the day on 1st July, 2004.

2000 years have 0 odd day. 3 ordinary years have 3 odd days.

Jan. Feb. March April May June July

31 + 29 + 31 + 30 + 31 + 30 + 1

= 183 days = (26 weeks + 1 day) = 1 t .

Total number of odd days = (0 + 3 + 1) odd days = 4 odd days. '

:. 1st July 2004 was 'Thursday',-,-

Thus, 1st Monday in July 2004 _as on 5th July.

Hence, during July 2004, Monday fell on 5th, 12th, 19th and 26th. .

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Filed Under: Calendar

118 24697

Q:

If 8 men can reap 80 hectares in 24 days , then how many hectares can 36 men reap in 30 days?

A) 350	B) 400
C) 425	D) 450

Answer & Explanation Answer: D) 450

Explanation:

Let the required no of hectares be x. Then

More men, More hectares (Direct proportion)

More days, More hectares (Direct proportion)

$\begin{array}{r} \begin{matrix} M e n & 8 : 36 \end{matrix} \\ \begin{matrix} D a y s & 24 : 30 \end{matrix} \end{array}\} ⋮ ⋮ 80 : x$

=> ( 8 * 24 * x) = (36 * 30 * 80)

=> x= 450

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Filed Under: Chain Rule

32 24688

Q:

A group of workers was put on a job. From the second day onwards, one worker was withdrawn each day. The job was finished when the last worker was withdrawn. Had no worker been withdrawn at any stage, the group would have finished the job in 55% of the time. How many workers were there in the group?

A) 50	B) 40
C) 45	D) 10

Answer & Explanation Answer: D) 10

Explanation:

Let the number of workers be x.

Now, Using work equivalence method,

X + (X-1) + (X-2)+ . . . . + 1 = X *55% of X

=> [X * (X+1)] / 2 = X * (55X/100) [because, Series is in AP. Sum of AP = {No. of terms (first term+ last term)/2} ]

Therefore, X = 10

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Filed Under: Time and Work

63 24679

Q:

The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475 find the lengths of the parallel sides.

A) 27 and 23	B) 24 and 23
C) 25 and 23	D) 22 and 23

Answer & Explanation Answer: A) 27 and 23

Explanation:

Let the two parallel sides of the trapezium be a cm and b cm.

Then, a - b = 4

And, $\frac{1}{2} \times (a + b) \times 19 = 475 = > (a + b) = 50$

Solving (i) and (ii), we get: a = 27, b = 23.

So, the two parallel sides are 27 cm and 23 cm.

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

23 24644

Q:

Rs. 5887 is divided between Shyam and Ram, such that Shyam's share at the end of 9 years is equal to Ram's share at the end of 11 years, compounded annually at the rate of 5%. Find the share of Shyam.

A) 3567	B) 3452
C) 3087	D) 3544

Answer & Explanation Answer: C) 3087

Explanation:

Shyam's share * (1+0.05)9 = Ram's share * (1 + 0.05)11

Shyam's share / Ram's share = (1 + 0.05)11 / (1+ 0.05)9 = (1+ 0.05)2 = 441/400

Therefore Shyam's share = (441/841) * 5887 = 3087

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

17 24623

Q:

The H.C.F and L.C.M of two numbers are 84 and 21 respectively. If the ratio of the two numbers is 1 : 4 , then the larger of the two numbers is

A) 12	B) 48
C) 84	D) 108

Answer & Explanation Answer: C) 84

Explanation:

Let the numbers be x and 4x. Then, $x \times 4 x = 84 \times 21 \Leftrightarrow x^{2} = \frac{84 \times 21}{4} \Leftrightarrow x = 21$

Hence Larger Number = 4x = 84

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Filed Under: HCF and LCM

26 24607

Q:

The banker's gain on a sum due 3 years hence at 12% per annum is Rs. 270. The banker's

discount is:

A) 1315	B) 1150
C) 1020	D) 980

Answer & Explanation Answer: C) 1020

Explanation:

T.D. =(B.G*100)/(R*T)=Rs(270*100)/(12*3) = Rs. 750.

B.D. = Rs.(750 + 270) = Rs. 1020.

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Filed Under: Banker's Discount

3 24597

Q:

In a college, the ratio of the number of boys to girls is 8 : 5. If there are 160 girls, the total number of students in the college is

A) 100	B) 250
C) 260	D) 416

Answer & Explanation Answer: D) 416

Explanation:

Let the number of boys and girls be 8x and 5x.
Total number of students = 13x = 13 * 32 = 416.

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Filed Under: Ratios and Proportions

97 24595

Quantitative Aptitude - Arithmetic Ability Questions

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