6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

If the arithmetic mean of seventy-five numbers is calculated, it is 35. if each number is increased by 5, then mean of new numbers is :

A) 30	B) 40
C) 50	D) 60

Answer & Explanation Answer: B) 40

Explanation:

Let the numbers are $x_{1,} x_{2,} . . . . . . . x_{75}$

By Hypothesis , $\frac{x_{1} + x_{2} + . . . . x_{75}}{75} = 35$ ......(i)

Mean of new numbers = $\frac{(x_{1} + 5) + (x_{2} + 5) + . . . . . . . (x_{75} + 5)}{75}$

$\frac{x_{1} + x_{2} + . . . . . . x_{75} + 5 * 75}{75}$

$\frac{x_{1} + x_{2} + . . . . . . x_{75}}{75} + \frac{375}{75} = 35 + 5 = 40$ By (i)

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Filed Under: Average

43 24478

Q:

Rahul went to purchase a Nokia mobile handset, the shopkeeper told him to pay 20% tax if he asked the bill. Rahul manages to get the discount of 5% on the actual saleprice of the mobile and he paid the shopkeeper Rs. 3325 without tax. Besides he manages to avoid to pay 20% tax on the already discounted price, what is the amount of discount that he has gotten?

A) 750	B) 375
C) 875	D) 525

Answer & Explanation Answer: C) 875

Explanation:

CP = 100, SP (with tax) =120

New SP = 100 - 5 = 95

Effective discount = 120 - 95 = 25

So, at SP of 95 ----> discount = 25

and at SP of 3325 -----> discount = $\frac{25}{95} \times 3325 = 875$

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

54 24471

Q:

A Certain sum of money an amounts to Rs 2500 in a span Of 5 years and further to Rs.3000 in a span of 7 years at simple interest The sum is ?

A) Rs. 1800	B) Rs. 2000
C) Rs. 1400	D) Rs. 1250

Answer & Explanation Answer: D) Rs. 1250

Explanation:

2500 in 5th year and 3000 in 7th year
So in between 2 years Rs. 500 is increased => for a year 500/2 = 250
So, per year it is increasing Rs.250 then in 5 years => 250 x 5 = 1250
Hence, the initial amount must be 2500 - 1250 = Rs. 1250

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Filed Under: Simple Interest
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

16 24463

Q:

A man wants to sell his scooter .There are two offers one at Rs12000 cash and other at a credit of Rs12880 to be paid after 8 months ,money being at 18% per annum which is better offer?

A) Rs.12880	B) Rs.12000
C) Both are equally good	D) None of the above

Answer & Explanation Answer: B) Rs.12000

Explanation:

PW of Rs.12,880 due 8 months hence

= Rs. [12880 x 100] / [100+(18 x 8/12)] =Rs.11500

Clearly 12000 in cash is a better offer.

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Filed Under: True Discount

13 24426

Q:

The present worth of Rs.169 due in 2 years at 4% per annum compound interest is

A) Rs.156.25	B) Rs.150
C) Rs.140	D) Rs125.25

Answer & Explanation Answer: A) Rs.156.25

Explanation:

Present Worth

= $\frac{P}{{(1 + \frac{R}{100})}^{2}}$

= $\frac{169}{{(1 + \frac{4}{100})}^{2}}$

= Rs.156.25

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

30 24399

Q:

A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:

A) 29/5	B) 37/4
C) 42	D) 54

Answer & Explanation Answer: C) 42

Explanation:

After 10 days : 150 men had food for 35 days.

Suppose 125 men had food for x days.

Now, Less men, More days (Indirect Proportion)

125 : 150 :: 35 : x => 125 x x = 150 x 35

=>

=> x = 42.

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Filed Under: Quantitative Aptitude - Arithmetic Ability

38 24390

Q:

H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is

A) 180	B) 360
C) 540	D) 1260

Answer & Explanation Answer: A) 180

Explanation:

$4 \times 27 \times 3125 = 2^{2} \times 3^{3} \times 5^{5}$

$8 \times 9 \times 25 \times 7 = 2^{3} \times 3^{2} \times 5^{2} \times 7$

$16 \times 81 \times 5 \times 11 \times 49 = 2^{4} \times 3^{4} \times 5 \times 7^{2} \times 11$

Therefore, H.C.F = $2^{2} \times 3^{2} \times 5$ = 180

$\inline \fn_jvn \therefore$ $\inline \fn_jvn H.C.F =2^{2}\times 3^{2}\times 5=180$

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Filed Under: HCF and LCM

75 24355

Q:

A man borrowed Rs 24000 from two money lenders. For one loan, he paid 15% per annum and for the other 18% per annum. At the end of one year, he paid Rs 4050. How much did he borrow at each rate ?

A) Rs.16000	B) Rs.12000
C) Rs.15000	D) Rs.13000

Answer & Explanation Answer: C) Rs.15000

Explanation:

Let the sum at 15% be Rs x and that at 18% be Rs (24000 - x).

{(x * 15 * 1)/100 } + { [(24000 – x) * 18 * 1]/100 } = 4050

or 15 x + 432000 - 18x = 405000 or x = 9000.

Money borrowed at 15% = Rs 9000 .

Money borrowed at 18% = Rs 15000.

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Filed Under: Simple Interest
Exam Prep: GRE

25 24351

Quantitative Aptitude - Arithmetic Ability Questions

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