6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A merchant buys two items for Rs. 7500. One item he sells at a profit of 16% and the other item at 14% loss. In the deal, the merchant makes neither any profit nor any loss. What is the difference between the selling price of both the items?

A) Rs. 620	B) Rs. 654
C) Rs. 725	D) Rs. 747

Answer & Explanation Answer: A) Rs. 620

Explanation:

Let the C.P of one item is Rs. P
and that of other is Rs. (7500 - P)

According to the data given
C.P = S.P
=> Px(116/100) + (7500-P)x(86/100) = 7500
=> 30P = 105000
=> P = 3500

Required difference between selling prices
= Rs. [(3500/100) x 116] - [(4000/100) x 86]
= 4060-3440
= Rs. 620

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

15 15400

Q:

The capacity of a tank of dimensions (8m x 6m x 2.5m)is

A) 120 litres	B) 1200 litres
C) 12000 litres	D) 120000 litres

Answer & Explanation Answer: D) 120000 litres

Explanation:

capacity of a tank = volume of tank

= [ (8 x 100) x (6 x 100) x (2.5 x 100) ]/ 1000 litres

= 120000 litres

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams
Job Role: Bank PO

12 15382

Q:

Sum of the ages of Rajesh, Suresh, Mahesh and Dinesh is 76 years. 7 years hence, their age ratio is 7:6:5:8. Find Mahesh’s present age ?

A) 17 years	B) 13 years
C) 14 years	D) 16 years

Answer & Explanation Answer: B) 13 years

Explanation:

Given R + S + M + D = 76

=> R+7 : S+7 : M+7 : D+7 = 7:6:5:8

=> Let the ratio = x

=> M+7 = 5x

=> M = 5x-7

=> R = 7x-7

=> S = 6x-7

=> D = 8x-7

=> R + S + M + D = 76

=> 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76

=> 26x - 28 = 76

=> 26x = 104

=> x = 4

=> Mahesh's present age = 5x-7 = 20 - 7 = 13 years.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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23 15359

Q:

The milk and water in two vessels A and B are in the ratio 4:3 and 2:3 respectively. In what ratio the liquids in both the vessels be mixed to obtain a new mixture in vessel c consisting half milk and half water?

A) 8:3	B) 6:7
C) 7:5	D) 11:7

Answer & Explanation Answer: C) 7:5

Explanation:

Milk in 1-litre mixture of A = 4/7 litre.

Milk in 1-litre mixture of B = 2/5 litre.

Milk in 1-litre mixture of C = 1/2 litre.

By rule of alligation we have required ratio X:Y

X : Y

4/7 2/5

\ /

(Mean ratio)
(1/2)

/ \

(1/2 – 2/5) : (4/7 – 1/2)

1/10 1/1 4

So Required ratio = X : Y = 1/10 : 1/14 = 7:5

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Filed Under: Alligation or Mixture
Exam Prep: CAT , Bank Exams , AIEEE
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24 15359

Q:

The sum of three numbers is 98. If the ratio of the first to second is 2 : 3 and that of the second to the third is 5 : 8, then the second number is:

A) 10	B) 20
C) 30	D) 40

Answer & Explanation Answer: C) 30

Explanation:

Let the three parts be A, B, C. Then,

A : B = 2 : 3 and B : C = 5 : 8 = $(5 * \frac{3}{5}) : (8 * \frac{3}{5})$ = $3 : \frac{24}{5}$

$\Rightarrow$ A : B : C = 2 : 3 : => = 10 : 15 : 24

$\Rightarrow$ B = $\frac{24}{5}$ = 30

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Filed Under: Ratios and Proportions

45 15348

Q:

Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is:

A) Rs.1550	B) Rs.1650
C) Rs,1750	D) Rs.1850

Answer & Explanation Answer: C) Rs,1750

Explanation:

C.I.= Rs.[4000*(1+10/100)^2-4000]

=Rs.840

sum=Rs.(420 * 100)/3*8=Rs.1750

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

23 15326

Q:

What is the average of four tenths and five thousandths

A) 25002	B) 2502
C) 0.2025	D) none

Answer & Explanation Answer: C) 0.2025

Explanation:

Four tenths = 0.4

Five thousandths = 0.005

The average is (0.4 + 0.005)/2 = 0.2025

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Filed Under: Average
Exam Prep: GRE

12 15325

Q:

Compute the sum of 4 digit numbers which can be formed with the four digits 1,3,5,7, if each digit is used only once in each arrangement.

A) 105555	B) 106665
C) 106656	D) 108333

Answer & Explanation Answer: C) 106656

Explanation:

The number of arrangements of 4 different digits taken 4 at a time is given by $4 P_{4}$ = 4! = 24.All the four digits will occur equal number of times at each of the position,namely ones,tens,hundreds,thousands.

Thus,each digit will occur 24/4 = 6 times in each of the position.The sum of digits in one's position will be 6 x (1+3+5+7) = 96.Similar is the case in ten's,hundred's and thousand's places.

Quantitative Aptitude - Arithmetic Ability Questions

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