Quantitative Aptitude - Arithmetic Ability Questions

Q:

The sum of 3rd and 15th elements of an arithmetic progression is equal to the sum of 6th, 11th and 13th elements of the same progression. Then which element of the series should necessarily be equal to zero ?

A) 14th element B) 9th element
C) 12th element D) 7th element
 
Answer & Explanation Answer: C) 12th element

Explanation:

If we consider the third term to be ‘x”
The 15th term will be (x + 12d)
6th term will be (x + 3d)
11th term will be (x + 8d) and
13th term will be (x + 10d).
Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.
x + 9d will be the 12th term.

Thus, 12th term of the A.P will be zero.

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Filed Under: Chain Rule
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

35 13143
Q:

Calender Puzzle 

calendar puzzle

A) A B) B
C) C D) D
 
Answer & Explanation Answer: D) D

Explanation:

We can't determine the last day of the next month which has 31 days because we don't know the days in present month which may be 30 or 31. And the next month may be March which contains 31 days  which implies that the present month may be February which contains 28 or 29 days.

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Filed Under: Calendar
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

42 13129
Q:

In how many different ways can the letters of the word 'CORPORATION' be arranged so that the vowels always come together

A) 50000 B) 40500
C) 5040 D) 50400
 
Answer & Explanation Answer: D) 50400

Explanation:

In the word 'CORPORATION', we treat the vowels OOAIO as one letter.

 

Thus, we have CRPRTN (OOAIO).

 

This has 7 (6 + 1) letters of which R occurs 2 times and the rest are different.

 

Number of ways arranging these letters =7!/2!= 2520.

 

Now, 5 vowels in which O occurs 3 times and the rest are different, can be arranged in 3!/5!= 20 ways.

 

Required number of ways = (2520 x 20) = 50400.

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Q:

The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq.cm. Find its height?

A) 3 cm B) 4 cm
C) 6 cm D) 8 cm
 
Answer & Explanation Answer: C) 6 cm

Explanation:

Let height =x Then,  base =2x

2x * x = 72      

=>x=6

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

58 13115
Q:

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases  by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity?

A) 2010 B) 2011
C) 2012 D) 2013
 
Answer & Explanation Answer: B) 2011

Explanation:

Suppose commodity X wil cost 40 paise more than Y after Z  years. Then,

        (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40

=>  0.25Z = 0.40 + 2.10  => Z= 2.50/0.25 = 10

Therefore, X will cost 40 paise more than Y 10  years after 2001 . i.e in 2011

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Filed Under: Decimal Fractions

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Q:

If an object travels at five feet per second, how many feet does it travel in one hour?

A) 30 B) 3000
C) 18 D) 1800
 
Answer & Explanation Answer: D) 1800

Explanation:

If an object travels at 5 feet per second it covers 5x60 feet in one minute, and 5x60x60 feet in one hour.

 

 

 

Answer = 1800 

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Filed Under: Height and Distance
Exam Prep: GRE

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Q:

A solid cube of side 6 is first painted pink and then cut into smaller cubes of side 2. How many of the smaller cubes have paint on exactly 2 sides?

A) 30 B) 24
C) 12 D) 8
 
Answer & Explanation Answer: C) 12

Explanation:

When the larger cube is cut into smaller cubes, the corner cubes will have paint on three sides. The cubes in the middle of the faces will have paint on only one side, but the cubes cut from the edges will have paint on two sides. In this case, there will be only one cube one each edge (excluding the corners), and since there are 12 edges, there will be 12 cubes with paint on two sides.

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Filed Under: Numbers
Exam Prep: GRE

8 13075
Q:

Helpers are needed to prepare for the fete. Each helper can make either 2 large cakes or 35 small cakes per hour. The kitchen is available for 3 hours and 20 large cakes and 700 small cakes are needed. How many helpers are required?

A) 10 B) 15
C) 20 D) 25
 
Answer & Explanation Answer: A) 10

Explanation:

20 large cakes will require the equivalent of 10 helpers working for one hour. 700 small cakes will require the equivalent of 20 helpers working for one hour. This means if only one hour were available we would need 30 helpers. But since three hours are available we can use 10 helpers.

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Filed Under: Percentage
Exam Prep: GRE

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