6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The base of a parallelogram is twice its height. If the area of the parallelogram is 72 sq.cm. Find its height?

A) 3 cm	B) 4 cm
C) 6 cm	D) 8 cm

Answer & Explanation Answer: C) 6 cm

Explanation:

Let height =x Then, base =2x

2x * x = 72

=>x=6

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Filed Under: Area
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58 13148

Q:

A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2490 ?

A) Rs. 820	B) Rs. 830
C) Rs. 840	D) Rs. 850

Answer & Explanation Answer: B) Rs. 830

Explanation:

Let the total amount in the partnership be 'x'.
Then A's share = x/3
B's share = x/4
C's share = x/5
D's share = x - (x/3 + x/4 +x/5) = 13x/60

A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13

A's share in the profit of Rs. 2490 = 20 (2490/60) = Rs. 830.

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Filed Under: Partnership
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7 13139

Q:

600 students took the test on physics and chemistry. 35% students failed in physics and 45% students failed in chemistry and 40% of those who passed in chemistry also passed in physics, then how many students failed in both:

A) 162	B) 138
C) 60	D) None of these

Answer & Explanation Answer: D) None of these

Explanation:

Physics Chemistry

Failed 35% 45%

Passed 65% 55%

Passed in both = 22% of total student

percentage of students who are passed in any of the physics or chemistry or both =(65+55) - 22 = 98%

So, the percentage of students who are failed in both = 2%

Therefore, total failed (in both subjects) students = 12

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Filed Under: Percentage

14 13135

Q:

Two numbers are respectively 40% and 30% more than a third number. The second number expressed in terms of percentage of the first is ?

A) 92.8%	B) 84.23%
C) 87.14%	D) 94.1%

Answer & Explanation Answer: A) 92.8%

Explanation:

Here, x = 40 and y = 30;
Therefore second number
= [[ $\frac{100 + y}{100 + x}$ ] x 100 ]% of first number
= [[ $\frac{100 + y}{100 + x}$ ] x 100 ]% of first number
Second number = 92.8% of the first number.

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Filed Under: Percentage
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12 13131

Q:

Find the Greatest Number that will devide 43, 91 and 183 so as to leave the same remainder in each case

A) 4	B) 7
C) 9	D) 13

Answer & Explanation Answer: A) 4

Explanation:

Required Number = H.C.F of (91- 43), (183- 91) and (183-43)

= H.C.F of 48, 92, and 140 = 4

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Filed Under: HCF and LCM

33 13100

Q:

How many seconds in 10 years?

A) 31523500 sec	B) 315360000 sec
C) 315423000 sec	D) 315354000 sec

Answer & Explanation Answer: B) 315360000 sec

Explanation:

We know that,

1 year = 365 days

1 day = 24 hours

1 hour = 60 minutes

1 minute = 60 seconds.

Then, 1 year = 365 x 24 x 60 x 60 seconds.

= 8760 x 3600

1 year = 31536000 seconds.

Hence, 10 years = 31536000 x 10 = 315360000 seconds.

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Filed Under: Calendar
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60 13088

Q:

Wheels of diameters 7cm and 14cm start rolling simultaneously from x & y which are 1980 cm apart towards each other in opposite directions. Both of them make the same number of revolutions per second. If both of them meet after 10seconds.The speed of the smaller wheel is

A) 22m/s	B) 33m/s
C) 44m/s	D) 55m/s

Answer & Explanation Answer: A) 22m/s

Explanation:

let each wheel make x revolutions per sec. Then $[(2 π * \frac{7}{2} * x) + (2 π * 7 * x)] * 10 = 1980$ $(2 * \frac{22}{7} * \frac{7}{2} * x) + (2 * \frac{22}{7} * \frac{7}{2} * x) = 198$

$66 x = 198$

distance moved by smaller wheel in 3 revolutions

= $2 * \frac{22}{7} * \frac{7}{2} * 3 = 66 c m$

speed of smaller wheel = $\frac{66}{3}$ m/s = 22m/s

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Filed Under: Area
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Job Role: Bank PO

5 13080

Q:

There are three boats B1, B2 and B3 working together they carry 60 people in each trip. One day an early morning B1 carried 50 people in few trips alone. When it stopped carrying the passengers B2 and B3 started carrying the people together. It took a total of 10 trips to carry 300 people by B1, B2 and B3. It is known that each day on an average 300 people cross the river using only one of the 3 boats B1, B2 and B3. How many trips it would take to B1, to carry 150 passengers alone?

A) 15	B) 30
C) 25	D) 10

Answer & Explanation Answer: A) 15

Explanation:

Combined efficiency of all the three boats = 60 passenger/trip

Now, consider option(a)

15 trips and 150 passengers means efficiency of B1 = 10 passenger/trip

which means in carrying 50 passengers B1 must has taken 5 trips. So the rest trips equal to 5 (10-5 = 5) in which B2 and B3 together carried remaining 250 (300 - 50 = 250) Passengers.

Therefore the efficiency of B2 and B3 = 250/5 = 50 passenger/trip

Since, the combined efficiency of B1, B2 and B3 is 60. Which is same as given in the first statement hence option(a) is correct.

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Filed Under: Time and Work

33 13077

Quantitative Aptitude - Arithmetic Ability Questions

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