Sawaal

 Quantitative Aptitude - Arithmetic Ability Questions

Popular Latest Rated
Q:

In ∆PQR measure of angle Q is 90 deg. If cosecP = 17/15, and PQ = 0.8cm, then what is the length (in cm) of side QR?

 

A) 1.7   B) 2  
C) 2.5   D) 1.5
 
Answer & Explanation Answer: D) 1.5

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

0 10649
Q:

The dates 3rd April, 2005; 6th August, 2010 and 5th December, 2013 when written in Date-Month-Year Form have a unique mathematical property. The Indian Independence Day of which year among the following has the same property?

A) 2017 B) 2016
C) 2018 D) 2015
 
Answer & Explanation Answer: A) 2017

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Calendar
Exam Prep: Bank Exams

51 10639
Q:

If x is 90% of Y, what percent of x is y?

Answer

x = 90% of y = \inline \frac{9}{10}y


 


\inline \therefore \frac{x}{y}=\frac{9}{10}\Rightarrow \frac{y}{x}=\frac{10}{9} 


=> y = 1.1% of x.

Report Error

View answer Workspace Report Error Discuss

Subject: Percentage

25 10628
Q:

Suppose you can travel from a place A to a place B by 3 buses, from place B to place C by 4 buses, from place C to place D by 2 buses and from place D to place E by 3 buses. In how many ways can you travel ?from A to E?

A) 36 B) 64
C) 74 D) 72
 
Answer & Explanation Answer: D) 72

Explanation:

 

The bus fromA to B can be selected in 3 ways.

The bus from B to C can be selected in 4 ways.

The bus from C toD can be selected in 2 ways.

The bus fromD to E can be selected in 3 ways.

So, by the General Counting Principle, one can travel fromA to E in 3 x 4 x 2 x 3 ways = 72

 

Report Error

View Answer Report Error Discuss

Filed Under: Permutations and Combinations

2 10625
Q:

A man walks at a speed of 2 km/hr and runs at a speed of 6 km/hr. How much time will the man require to cover a distance of 20 1/2 km, if he completes half of the distance, i.e., (10 1/4) km on foot and the other half by running ?

A) 12.4 hrs B) 11.9 hrs
C) 10.7 hrs D) 9.9 hrs
 
Answer & Explanation Answer: B) 11.9 hrs

Explanation:

We know that

Time = Distance/speed
Required time = (10 1/4)/2 + (10 1/4)/6
= 41/8 + 41/6
= 287/24 = 11.9 hours.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

9 10622
Q:

Oct 1st 1994 falls on which day?

A) Sunday B) Saturday
C) Friday D) Wednesday
 
Answer & Explanation Answer: B) Saturday

Explanation:

1 Oct, 1994 = (1993 years + Period from 1.1.1993 to 1.10.1993)

Odd days in 1600 years = 0

Odd days in 300 years = 1

93 years = (70 ordinary years + 23 leap year) = (70 x 1 + 23 x 2)= 4 odd days

Jan  Feb  March  April  May  June  July  Aug  sept  Oct

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 1 ) = 274 days

274 days = (39 weeks + 1 day) =1 odd day.

Total number of odd days = (0 + 1 + 4 + 1) = 6 odd days.

Given day is Saturday.

Report Error

View Answer Report Error Discuss

Filed Under: Calendar

9 10615
Q:

A cicketer bas a certain average for 10 innings, In the eleventh inning, he scorod 108 runs, thereby increasing his average by 6 runs. His new average is :

A) 44 runs B) 46 runs
C) 48 runs D) 49 runs
 
Answer & Explanation Answer: C) 48 runs

Explanation:

Let average for 10 innings be x. Then,

(10x + 108)/11 = x + 6 => 11x + 66 = 10x + 108  =>  x = 42.

New average = (x + 6) = 48 runs.

Report Error

View Answer Report Error Discuss

Filed Under: Average

3 10604
Q:

The cost price of an article is 54% of the marked price. Calculate the gain percent after allowing a discount of 15%  ?

A) 51.32 % B) 49.23 %
C) 48.4 % D) 46.8 %
 
Answer & Explanation Answer: C) 48.4 %

Explanation:

Let marked price = Rs. 100.
Then, C.P. = RS. 54,
S.P. = Rs. 85
Gain % = 31/64 x 100 = 48.4%.

Report Error

View Answer Report Error Discuss

Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

17 10598