Quantitative Aptitude - Arithmetic Ability Questions

B.G. =(T.D.)^2/P.W.

      = Rs. (160*160)/1600 = Rs. 16.

We know that

Time = Distance/speed
Required time = (10 1/4)/2 + (10 1/4)/6
= 41/8 + 41/6
= 287/24 = 11.9 hours.

Lowest 4-digit number is 1000.
LCM of 3, 4 and 5 is 60.
Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.
Now, add the remainder 2 that's required. Thus, the answer is 1022.

Compound ratio of A:B:C
A:B = 3:4
B:C = 5:6
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A:B:C = 15:20:24

We can divide Rs.118000 in this ratio.

Share of A = 15/59 x 118000 = 30000

Share of B = 20/59 x 118000 = 40000

Share of C = 24/59 x 118000 = 48000

Average speed = total distance / total time

Total distance covered = 6 miles; total time = 45 minutes = 0.75 hours

Average speed = 6/ 0.75 = 8 miles/hour

Total number of events=6 x 6 x 6=216
Let A be the event of getting a total of atleast 6 and B denoted event of getting a total of less than 6 i.e.,3,4,5.

So,B={(1,1,1),(1,1,2),(1,2,1),(2,1,1),(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1)}

Favourable number of cases=10

Therefore,P(B)=10/216

=> P(A) = 1 - P(B)

             = 1 - (10/216) = 103/108

Let marked price = Rs. 100.
Then, C.P. = RS. 54,
S.P. = Rs. 85
Gain % = 31/64 x 100 = 48.4%.