Quantitative Aptitude - Arithmetic Ability Questions

Q:

What is the length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high  ?

A) 13 m B) 14 m
C) 15 m D) 16 m
 
Answer & Explanation Answer: A) 13 m

Explanation:

The length of the longest pole which can be kept in a room 12 m long, 4 m broad and 3 m high is

 

=>  d2 = 122 + 42 + 32 = 13mts.

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Filed Under: Area
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13 7920
Q:

Find the perimeter and area of a square that has a side of length 14 feet.

A) 176 B) 186
C) 196 D) 206
 
Answer & Explanation Answer: C) 196

Explanation:

Perimeter of a square p=4s ,where s=length of its side 

=> p=4(14)=56 feets 

 

Area  of a square A = s x s

=> A=196


The perimeter is 56 feet, and the area is 196 square feet.

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Filed Under: Area
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2 7913
Q:

What will be the day on 18th Feb,2016? 

A) Friday B) Thursday
C) Saturday D) Wednesday
 
Answer & Explanation Answer: B) Thursday

Explanation:

18 Feb, 2016 = (2015 years + Period from 1.1.2016 to 18.2.2016)

 

Odd days in 1600 years = 0

Odd days in 400 years = 0

15 years = (12 ordinary years + 3 leap year) = (12 x 1 + 3 x 2)= 4 odd days

 

Jan  Feb

(31 + 18 ) = 49 days

49 days = (7 weeks + 0 day)= 0 odd day.

 

Total number of odd days = (0 + 0 + 4 + 0) = 4 odd day.

 

Given day is Thursday

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Filed Under: Calendar

16 7913
Q:

H.C.F of 3240, 3600 and a third number is 36 and their L.C.M is 24 x 35 x 52 x 72 . What is the third number?

A) 47628 B) 49874
C) 24157 D) 42146
 
Answer & Explanation Answer: A) 47628

Explanation:

hcf_of_three_numbers_3240,_3600_and_third_number_is_361542439249.jpg image

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Filed Under: HCF and LCM
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17 7912
Q:

If 1 is added to the denominator of a traction, the fraction becomes 1/2. If 1 is added to the numerator of the fraction, the fraction becomes 1. The fraction is :

A) 1/3 B) 2/3
C) 4/3 D) 5/3
 
Answer & Explanation Answer: B) 2/3

Explanation:

Let the fraction be x/y. Then, x /(y+1) = 1/2

=> 2x - y = 1  ..........(i)and 

(x + 1) / y = 1  => x - y =  1 .......(ii)

 Solving (i) and (ii), we get :  x  = 2, y = 3. Hence, the required fraction is 2/3..

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Filed Under: Problems on Numbers

4 7900
Q:

Kalyan purchased a Maruti van for Rs. 1,96,000 and the rate of depreciation is 14(2/7) % per annum. Find the value of the van after two years ?

A) Rs. 1,24,000 B) Rs. 1,44,000
C) Rs. 1,32,000 D) Rs. 1,62,000
 
Answer & Explanation Answer: B) Rs. 1,44,000

Explanation:

Value of Maruti Van, V1 = Rs. 1,96,000
Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 years
Let V2 is the value after depreciation.

V2 = V11 - r100t
V2 = 196001 - 10071002

V2 = 196000(6/7)(6/7)

V2 = (196000x36)/49 = Rs. 1,44,000.

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Filed Under: Percentage
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4 7894
Q:

A person lends Rs. 1540 for five years and Rs. 1800 for four years. If he gets Rs. 1788 as interest on both amounts, what is the rate of interest ?

A) 14.5% B) 11%
C) 12% D) 10.5%
 
Answer & Explanation Answer: C) 12%

Explanation:

Let the interest rate be r%

We know that,

S.I = PTR/100

=> (1540 x 5 x r)/100  +  (1800 x 4 x r)/100 = 1788

=> r = 178800/14900 = 12%

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Filed Under: Simple Interest
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20 7891
Q:

In the following question, four groups of three numbers are given. In each group the second and third number are related to the first number by a Logic/Rule/Relation. Three are similar on basis of same Logic/Rule/Relation. Select the odd one out from the given alternatives.

 

A)  (4, 8, 16) B)  (9, 18, 36)
C)  (6, 12, 24) D)  (5, 10, 25)
 
Answer & Explanation Answer: D)  (5, 10, 25)

Explanation:
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Filed Under: Odd Man Out
Exam Prep: Bank Exams

7 7881