Quantitative Aptitude - Arithmetic Ability Questions

Q:

At a game of billiards, A can give B 20 points in 60 and A can give C  15 points in 60. How many points can C give B in a game of 90 ?

A) 9 points B) 10 points
C) 11 points D) 8 points
 
Answer & Explanation Answer: B) 10 points

Explanation:

a:b = 60:40
a:c = 60:45
c/a x a/b = 45/60 x 60/40 = 45/40 = 90/80
So C gives B => 10 points.

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Filed Under: Ratios and Proportions
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Q:

Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is :

A) 83 B) 89
C) 85 D) 79
 
Answer & Explanation Answer: C) 85

Explanation:

Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F of 551 and 1073 = 29;
First number = 551/29 = 19
Third number = 1073/29 = 37.
Required sum = 19 + 29 + 37 = 85.

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Filed Under: Problems on Numbers
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Q:

P, Q and R secured 45%, 50% and 60% marks respectively in Biology. M’s marks in Biology is 12.5 more than P’s marks and 4 less than R’s marks. Find out the individual marks of four students.

 

A. For the students, total marks obtained for Biology is 311.5.
B. Total of M’s and P’s marks in Biology is 147.5.
C. R has obtained 84 marks.

A) Only C B) Only A & B
C) All are required D) None of the statements is required
 
Answer & Explanation Answer: D) None of the statements is required

Explanation:

From the given data,
(60 - 45)% = 12.5 + 4
15% = 16.5
=> 100% = ?
100% = 16.5 x 100/15 = 110

Hence, P = 45% of 110 = 45x110/100 = 49.5
Q = 50% of 110 = 55
R = 60% of 110 = 60 x 110/100 = 66
M = 12.5 + 49.5 = 62 or 66 - 4 = 62

 

Hence, no statement is required to answer.

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Filed Under: Percentage
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Q:

A Product is supported each week by the same three Product supporters. Last month the first supporter took 440 calls, the second took 360 calls, and the third took 300 calls. This month the job will consists of 1500 calls. If the three supporters each increase their work proportionately, how many more calls will the second supporter take this month than last month ?

A) 131 calls B) 160 calls
C) 491 calls D) 600 calls
 
Answer & Explanation Answer: A) 131 calls

Explanation:

1st supporter recieve 440 calls
2nd supporter recieve 360 calls
3rd supporter recieve 300 calls

So total calls = 1100 calls ;
Calls this month= 1500
So remaining calls to be distributed is 400

So Now Ratio 1st:2nd:3rd ==> 440:360:300
=> 22:18:15

Now No. of More Calls 2nd supporter will get => [18/(22+18+15)] x 400
=> (18/55) x 400
=> 131 Calls
So 131 more Calls than last month.

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Filed Under: Ratios and Proportions
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Q:

A man has only 20-paise and 25-paise coins in a bag. If he has 50 coins in all totaling to Rs.10.25, then the number of 20-paise coins is 

A) 42 B) 45
C) 38 D) 36
 
Answer & Explanation Answer: B) 45

Explanation:

Let number of 20 ps coins = x and

number of 25 ps coins = y

Given total coins in the bag = 50

x + y = 50.......(1)

But the total money in the bag = Rs. 10.25

0.20x + 0.25y = 10.25

20x + 25y = 1025.........(2)

Now multiplying (1) by 25 we get

25x+25y=1250.............(3)

By solving (2) and (3)

20x + 25y = 1025;

=> x = 45;

Then, the no. of 20 ps coins are 45.

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Filed Under: Simplification
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Q:

A class is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the class room ?

A) 115 B) 117
C) 116 D) 114
 
Answer & Explanation Answer: B) 117

Explanation:

Length = 6 m 24 cm = 624 cm
Width = 4 m 32 cm = 432 cm
HCF of 624 and 432 = 48
Number of square tiles required = (624 x 432)/(48 x 48) = 13 x 9 = 117.

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Filed Under: Area
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6 7484
Q:

Which of the following dances is a solo dance?

A) Yakshagana B) Ottan Thullal
C) Bharathanatyam D) Kuchipudi
 
Answer & Explanation Answer: B) Ottan Thullal

Explanation:
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Q:

The banker's discount on Rs. 1650 due a certain time hence is Rs. 165. Find the true discount and the banker's gain.

A) 15 B) 20
C) 18 D) 13
 
Answer & Explanation Answer: A) 15

Explanation:

   Sum = [(B.D.xT.D.)/ (B.D.-T.D.)]

              = [(B.D.xT.D.)/B.G.]

T.D./B.G.  = Sum/ B.D.

   =1650/165

               =10

Thus, if B.G. is Re 1, T.D. = Rs. 10.

If B.D.is Rs. ll, T.D.=Rs. 10.

If B.D. is Rs. 165, T.D. = Rs. [(10/11)xl65]

            =Rs.150

 And, B.G. = Rs. (165 - 150) = Rs, 15.

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Filed Under: Banker's Discount

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