Quantitative Aptitude - Arithmetic Ability Questions

According to the given data,

Let Cost price of the article be 'cp'

Then,

102.25 cp - 92 cp = 164 x 100

10.25 cp = 16400

cp = 1600

Now, if he sells at Rs. 1760

Profit = 1760 - 1600 = 160

Profit% = 160/1600 x 100 = 10%.

Let marks obtained by N = x

M's marks = 0.80x

L's marks = 1.25 (0.80x)

K's marks = (0.90) (1.25) (0.80x)

= 0.9x

But 0.9x = 360 ⇒ x = 400

Percentage of Marks obtained by N

= 400 x 100/500 = 80%

Given initial investments ratio = 2 : 3 : 4

At the end of 6 months, A invested an amount such that his total capital became equal to B's initial capital investment

i.e, upto 6 months A's investment is 2 and after 6 months his invstment is 3 = B's investment

Now, Ratio of investment for one year

=> A : B : C = (2×6 + 3×6) : (3×12) : (4×12)

= 30 : 36 : 48

= 5 : 6 : 8

But given B's profit = 3000

=> 6 ratio = 3000

For total => 19 ratio = Rs. 9500.

Area of the park = (60 x 40) = 2400 sq.m  

Area of the lawn = 2109  sq.m 

Area of the crossroads = (2400 - 2109) = 291 sq.m   

Let the width of the road be x metres. Then,   

60x + 40x - (x * x) = 291  

=>(x * x) - 100x + 291 = 0    

=>(x - 97)(x - 3) = 0  

=>x=3

Given exp = 18225102+18225104+18225106+18225108

               = 1822510+18225102+18225103+18225104

               = 13510+135100+1351000+13510000

               = 13.5+1.35+0.135+0.0135=14.9985

A : B = 100 : 75

B : C = 100 : 96.

A : C = (A/B*B/C) = (100/75*100/96) = 100/72  =100:72     

   A beats C by (100 - 72) m = 28 m.

% of milk in first bottle = 64%

% of milk in second bottle = 100 - 26 = 74%

Now, ATQ

64%            74%
         

         68%

6                    4

Hence, by using allegation method,

Required ratio = 3 : 2

Ratio of profit of Rohith and Puneeth = 3600 x 12 : 2400 x P

= 3600 x 12/2400P = 2/1

=> P = 9

So, Puneeth joined the business after (12 - P) = 12 - 9 = 3 months.