Quantitative Aptitude - Arithmetic Ability Questions

Q:

Rajeev's age is four more than the age of Shilpa. The age of Shilpa can be obtained by subtracting four times her age 4 years ago from the four times her age after 4 years. What was Rajeev's age before 4 years ?

A) 36 years B) 28 years
C) 32 years D) 40 years
 
Answer & Explanation Answer: C) 32 years

Explanation:

Let Shilpa's present age is p years

According to question,

p = 4(x+4) – 4(x–4)

p = 4x+16 – 4x+16

p = 32

Shilpa's present age = 32 years

Rajeev is four years older than Shilpa

=> Shilpa's present age = Rajeev's age 4 years before.

=> Rajeev's age 4 years before = 32 years.

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Filed Under: Problems on Ages
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Q:

If the sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively, then the sum of the reciprocals of the numbers is equal to ?

A) 13/125 B) 14/57
C) 11/120 D) 16/41
 
Answer & Explanation Answer: C) 11/120

Explanation:

Let the numbers be a and b.
We know that product of two numbers = Product of their HCF and LCM
Then, a + b = 55 and ab = 5 x 120 = 600.
=> The required sum = (1/a) + (1/b) = (a+b)/ab
=55/600 = 11/120

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Filed Under: HCF and LCM
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23 7283
Q:

What is the difference between the biggest and the smallest fraction among 2/3 , 3/4 , 4/5 and 5/6?

A) 1/6 B) 1/12
C) 1/20 D) 1/30
 
Answer & Explanation Answer: A) 1/6

Explanation:

Converting each of the given fractions into decimal form, we get

2/3 = 0.66, 3/4 = 0.75, 4/5 = 0.8, 5/6 = 0.833 

Since 0.833>0.8>0.75>0.66 

So, 5/6 > 4/5 > 3/4 > 2/3 

Therefore,  Required Difference = 5/6 - 2/3 = 1/6

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Filed Under: Decimal Fractions

5 7281
Q:

Two trains start from same place at same time at right angles to each other. Their speeds are 36km/hr and 48km/hr respectively. After 30 seconds the distance between them will be ?

A) 900 mts B) 300 mts
C) 250 mts D) 500 mts
 
Answer & Explanation Answer: D) 500 mts

Explanation:

Using pythagarous theorem,
distance travelled by first train = 36x5/18x30 = 300m
distance travelled by second train = 48x5/18x30 = 400m
so distance between them =√( 90000 + 160000) = √250000 = 500mts.

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Filed Under: Time and Distance
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8 7280
Q:

The Value of  logtan10+logtan20++logtan890 is

A) -1 B) 0
C) 1/2 D) 1
 
Answer & Explanation Answer: B) 0

Explanation:

= log tan10+log tan890 + log tan20+ log tan880++log tan450  

 

= log [tan10 × tan890] + log [tan20 × tan880 ] ++log1  

 

 tan(90-θ)=cotθ and tan 450=1  

 

= log 1 + log 1 +.....+log 1 

 

= 0.

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Filed Under: Logarithms
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27 7266
Q:

Adam and Smith are working on a project. Adam takes 6 hrs to type 36 pages on a computer, while Smith takes 5 hrs to type 40 pages. How much time will they take, working together on two different computers to type a project of 120 pages?

A) 8 hrs 45 min B) 8 hrs 42 min
C) 8 hrs D) 8 hrs 34 min
 
Answer & Explanation Answer: D) 8 hrs 34 min

Explanation:

Number of pages typed by Adam in 1 hour = 36/6 = 6
Number of pages typed by Smith in 1 hour = 40/5 = 8
Number of pages typed by both in 1 hour = (6 + 8) = 14
Time taken by both to type 110 pages = (120 * 1/14) = 847 = 8 hrs 34 min.

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Filed Under: Time and Work
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10 7261
Q:

A sold an article to B at 40% profit and B sold it to C at 50% profit, then what will be profit percent with respect to A ?

A) 97 % B) 110 %
C) 135 % D) 115 %
 
Answer & Explanation Answer: B) 110 %

Explanation:

% Profit with respect to A = 40 + 50 + (40 x 50)/100 = 90 + 20 = 110 %.

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Filed Under: Profit and Loss
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2 7256
Q:

There are 5 multiple choice questions in an examination. How many sequences of answers are possible, if the first three questions have 4 choices each and the next two have 6 choices each?

A) 1112 B) 2304
C) 1224 D) 2426
 
Answer & Explanation Answer: B) 2304

Explanation:

Number of questions = 5
Possibilities of choices for each question 1 to 5 respectively = 4, 4, 4, 6, 6


Reuired total number of sequences

= 4 x 4 x 4 x 6 x 6

= 2304.

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Filed Under: Permutations and Combinations
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