Quantitative Aptitude - Arithmetic Ability Questions

Q:

If the area of a square with side a s equal to the area of a triangle with base a, then the altitude of the triangle is

A) a B) 2a
C) 5a D) 3a
 
Answer & Explanation Answer: B) 2a

Explanation:

Area of a square with side a = a² sq unts

Area of a triangle with base a = (1/2) * a * h sq.unts

a² =1/2 *a *h

=> h = 2a

altitude of the triangle is 2a

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1 6548
Q:

From a deck of 52 cards, a 7 card hand is dealt.How many distinct hands are there if the hand must contain 2 spades and 3 diamonds ?

A) 7250100 B) 7690030
C) 7250000 D) 3454290
 
Answer & Explanation Answer: A) 7250100

Explanation:

There are 13 spades,we must include 2: 13C2

 

There are 13 diamonds,we must include 3: 13C3

 

Since we can't have more than 2 spades and 3 diamonds,the remaining 2 cards must be pulled out from the 26 remaining clubs and hearts : 26C2

 

Therefore,13C2*13C3*26C2 = 7250100

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0 6546
Q:

A passenger train is moving at a speed of 120 km/hr. If the length of the train is 101 meters, how long will it take to cross a railway platform 154 meters long ?

A) 6.24 sec B) 6.58 sec
C) 7.325 sec D) 7.65 sec
 
Answer & Explanation Answer: D) 7.65 sec

Explanation:

Here total distance = 154 + 101 = 255 mts
Given speed = 120 kmph = 120x5/18 m/sec
Hence, Time = d/s = 255x18/120x5 = 7.65 sec

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Filed Under: Problems on Trains
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8 6541
Q:

4 45 of 259.99 = ? % of 1247.9

A) 96 B) 100
C) 78 D) 88
 
Answer & Explanation Answer: B) 100

Explanation:

Given 

4 45 of 259.99 = ? % of 1247.9

24/5 x 260 = ? x 1248/100

? = 1248 x 100/1248

? = 100.

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6 6541
Q:

The average age of a group of 10 students is 15 years. When 5 more students join the group, the average age increase by 1 year. The average age of the new student is?

Answer

Total age of 10 students = 150 years


Total age of 15 students = 240 years


Total age of 5 new students = 240 - 150 = 90 years


 Average age of 5 new students = 90/5 = 18 years.

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Subject: Problems on Ages

5 6536
Q:

Ajay and his wife Reshmi appear in an interview for two vaccancies in the same post. The Probability of Ajay's selection is 1/7 and that of his wife Reshmi's selection is 1/5. What is the probability that only one of them will be selected?

A) 5/7 B) 1/5
C) 2/7 D) 2/35
 
Answer & Explanation Answer: C) 2/7

Explanation:

P( only one of them will be selected) = p[(E and not F) or (F and not E)] 

 = PEFFE 

 

PEPF+PFPE

 

 =17×45+15×67=27

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Filed Under: Probability
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17 6531
Q:

A jogger running at 9 kmph alongside a railway track is 240 metres ahead of the engine of a 120 metre long train running at 45 kmph in the same direction. In how much time will the train pass the jogger  ?

A) 10 sec B) 48 sec
C) 36 sec D) 56 sec
 
Answer & Explanation Answer: C) 36 sec

Explanation:

Given speed of jogger = 9 kmph
Speed of train = 45 kmph
As they are in same direction,
Relative speed = 45 - 9 = 36 kmph = 36x5/18 = 10 m/s
Distance = 240 + 120 = 360 mts
Time = distance/speed = 360/10 = 36 sec.

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Filed Under: Problems on Trains
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2 6526
Q:

Prasanna invested certain amount in three different schemes X, Y and Z with the rate of interest 10% p.a, 12% p.a and 15% p.a respectively. If the total interest accrued in one year was Rs. 3200 and the amount invested in Scheme Z was 150% of the amount invested in Scheme X and 240% of the amount invested in Scheme Y, what was the amount invested in Scheme Y by Prasanna ?

A) Rs.6000 B) Rs.4500
C) Rs.7500 D) Rs.5000
 
Answer & Explanation Answer: D) Rs.5000

Explanation:

Let a, b and c be the amounts invested in schemes X, Y and Z respectively. Then,

As we know:

Simple interest (S.I.) = PTR/100

(a × 10 × 1/100) + (b × 12 × 1/100) + (c × 15 × 1/100) = 3200

= 10a + 12b + 15c = 320000 .........(1)

Now, c = 240% of b = 12b/5 .........(2)

And, c = 150% of a = 3a/2 => a = 2/3 c = (2 × 12)b/(3 × 5) = 8b/5 .......(3)

From (1), (2) and (3), we have

16b + 12b + 36b = 320000 => 64b = 320000 => b = 5000

∴ Sum invested in Scheme Y = Rs.5000.

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Filed Under: Percentage
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