Quantitative Aptitude - Arithmetic Ability Questions

Q:

A passenger train is moving at a speed of 120 km/hr. If the length of the train is 101 meters, how long will it take to cross a railway platform 154 meters long ?

A) 6.24 sec B) 6.58 sec
C) 7.325 sec D) 7.65 sec
 
Answer & Explanation Answer: D) 7.65 sec

Explanation:

Here total distance = 154 + 101 = 255 mts
Given speed = 120 kmph = 120x5/18 m/sec
Hence, Time = d/s = 255x18/120x5 = 7.65 sec

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Filed Under: Problems on Trains
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Q:

A shopkeeper’s earning increases by 25% in first year but decreases by 4% in the next and so on. After 5 years his total earnings would be Rs. 72,000. What is his present earning?

A) Rs. 40,000 B) Rs. 45,000
C) Rs. 42,000 D) Rs. 46,000
 
Answer & Explanation Answer: A) Rs. 40,000

Explanation:

Let his present earnings be Rs. p

ATQ,

(125/100) x (96/100) x (125/100) x (96/100) x (125/100) x p = 72000

p = Rs. 40,000.

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Filed Under: Percentage
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27 6183
Q:

A person lends Rs. 300 to A at 4% and Rs.540 to B at 6% for the same time. if the total amount that he gets at the end is Rs. 1032. What is the time?

Answer

Money lent to A+B = (300 + 540) = Rs. 840 


Amount received = Rs. 1032 


Interest received = Rs. 1032 - Rs.840 = Rs. 192


 


Interest on Rs. 300 lent to A for 1 year = 300×1×4100 = Rs. 12 


 


Interest on Rs.540 lent to B for 1 year = 540×6×1100 = Rs. 36 


 


 


Total yearly interest = Rs.(12+36) = Rs.48 


If interest is Rs. 48, time = 1 year 


If interest is Rs. 192, time =  192/48 = 4 years 

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Subject: Simple Interest Exam Prep: GATE , CAT , Bank Exams , AIEEE
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14 6180
Q:

The difference between 4632 and 20000 is what number

A) 15368 B) 12652
C) 14562 D) 14965
 
Answer & Explanation Answer: A) 15368

Explanation:

The difference between 4632 and 20000 is given by subtracting smaler number from the bigger number.

Here the bigger number is 20000

Smaller number is 4632

Now, subtracting 4632 from 20000

20000 - 4632 = 15368 and the resut is an even number.

 

Hence, The difference between 4632 and 20000 is 15368 and is an even number.

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Filed Under: Problems on Numbers
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Q:

The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?

A) 16cm B) 18cm
C) 24cm D) .Data inadequate
 
Answer & Explanation Answer: B) 18cm

Explanation:

2(l+b)/b = 5/1 

=> 2l + 2b = 5b  

=> 3b = 2l  

=> b =(2/3) x l

 Then, Area = 216 sq.cm 

 

l x b = 216  

=> l x [(2/3)x l] =216  

=> l x l = 324 

=> l = 18 cm.

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Q:

The ratio of the speeds of a car, a jeeps and a tractor is 3 : 5 : 2. The speed of the jeep is 250 per cent of the speed of the tractor and tractor covers 360 km in 12 hours. What is the average speed of car and jeep together?

A) 50 kmph B) 60 kmph
C) 70 kmph D) 80 kmph
 
Answer & Explanation Answer: B) 60 kmph

Explanation:

Speed of tractor = 360/12 = 30 kmph

Speed of jeep = 250 x 30/100 = 75 kmph

But, given ratio of speed of car, jeep and tractor is 3 : 5 : 2

Speed of car = 3 x 75/5 = 45 kmph

 

Required, average speed of car and jeep = 75 + 45/2 = 60 kmph.

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Filed Under: Time and Distance
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Q:

Salaries of Karthik, Arun and Akhil were in the ratio 4 : 5 : 6 respectively. If their salaries were increased by 50 per cent, 60 per cent and 50 per cent respectively, what will be the new ratio of the salaries of Akhil, Arun and Karthik ?

A) 6 : 8 : 9 B) 8 : 6 : 9
C) 9 : 8 : 6 D) 6 : 5 : 4
 
Answer & Explanation Answer: C) 9 : 8 : 6

Explanation:

Given the salaries are in the ratio of 4 : 5 : 6

 

Now the salaries are increased by 50%, 60% and 50% respectively

 

The New ratio of salaries will be

 

4 x (150/100) : 5 x (160/100) : 6 x (150/100)

 

= 6 : 8 : 9

 

The new ratio of salaries of Akhil, Arun and Karthik is 9 : 8 : 6

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Filed Under: Ratios and Proportions
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Q:

In How many ways can the letters of the word 'CAPITAL' be arranged in such a way that all the vowels always come together?

A) 360 B) 720
C) 120 D) 840
 
Answer & Explanation Answer: A) 360

Explanation:

CAPITAL = 7

 

Vowels = 3 (A, I, A)

 

Consonants = (C, P, T, L)

 

5 letters which can be arranged in  5P5=5!

 

Vowels A,I = 3!2!

 

No.of arrangements = 5! x 3!2!=360

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Filed Under: Permutations and Combinations
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