Quantitative Aptitude - Arithmetic Ability Questions

Q:

Find the probability of selecting exactly 2 children when four persons are choosen at random from a group of 3 men, 2 woman and 4 children.

A) 9/29 B) 10/21
C) 12/21 D) 14/19
 
Answer & Explanation Answer: B) 10/21

Explanation:

4 persons can be selected from 9 in 9C4 ways =126

 

Fvaourable events =4C2*5C2 =60

 

So,required probability = 60/126 = 10/21

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Filed Under: Probability

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Q:

There are two numbers such that the sum of twice the first number and thrice the second number is 300 and the sum of thrice the first number and twice the second number is 265. Which is the largest number ?

A) 24 B) 39
C) 85 D) 74
 
Answer & Explanation Answer: D) 74

Explanation:
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Q:

Two cylindrical buckets have their diameters in the ratio 3:1 and their heights are as 1: 3. Find the ratio of their volumes.

A) 2:1 B) 3:1
C) 4:1 D) 5:1
 
Answer & Explanation Answer: B) 3:1

Explanation:

v1v2=r12×h1r22×h2 

 

d1 = 2r1 and d2 = 2r2 are diameters

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Filed Under: Volume and Surface Area
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Q:

Find the effective rate of interest for an investment that earns 5 1/2% per year, compounded continuously

A) 5.65% B) 5.75%
C) 5.85% D) 5.95%
 
Answer & Explanation Answer: A) 5.65%

Explanation:

We are not given a value of P in this problem, so either pick a value

for P and stick with that throughout the problem, or just let P = P.

We have that t = 1, and r = .055. To find the effective rate of interest,

first find out how much money we have after one year:

A = Pert

A = Pe(.055)(1)

A = 1.056541P.

Therefore, after 1 year, whatever the principal was, we now have 1.056541P.

Next, find out how much interest was earned, I, by subtracting the initial amount of money from the final amount:

I = A − P

  = 1.056541P − P

  = .056541P.

Finally, to find the effective rate of interest, use the simple interest formula, I = Prt. So,

I = Pr(1) = .056541P

.056541 = r.

Therefore, the effective rate of interest is 5.65%

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Filed Under: Compound Interest
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Q:

Mary is 12 years younger to Pinky. After 3 years, the ratio of their ages will be 5:8. If the present age of Sam is the sum of ages of Mary and Pinky, then what was the age of Sam 15 years back ?

A) 31 years B) 37 years
C) 46 years D) 29 years
 
Answer & Explanation Answer: A) 31 years

Explanation:

Let the present age of Pinky be x years

 

Then the age of Mary is x - 12 years

 

After 3 years,

 

Ratio of  MaryPinky = x - 9x + 3 = 58

 

8x - 72 = 5x +15

 

=> 3x = 87

 

=> x = 29

 

=> Age of Pinky = 29 years

 

=> Age of Mary = 29 - 12 = 17 years

 

Present age of Sam = 29 + 17 = 46

 

Before 15 years Sam age = 46 - 15 = 31 years.

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Filed Under: Problems on Ages
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Q:

A can complete a piece of work in 12 days and B is 60% more efficient than A. In how many days B will complete the same work  ?

A) 8.7 hrs B) 5.2 hrs
C) 5 hrs D) 7.5 hrs
 
Answer & Explanation Answer: D) 7.5 hrs

Explanation:

Ratio of times taken by A and B = 160 : 100
A can do the work in 12 days
Let B can do the work in "D" days
=> 160:100 = 12 : D
=> D = 12 x 100/160 = 7.5 hrs

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Filed Under: Time and Work
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Q:

If A1, A2, A3, A4, ..... A10 are speakers for a meeting and A1 always speaks after, A2 then the number of ways they can speak in the meeting is 

A) 9! B) 9!/2
C) 10! D) 10!/2
 
Answer & Explanation Answer: D) 10!/2

Explanation:

As A1 speaks always after A2, they can speak only in  1st  to 9th places and 

 

A2 can speak in 2nd to 10 the places only when A1 speaks in 1st place 

 

A2 can speak in 9 places the remaining 

 

 A3, A4, A5,...A10  has no restriction. So, they can speak in 9.8! ways. i.e

 

when A2 speaks in the first place, the number of ways they can speak is 9.8!.

 

When A2 speaks in second place, the number of ways they can speak is  8.8!.

 

When A2 speaks in third place, the number of ways they can speak is  7.8!. When A2 speaks in the ninth place, the number of ways they can speak is 1.8!

 

 

 

Therefore,Total Number of ways they can  speak = (9+8+7+6+5+4+3+2+1) 8! = 92(9+1)8! = 10!/2

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Filed Under: Permutations and Combinations
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Q:

The calendar for the year 2007 will be the same for the year ?

A) 2014 B) 2019
C) 2021 D) 2018
 
Answer & Explanation Answer: D) 2018

Explanation:

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017
Odd day : 1 2 1 1 1 2 1 1 1 2 1

Sum = 14 odd days => 0 odd days.
Calendar for the year 2018 will be the same as for the year 2007.

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Filed Under: Calendar
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