Quantitative Aptitude - Arithmetic Ability Questions

Q:

The number of solutions of the equation logx2x2+40log4xx-14log16xx3=0 is:

A) 0 B) 1
C) 2 D) 3
 
Answer & Explanation Answer: D) 3

Explanation:
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Filed Under: Logarithms
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14 5048
Q:

A watch which gains uniformly is 2 minutes low at noon on Tuesday and is 4 min 48 sec fast at 2 p.m. on the following Tuesday. When was it correct ?

A) 12 p.m. on Wednesday B) 2 p.m. on Thursday
C) 3 p.m. on Thursday D) 2 p.m. on Wednesday
 
Answer & Explanation Answer: B) 2 p.m. on Thursday

Explanation:

Time from 12 p.m. on Tuesday to 2 p.m. on the following Tuesday = 7 days 2 hours.
= 170 hours.
The watch gains = (2 + 4 x 4/5) min
= 34/5 min. in 170 hrs.
Now, 34/5 min are gained in 170 hrs.
Then, 2 min are gained in (170 x 5/34 x 2) hrs.
Watch is correct after 2 days 2 hrs after 12 p.m. on Tuesday, i.e., it will be correct at 2 p.m. on Thursday.

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Filed Under: Clocks
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9 5041
Q:

Equal distance is covered by a boat in upstream and in downstream in total 5 hours. Sum of speed of a boat in upstream and downstream is 40 km/hr. Speed of boat in still water is 600%
more than the speed of stream. Find theapproximate distance covered by boat in downstream (in km).

A) 45 B) 50
C) 55 D) 60
 
Answer & Explanation Answer: B) 50

Explanation:

let speed of boat= X, speed of stream= Y
Upstream speed= X-Y
Downstream speed= X+Y
Sum of upstream & downstream= (X-Y) +(X+Y)= 2X
So, 2X= 40
X= 20 km/hr
Speed of boat : speed of stream= 600+100 :100= 7:1
So speed of Stream= 20/7 km/hr
ATQ, D/( X-Y) + D/( X+Y) = 5
D/(120/7) + D/(160/7)= 5
D= 480×5/49= 48.97 km= 50 Km(approx)

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Filed Under: Boats and Streams
Exam Prep: Bank Exams , GATE

10 5040
Q:

Cube root of 729 then square it

A) 9 B) 36
C) 81 D) 144
 
Answer & Explanation Answer: C) 81

Explanation:

729 = 9 x 9 x 9

=> Cube root of 729 = 9

 

Now, required square of 9 = 9 x 9 = 81.

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Filed Under: Square Roots and Cube Roots
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4 5034
Q:

A merchant receives an invoice for a motor boat for $20 000 with terms 4/30, n/100. What is the highest simple interest rate at which he can afford to borrow money in order to take advantage of the discount?

A) 247.67 B) 237.67
C) 227.67 D) 215.67
 
Answer & Explanation Answer: A) 247.67

Explanation:

Suppose the merchant will take advantage of the cash discount of 4% of $20 000 = $800 by paying the bill within 30 days from the date of invoice. He needs to borrow $20 000 = $800 = $19 200. He would borrow this money on day 30 and repay it on day 100 (the day the original invoice is due) resulting in a 70-day loan. The interest he should be willing to pay on borrowed money should not exceed the cash discount $800.

 

r=I/pt=21.73%

 

The highest simple interest rate at which the merchant can afford to borrow money is 21.73%. This is a break-even rate. If he can borrow money, say at a rate of 15%, he should do so. He would borrow $19 200 for 70 days at 15%. Maturity value of the loan is $19 200(1+0.15(70/365))=$19 752.33

 

savings would be $20 000 − $19 752.33 = $247.67

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

1 5025
Q:

Find the odd man out 1 4 9 16 22 36?

A) 9 B) 16
C) 22 D) 36
 
Answer & Explanation Answer: C) 22

Explanation:

In the given series 1 4 9 16 22 36

1 = 1 x 1 

4 = 2 x 2

9 = 3 x 3

16 = 4 x 4

25 = 5 x 5 (Not 22)

36 = 6 x 6

 

Hence, the odd man in the series is 22.

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Filed Under: Odd Man Out
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13 5024
Q:

Three unbiased coins are tossed. What is the probability of getting at most two heads ?

A) 4/3 B) 2/3
C) 3/2 D) 3/4
 
Answer & Explanation Answer: D) 3/4

Explanation:

Let S be the sample space.
Here n(S)= 23 = 8
Let E be the event of getting atmost two heads. Then,
n(E) = {(H,T,T), (T,H,T), (T,T,H), (H,H,T), (T,H,H), (H,T,H)}
Required probability = n(E)/n(S) = 6/8 = 3/4.

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Filed Under: Probability
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6 5021
Q:

The B.G. on a certain sum 4 years hence at 5% is Rs. 200. What is the present worth?

A) Rs. 4500 B) Rs. 6000
C) Rs. 5000 D) Rs. 4000
 
Answer & Explanation Answer: C) Rs. 5000

Explanation:

T = 4 years

R = 5%

Banker's Gain, BG = Rs.200

 

TD= BG×100TR=200×1004×5=Rs.1000

 

 TD=PW×BG

 

1000=PW×200

 

=>PW = Rs.5000

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Filed Under: Banker's Discount

3 5021