Quantitative Aptitude - Arithmetic Ability Questions

T = 4 years

R = 5%

Banker's Gain, BG = Rs.200

TD= BG×100TR=200×1004×5=Rs.1000

 TD=PW×BG

⇒1000=PW×200

=>PW = Rs.5000

To find the LCM of 24, 36 and 40

24 = 2 x 2 x 2 x 3

36 = 2 x 2 x 3 x 3

40 = 2 x 2 x 2 x 5 

Now, LCM of 24, 36 and 40 = 2 x 2 x 2 x 3 x 3 x 5

= 8 x 9 x 5

= 72 x 5

= 360

We know that I = PTR/100

11 = (2x30xR)/100

R = 18.333 %

let speed of boat= X, speed of stream= Y
Upstream speed= X-Y
Downstream speed= X+Y
Sum of upstream & downstream= (X-Y) +(X+Y)= 2X
So, 2X= 40
X= 20 km/hr
Speed of boat : speed of stream= 600+100 :100= 7:1
So speed of Stream= 20/7 km/hr
ATQ, D/( X-Y) + D/( X+Y) = 5
D/(120/7) + D/(160/7)= 5
D= 480×5/49= 48.97 km= 50 Km(approx)

We know that,

$$\begin{gathered} S.I. = PTR100 \\ ⇒ P = S.I x 100T x R \\ And also, \\ C.I = P1 + R100n- 1 \end{gathered}$$

From given data, P = Rs. 8625

Now, C.I  = $$\begin{gathered} 86251+41002-1 \\ = 862526252-1 \\ = 8625676625-1 \\ = 8625 x 51625 \\ C.I = Rs. 703.80 \end{gathered}$$

I = (p x r x t)/100

I = $25.20

A = P+I

A = 235.20

Given, Manideep purchases 30kg of barley at the rate of 11.50/kg nad 20kg at the rate of 14.25/kg.

Total cost of the mixture of barley = (30 x 11.50) + (20 x 14.25)

=> Total cost of the mixture = Rs. 630

Total kgs of the mixture = 30 + 20 = 50kg

Cost of mixture/kg = 630/50 = 12.6/kg

To make 30% of profit

=> Selling price for manideep = 12.6 + 30% x 12.6

=> Selling price for manideep = 12.6 + 3.78 = 16.38/kg.

Let the Time be 'N' and Rate be 'R' 

J = (K x NR)/100 K = (L x NR)/100 

J/K = NR/100 K/L = NR/100 

J/K = K/L 

K x K = JL