Pick the odd man out of the folowing number sequence?
123 112 133 112 143
Here the given series is 123 112 133 112 143
It follows a pattern that,
123
123 - 11 = 112
112 + 21 = 133
133 - 31 = 102 (not 122)
102 + 41 = 143
Hence, the odd man in the given number sequence is 122 instead of 102.
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The volume of a hemisphere is 89.83 cm³. Find its diameter (in cm).
On what dates of April, 2001 did Wednesday fall?
We shall find the day on 1st April, 2001.
1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April
(31 + 28 + 31 + 1) = 91 days 0 odd days.
Total number of odd days = (0 + 0 + 0) = 0
On 1st April, 2001 it was Sunday.
In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?
Let the required number of days be x.
Less persons, More days (Indirect Proportion)
More working hours per day, Less days (Indirect Proportion)
Persons30:39Working hours/day6:5⋮⋮ 12:x
=> 30 * 6 * x = 39 * 5 * 12
=> x= 13
The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively, is:
Required number = H.C.F. of (1657 - 6) and (2037 - 5)
= H.C.F. of 1651 and 2032 = 127.
At what time between 7 and 8 o'clock will the hands of a clock be in the same straight line but,not together?
When the hands of the clock are in the same straight line but not together, they are 30 minute spaces apart.At 7 o'clock, they are 25 min. spaces apart.Minute hand will have to gain only 5 min. spaces.55 min. spaces are gained in 60 min.
5 min spaces are gained in 6055*5 min = 5511min
so, Required time = 5511 min past 7
Find the missing number in the given number series?
2676, 445, ?, 21,6, 2, 1
The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that,
From right side,
1
1 x 1 + 1 = 2
2 x 2 + 2 = 6
6 x 3 + 3 = 21
21 x 4 + 4 = 88
88 x 5 + 5 = 445
445 x 6 + 6 = 2676
Hence the missing number in the given number series is 88.
Calculate the area (in sq.cm) of a circle whose diameter is 14 cm.