Quantitative Aptitude - Arithmetic Ability Questions

Q:

Find the compound interest on Rs. 10,000 in 2 years at 4% per annum, the interest being compounded half-yearly.

A) 524.32 B) 624.32
C) 724.32 D) 824.32
 
Answer & Explanation Answer: D) 824.32

Explanation:

Principal = Rs. 10000; Rate = 2% per half-year; Time = 2 years = 4 half-years.
Amount == Rs. 10824.32.

 

 Rs.10000*1+21004=Rs.10000*5150*5150*5150*5150

 

 C.I. = Rs. (10824.32 - 10000) = Rs. 824.32.

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Q:

What is the value of (2 + tan600) ?

 

A)  3   B)  2/√3  
C)  4/√3   D)  2+√3
 
Answer & Explanation Answer: D)  2+√3

Explanation:
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Q:

What percent of 7.2 kg is 18 gms ?

A) .25% B) .5%
C) .75% D) 1%
 
Answer & Explanation Answer: A) .25%

Explanation:

Required percentage = (18/7200 * 100)% =  1/4% = 0.25%

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201 53992
Q:

Find the odd man out in the following number series?

5, 4, 9, 32, 273

A) 4 B) 9
C) 32 D) 273
 
Answer & Explanation Answer: C) 32

Explanation:

The given number series follows 5, 4, 9, 32, 308 pattern that

 

5

5 x 1 - 1 = 4

4 x 3 - 3 = 9

9 x 5 - 5 = 40 (not equals to 32)

40 x 7 - 7 = 273

 

Hence, the odd man in the given number series is 32.

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Q:

A man sitting in a train which is traveling at 50 kmph observes that a goods train, traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m long, find its speed.?

A) 60 B) 62
C) 64 D) 65
 
Answer & Explanation Answer: B) 62

Explanation:

Relative speed =280/9  m / sec = (280/9*18/5)  kmph = 112 kmph.

 

Speed of goods train = (112 - 50) kmph = 62 kmph.

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Q:

Aman started a business investing Rs. 70,000. Rakhi  joined him after six months with an amount of Rs. 1,05,000 and Sagar joined them with Rs. 1.4 lakhs after another six months. The amount of profit earned should be distributed in what ratio among Aman, Rakhi and Sagar respectively, 3 years after Aman started the business ?

A) 11 : 13 : 15 B) 11 : 13 : 17
C) 12 : 17 : 18 D) 12 : 15 :16
 
Answer & Explanation Answer: D) 12 : 15 :16

Explanation:

Aman : Rakhi : Sagar = (70000 x 36) : (105000 x 30) : (140000 x 24) = 12 : 15 : 16.

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30 53855
Q:

26 january 1950 which day of the week?

A) Monday B) Wednesday
C) Thursday D) Tuesday
 
Answer & Explanation Answer: C) Thursday

Explanation:

We know that,

Odd days --> days more than complete weeks

Number of odd days in 400/800/1200/1600/2000 years are 0.

Hence, the number of odd days in first 1600 years are 0.

Number of odd days in 300 years = 1

Number of odd days in 49 years = (12 x 2 + 37 x 1) = 61 days = 5 odd days

Total number of odd days in 1949 years = 1 + 5 = 6 odd days

Now look at the year 1950

Jan 26 = 26 days = 3 weeks + 5 days = 5 odd days

Total number of odd days = 6 + 5 = 11 => 4 odd days

 

Odd days :-

0 = sunday ;

1 = monday ;

2 = tuesday ;

3 = wednesday ;

4 = thursday ;

5 = friday ;

6 = saturday

 

Therefore, Jan 26th 1950 was Thursday.

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208 53799
Q:

Solve the following :

60 ÷ 5 × 16 - 8 ÷ 2 ÷ 3 = ?

A) 3 B) 48
C) 1 D) 1/3
 
Answer & Explanation Answer: B) 48

Explanation:
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